Electricity in 20 Minutes🔥| Class 10th | Rapid Revision | Prashant Kirad

[@ankushsingh7163]

Electric Current and Circuit 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh) likeee😃

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[@sarphitegamers243]

20:13 answer is (b) It become half V = IR (Ohm's law) I = V/R But R is doubled I = V/2R or I/2 means current becomes half 20:19 answer = first make watt in kilo watt => 100000 W x 1/1000 = y KW => 100 KW now commercial unit is KWh, so => 100 KW x 30 h (because it was moving 1 h per day, so 30 h in 30 days) => 3000 KWh and we know that 1KWh = 10 Rs, so 3000 x 10 = 30000 Answer = 30000 Rs Thank You

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[@mdrafikbjp8369]

1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (1.6 x 10⁻¹⁹ C) 1kWh= 3.6 × 10⁶J 1Ampere = 1000mA 1 Kilowaat = 1000W 1 Horse Power = 746W i hope this list will help you! ❤ ek free ka like dete jana also please subscribe and visit my channel for this type of videos

[@draxx915]

welcome everyone and thnks for like[edit] All Formulas of Electricity: 1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (1.6 x 10⁻¹⁹ C) 1kWh= 3.6 × 10⁶J 1Ampere = 1000mA 1 Kilowaat = 1000W 1 Horse Power = 746W i hope this list will help you! ❤ ek free ka like dete jana

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[@ROHITSHORTS555]

👍 electricity formulas and their SI units: Electric Charge 1. *Charge (Q)* = Current (I) × Time (t) - Q = I × t - Unit: Coulomb (C) Electric Current 1. *Current (I)* = Charge (Q) / Time (t) - I = Q / t - Unit: Ampere (A) Voltage 1. *Voltage (V)* = Work (W) / Charge (Q) - V = W / Q - Unit: Volt (V) Resistance 1. *Resistance (R)* = Voltage (V) / Current (I) - R = V / I - Unit: Ohm (Ω) Power 1. *Power (P)* = Voltage (V) × Current (I) - P = V × I - Unit: Watt (W) Energy 1. *Energy (E)* = Power (P) × Time (t) - E = P × t - Unit: Joule (J) Other Formulas 1. *Ohm's Law*: V = I × R 2. *Series Circuit*: R_total = R1 + R2 + ... + Rn 3. *Parallel Circuit*: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn These formulas and units are fundamental to understanding electricity and electronics. Likeeeeeeeee 🤗

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[@activegaming586]

20:12 Q1 [b] it becomes half Q2 Power=100000W t=1hr Power=100000/1000=100W Total energy consumption= 100 * 1 = 100kwh Cost of energy consumed in one day= 100 * 10 = ₹1000 Cost of energy consumed in 30 days = 1000 * 30 = ₹30000

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[@AradhyaGupta-v2p]

wont it be double according to ohms law

[@activegaming586]

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[@Sh4d1ng]

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[@roheetdas]

Questions:- Q)1) Solution--- By Ohm's Law, V=IR=> I=V/R So I is inversely proportional to R When R is doubled, I is halved Answer:- b) It becomes half Q)2) Solution--- P=100000W=100KW [1KW=1000W] t=1 hr per day For 30 days, t=30 hrs We know, P=W/t=>W=Pt=>W=100KW×30h=>W=3000KWh Cost- 1KWh --> Rs 10 3000KWh --> Rs 10×3000=Rs 30000 Answer:- Rs 30000 Plss like the comment if you are satisfied with the answer.....😅😅😅😅😊😊 Thank you everyone for crossing 800 likes ❤️ 1.4K likes done 🗿 Thank you so much for 1.6K likes ❤️❤️❤️🔥🔥💯 2K LIKES DONE ✅✅✅✅✅✅

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[@daksh-m8d]

hiie every one 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh) i think this will make easy 😇😇

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00:04 Overview of electricity concepts 00:39 Charge 02:21 Quantization of charge explained 03:02 Understanding current and ammeter 04:32 Understanding work done and potential difference 05:11 Understanding formulas for charge, current, voltage, and work done by charge. 06:30 Understanding basic circuits and components 07:12 Understanding resistance and its unit 08:51 Understanding the significance of resistance in Ohm's Law 09:40 Understanding the relationship between resistance and temperature in electricity 11:03 Understanding voltage and current in parallel circuits 11:46 Calculating total resistance using Ohm's Law 13:25 Heating effect of electric current 14:07 Understanding the concept of resistance and heat generation in electrical circuits 15:29 Understanding the properties of Nichrome material 16:17 Understanding Power in Electricity 17:45 Understanding the concept of kilowatt-hour 18:33 Understanding the importance of conversion in exams 20:03 Understanding the relationship between voltage and current. 20:39 Share and discuss about the lecture topic with friends.

