Electric Field of a Dipole: Axis and Equator Explained

[@EngineeringFunda]

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[@ashuchaudhary51]

Thank you very much sir , these videos are too much useful for us...

[@EngineeringFunda]

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[@EngineeringFunda]

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[@EngineeringFunda]

It is y 》a, it is not a 》y.

[@nithinbusiraju1133]

❤️

[@lifemotivation342]

13:10 it should be Y>>A

[@EngineeringFunda]

I have already pinned comment based on that.

[@lifemotivation342]

@@EngineeringFunda yes i have seen it sir

[@DRUCVSKAMAU]

why did we use -q when we had already accounted for it in the direction at 04:29

[@EngineeringFunda]

It is -q only, thats why dieection of E+q and E-q is opposite.

[@safeegull22]

Professor all ok ,but my suggestion is to of you write z not like 2, so I think it will be most ok, respected professor it is suggestion, not complain, and also request

[@EngineeringFunda]

Thanks

[@kishorekumar042]

For case 1: for E-q the we take -q, but in case 2: E+qsintheta + E-qsintheta is taken as 2Esintheta, shouldn't the value of -q make the two values opposite to each other

[@rationalthinker9612]

Wait , am I missing something? At 5:00 , you combine the fractions by getting a common denominator. Shouldn't the common denominator be (z-a)^2 * (z+a) ^2 ?? You have (z-a)^2 only?? Also you make an assumption that z >> a. Okay let's assume that is true, once the fractions are combined over a common denominator, you have (( z-a)^2 - (z+a)^2 )/ ((z-a)^2)) , even though I think that denominator is wrong, let's just keep going. You simplify the numerator and get 4za. Then before you simplify the denominator, you assume z >> a and basically ignore the value of -a . Okay that's fine but why wasn't that logic applied to the numerator before you simplified it to 4za? Should you not apply that logic to the numerator as well? That would make numerator equal to 2z^2. What am I missing? I am fairly certain my logic is sound.

[@EngineeringFunda]

Dear, (z + a)(z - a) = (z^2 - a^2)

[@rationalthinker9612]

@@EngineeringFunda wasn't there a square outside the parentheses??

[@EngineeringFunda]

@@rationalthinker9612 ( z + a )^2 × (z - a)^2 = (z^2 - a^2)^2 only

[@rationalthinker9612]

@@EngineeringFunda ok you're right about that part. I didn't take the time to expand those things out, it just looked weird. What about the other issue I presented in my comment.

[@EngineeringFunda]

@@rationalthinker9612 It's perfectly correct dear, only one error was there that was y >> a. I have also mentioned it in comment section.

[@abdulmazeed9653]

please make a video on electric field due to dipole at any arbitrary point.

[@pratapchatterjee1762]

Kp/r³(√(1+3cos²(theta))

[@manishbetala8523]

It's y>>a not a>>y

[@hiteshdholakiya841]

It's just writing error. Else everything is well explained.

[@EngineeringFunda]

Yeah I have written that by mistake, so please do correct it.