Once you said it took you a while to get this, i knew i was at the right place. Cos people like you know how to explain it in the simplest of terms since you have been in our position before. Thank you. DOn't stop what your're doing
@affection2312 жыл бұрын
sir you ended my nightmare about these topics. Best of luck for you and your family in the New Year 🎁🎀🎄🎄
@noctao4163 Жыл бұрын
I liked how well this was explained I just started learning about this and it helps a lot.
@PhysicsNinja Жыл бұрын
Thank you!
@amandaliu74093 ай бұрын
omg these saved my life please keep making videos like this thank you so much
@PhysicsNinja3 ай бұрын
Will do!
@SuperSyntax-s7w2 ай бұрын
Absolutely fantastic teaching
@jojoo_aah8072 Жыл бұрын
Omg, the best explanation i had see so far!
@khaulamohammed192 жыл бұрын
Thank you so much, this was such a saver. Keep on coming more content!
@johngordon8513 Жыл бұрын
i was your 420th like, youre welcome.... also thank yoooou, these vids are the bees earlobes
@Iwonder4935 күн бұрын
5:01, Why can we assume angle theta will be the same for any dq on the ring? If dq was to be exactly on the x axis, wouldn't theta be 0?
@Pomegrante4603 ай бұрын
Would the total charge Q be the area of the disk, if so why would it be the area & not the volume?
@godisgood24822 жыл бұрын
Are there any experiments video showing electric field due to ring? And is the ring always going to get uniformly charged if we try to charge it
@vaibhavgowda67252 жыл бұрын
If the ring is perfectly conducting/metallic then yes it will have uniform charge distribution regardless of how we charged it. Unfortunately I couldn’t find any videos showing field due to a ring irl.
@Gamernotgamer1996 Жыл бұрын
How did you modify the new limits?, any video or explanation on that.
@DoofEvil3 ай бұрын
i have an exam tomorrow, please help!! how come in the first problem you integrated with respect to Q? when doing the same problem but with a vertical rod instead of a ring, i integrated with respect to y using lambda = Q/Y dQ = lambda * dY and plugging that in for q, which is how i was taught. because, they say, Q is not a geometric quantity. why did you integrate with dQ? how do i know when to integrate with respect to Q or Y? does the ring not still have a charge density lambda = Q/(2piR)?
@lucassarappa3327 Жыл бұрын
Hello friend, the video is very good, but I have a question with a similar exercise: I need to find the electric field at a known midpoint of 2 charged circular loops like the ones in the video (each with a different charge, both positive). I have to apply the formula that you show in the video for each of the circular loops, and then my question is: Should I add or subtract each of the results to obtain the electric field at that point? (taking into account that both charges are positive). Thank you so much
@hananiahtangpuz6849 Жыл бұрын
you the goat meehn! new fan
@PhysicsNinja Жыл бұрын
Thank you!
@ashqawala2 жыл бұрын
Which type of gussian surface we will take in order to find E field due to a hollow capsule like object which have both hemisphere and cylindrical symmetry?
@Patatas-p7u8 ай бұрын
Doesn't x change depending on the distance of the point we're choosing to calculate the electric filed for?
@HiruniJayaweera-in1hg Жыл бұрын
Thank you sir
@LilLefty27 Жыл бұрын
why is your point source formula kQ/r^2 instead of kQ/r? I have conflicting info in my notes from class
@PhysicsNinja Жыл бұрын
Kq/r2 is electric field and kq/r is electrical potential, not the same
@miguelbuitrago6050 Жыл бұрын
Is it possible find that Electric Field using the electric field of a line?
@adwardwilson1857 Жыл бұрын
the ring is finite, but for calculate the electric field of a finite line we have to use the gauss law
@ok-xt2ki Жыл бұрын
thank u!!
@tuongdihoc Жыл бұрын
Amazing!
@arshmehta180510 ай бұрын
what a legend
@chathunikulathunga30393 ай бұрын
Thanks man
@kabokbl2412 Жыл бұрын
Had a bad day due to this topic evicirating me in a quiz
@ice_the_kicker Жыл бұрын
Wow
@erickcastellanos68142 жыл бұрын
huh.
@sigma7208 Жыл бұрын
Thank you so much, this was such a saver. Keep on coming more content!