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[@PariAthwani]

20:13 b) it becomes half Q. 30000rs P×t= energy P should be in kwh 100×1= 100 Cost for 30 days = 100×30×10= 30000

[@ContraX_77]

It becomes half inversely proportional

[@rs476sharma]

Answer is b . It becomes half to 0.5

[@ArjunBot-rl3vm]

20:33 Given‚ p= 100000w t= 1×30= 30 hrs P=100000/1000 =100kw P=w×t So‚therefore 100×30 =3000kwh But‚ 1kwh= 10rs So‚ 3000×10 =30‚000rs

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Ans2. 30000

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[@mrmister-pb3dl]

Electric Current and Circuit 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh)

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[@vasanthedajol8627]

All topics 0:30 Electric charge 1:09 Electric circuit 5:28 Most important ohm's law 6:47 Resistance 7:30 Difference between resistance and resistivity 10:10 Derivations of series and parallel circuit 11:07 Heating effect of electric current 13:28 Electric power 15:50 Types of questions asked 18:40

[@RDJFFEDIT]

Question 1: ans b) its becomes half And Question 2: Power = 100,000 Watts (or 100 kW) Time per day = 1 hour Total energy consumption per day = Power x Time = 100 kW x 1 hr = 100 kWh Total energy consumption for 30 days = 100 kWh/day x 30 days = 3000 kWh Cost per kWh = Rs. 10 Total cost for 30 days = Total energy consumption x Cost per kWh = 3000 kWh x Rs. 10/kWh = Rs. 30,000 So, the total cost for 30 days is Rs. 30,000. Here's a breakdown: Power | 100 kW Time per day | 1 hr Energy/day | 100 kWh Energy/30 days | 3000 kWh Cost/kWh | Rs. 10 Total Cost/30 days | Rs. 30,000

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[@Studywithswati_10]

He is the best bhaiya 😊😊❤❤❤❤❤❤and best teacher 😊❤ who agree😊😊❤❤

[@mrmister-pb3dl]

Electric Current and Circuit 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh)

[@mahirajput07863]

Hii

[@luckystudio3400]

Sab kuch samaj me aagya bhaiya in 20. Min.....thank you bhaiya hmare liye itni achi chiz bnane ke liye ....❤❤❤thank you...😊😊

[@SunitaDevi-of9hh]

Jisne like ni kiya woh fail (don't take risk)⚠️⚠️

[@AryanYadav-pj3xg]

Tune comment delete nhi Kiya to tum fail

[@SunitaDevi-of9hh]

@AryanYadav-pj3xg agar tune ni kya to tu fail

[@SouravRajput-t7p]

😂

[@niteshgupta8957]

Tune comment nhi delete Kiya, to andi bandi sandi, aur agar tune ye merepe use Kiya to tu hamesha 0.00% se fail 😈😈

[@socialmediahub-s8d]

Raa bkl Tera ko ya sab kar ka kya milta h raa😡😡

[@Kanak-gm6qb]

1:47 true ufff😩🫶🏻

[@SrvRajpuT01]

Hi

[@arunendrashukla7075]

Realme C55 ?

[@RiderAyush704]

Hlo

[@deepkumar4471]

Hlo

[@satyamkesarwani4915]

Hi kanak

[@troll_faceedits-s3e]

13:17 Rnet = 2ohm Current (I) = 1Ampere

[@AluCard-c1p]

20:08 current becomes half, when resistence is increase by twice, i.e I2R = ÎR, î/I = 1/2 = 2î = I 20:21, P = 100kilowat , time = 1hr per day, one day consumption is 10rs , E = P x T = 1 X 100 energy consumption in one day. For 30 days consumption = 30 x 100 x 10rs= 30000rs.

