Electrical FE /EIT Exam Prep - Circuit Analysis 6: Superposition Principle

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[@scodyt3996]

Wonderful video(s)! Thanks for sharing :)

[@EngineeringEducation]

shawn thomas Thanks for the support! Glad you are enjoying the videos! :)

[@montalvoken]

It gives 7.5 volts for me

[@airbender9593]

All the work is in the video. How can you get a different value? Also, I took my last EE class 15 years ago. This is still review for me and watching the video 2x w/o any note so far.

[@rafaelr5243]

Same here. He did it by superposition but messed up the second part. The voltage at Vo that's contributed by the current source would be 2 * 1.875 which would yield 3.75. Add that to the 3.75 from the first part and you get 7.5. I did it by nodal analysis and got 7.5 which is correct.

[@johanmanuelrosariogarcia2033]

@@rafaelr5243 Req is actually 5.875 ohms. 5//3 = 1.875 ohms, then you add 4 ohms(series) wich is 5.875 ohms. After that just multiply that by 2 and that equals 11.75V. Add that to the 3.75 fro part 1 and you get 15.15V.

[@garyhoxha]

@@johanmanuelrosariogarcia2033 exactly I used nodal analysis as well and found v out is 7.5. 2A x 4omhs is 8volts plus 7.5 yields 15.5 as you said. Super position is just a technique you don't have to use it.

[@virajp8726]

@@garyhoxha How did you guys get Vo to be 7.5