[@HarshitDubey-v8g]

1 Like =95%+

[@RaviRajdevjoshi.1]

Very nice information ❤

[@meenamihaulia3922]

Sir/Bhai ne right time par video dali 😊

[@AnupamVerma-rf1dg]

Ha kal hi exam h mera

[@RDiitD]

Ha mera 1min baad hi h

[@brargamer952]

All Formula of Electricity: 1)I=Q/t 2)Q=ne 3)V=W/Q 4)V=IR 5) R=Rho×L/A 6) Resistance in series: RS=R1+R2+R3 7) Resistance in parallel:1/RP=1/R1+1/R2+1/R3 (*Reciprocal of R1+R2+R3) 8)H=V×Q i) H= Vlt ii)H= I²Rt iii)H= V²t/R 9) P=W/t i) P=VI ii)P=l²R iii)p=V²/R 10)E=P×t S.I Units : current (I) Ampere Charge (Q) coulomb Time (t) second potential diff or Voltage (V) volt resistance (R) Ohm resistivity (Rho) Ohm meter Power (P) watt Heat =energy= work=joule Measureing Devices : Ammeter/Milli Ammeter- for measuring current ( always connected in series) Galvanometer-for measuring small/sensitive current ( we can also get the direction of the of the current) voltmeter - for measuring volt (always connected in parallel) Ohm meter -measures the resistivity Things to remember: electron charge = (1.6× 10 -¹⁹C) 1KWH=3.6×10⁶J 1ampere =1000mA 1 kilowaat=1000W 1Horse power= 746W i hope this list will help you ! ek free ka like dete jana goal 2k like and you tube ka channel subscribe kar do mera. bhai or jo subscribe kar ga all paper me 85+score melaga

[@ALSONOBI]

Bhaiya app repid revision karake Mera sara topic clear kar diya I like ur pattern Use in teaching 🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@LovesehzaXharoon]

Radhe radhe 🙏🏻😍

[@Anushka-k3s2g]

Radhe Radhe ❤

[@aswaths7912]

Timestamps 00:04 - Overview of electricity concepts 00:39 - चार्ज क्या है? 02:21 - Quantization of charge explained 03:02 - Understanding current and ammeter 04:32 - Understanding work done and potential difference 05:11 - Understanding formulas for charge, current, voltage, and work done by charge. 06:30 - Understanding basic circuits and components 07:12 - Understanding resistance and its unit 08:51 - Understanding the significance of resistance in Ohm's Law 09:40 - Understanding the relationship between resistance and temperature in electricity 11:03 - Understanding voltage and current in parallel circuits 11:46 - Calculating total resistance using Ohm's Law 13:25 - Heating effect of electric current 14:07 - Understanding the concept of resistance and heat generation in electrical circuits 15:29 - Understanding the properties of Nichrome material 16:17 - Understanding Power in Electricity 17:45 - Understanding the concept of kilowatt-hour 18:33 - Understanding the importance of conversion in exams 20:03 - Understanding the relationship between voltage and current. 20:39 - Share and discuss about the lecture topic with friends.

[@Study.Channel.0_0]

if the resistance of a conductor doubles, what happens to the current for the same applied voltage? (b) It becomes half

[@Anime_wizz..1]

Why

[@a.screation4061]

Here, P = 100 kW T=1×30=30h Rate of current= 10rs So. the total cost of current is 100×30×10 = 30000/

[@AmeyKeni-z8u]

Are bhayyooo wo 30 nhi 720 hona chahie Hrs me cnvrt krna he use

[@Lonewill50]

Wahi wahi

[@NamanKesharwani-h1e]

​@@AmeyKeni-z8ubro time per day kitta use hota hai woh given hai so correct hai ans bhai ka

[@arungupta5168]

Bhai uska ans sahi hai apna recheck kro

[@HYPERDAZE]

Sahi he👍🏻

[@deepamishra224]

Thank you so much bhaiya❤❤❤❤ Love you from Uttarakhand ❤❤❤

[@VaishnaviTingre-shn]

Finally and successfully we are made perfect electricians ..!🤔😒🫡

[@Kiya...208]

Bhaiya please bring cased based questions.... Vote for this .. 😢

[@Kaushik_Banerjee033]

7:33 Arey yaar sir 🥲

[@Rahhahahahahhaha]

Lmao

[@suryansheditz019]

Ques 1 20:14 Ans:b) Ques 2 20:19 Ans:30,000 KWh

[@MohammedDaniyal-ex3pw]

bro its 30000 rs not KWh

[@Kanishkaarora227]

May it's because v is directly proportional to IR😅

[@vatsalchoudhary5976]

@@MohammedDaniyal-ex3pw YA U R RIGHT

[@GamingElite_yt15]

it is right ans b) and 30,000 Rs

[@conceptmastighazipur]

kzbin.info/www/bejne/i37GlWppn5epitE

[@Infinity-t3q]

20:18 b) it becomes half. Using V=IR I=V/R I'=V/R' I'=V/2R[voltage given to be same] I'=1/2 of R -thus becomes half.

[@Pranks_girl]

Jisna like nahi kiya wo 2025 wala board ma fail

[@shashidharkalyan]

Thank you bhaiya ji mee iss chapter kelia besabri se intezar kar raha ta 🙏😊

[@ADEDLOOP]

00:04 - Overview of electricity concepts 00:39 - चार्ज क्या है? 02:21 - Quantization of charge explained 03:02 - Understanding current and ammeter 04:32 - Understanding work done and potential difference 05:11 - Understanding formulas for charge, current, voltage, and work done by charge. 06:30 - Understanding basic circuits and components 07:12 - Understanding resistance and its unit 08:51 - Understanding the significance of resistance in Ohm's Law 09:40 - Understanding the relationship between resistance and temperature in electricity 11:03 - Understanding voltage and current in parallel circuits 11:46 - Calculating total resistance using Ohm's Law 13:25 - Heating effect of electric current 14:07 - Understanding the concept of resistance and heat generation in electrical circuits 15:29 - Understanding the properties of Nichrome material 16:17 - Understanding Power in Electricity 17:45 - Understanding the concept of kilowatt-hour 18:33 - Understanding the importance of conversion in exams 20:03 - Understanding the relationship between voltage and current. 20:39 - Share and discuss about the lecture topic with friends. ADEDLOOP....

[@VidhiJain-ut5zg]

Naukar ko kya sab ke Jo ye sab comment Kar Rahe ho 😂

[@Tensura_xi]

@VidhiJain-ut5zg AI use kara he usne

[@DemonGamer-l3x]

9:47 answer R =rho *2/1/2. Therefore,R=4 times Where if value of rho is 1 then)

[@fais2021]

All teachers are best but Prashant sir is very very very very very best teacher

[@woodworkingRSK]

You and your team is god of science, thanks for mentor us ..

[@Anshikachahar1112]

❤

[@AdityaSalgude-kq2zr]

1)b)It becomes half 2)30,000

[@arunsunil216]

19:34 Q ans : 5kw * 10h * 1₹ =50kw*1₹ =50₹

[@MayankSingh-oj3xt]

Please provide all the remaining chapters rapid revision as soon as possible as syllabus is almost completed it will be much helpful for last minute revision..😊

[@AadyadeepSharma]

East or west prashant bhaiya best maj aa gaye bhaiya litrally kab se is vid ka wait kr rha tha

[@Kamakshisharma576]

Yuppp !! U are right I'm also waiting for this video.....☺️

[@AadyadeepSharma]

@@Kamakshisharma576 YEH I TOPPED IN MY SCIENCE EXAM BECUSE OF BHAIYA

[@Kamakshisharma576]

​@@AadyadeepSharmacongrates dear☺️👀💛

[@nandanyadav2008]

1 b) it's become half 2 100×1=100 100×30 = 3000

[@ShivamRawat-m3o]

All Formulas of Electricity: 1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (-1.6 x 10⁻¹⁹ C) 1Ampere = 1000mA 1 Killowaat = 1000W 1 Horse Power = 746W

[@naseeraban1031]

Here are the key formulas from Class 10 Electricity chapter: *Electricity Formulas* *1. Electric Charge* - Q = ne (Charge = number of electrons × charge of an electron) - Q = It (Charge = current × time) *2. Electric Current* - I = Q/t (Current = charge / time) - I = V/R (Current = voltage / resistance) *3. Resistance* - R = ρL/A (Resistance = resistivity × length / area) - R = V/I (Resistance = voltage / current) *4. Ohm's Law* - V = IR (Voltage = current × resistance) - I = V/R - R = V/I *5. Series Circuit* - R_total = R1 + R2 + ... + Rn (Total resistance = sum of individual resistances) - I = V/R_total *6. Parallel Circuit* - 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn (Reciprocal of total resistance = sum of reciprocals of individual resistances) - V = I × R_total *7. Power* - P = VI (Power = voltage × current) - P = I^2R - P = V^2/R *8. Energy* - E = Pt (Energy = power × time) - E = VIt *9. Heating Effect of Current* - H = I^2Rt (Heat = current^2 × resistance × time) *10. Electric Power and Energy* - 1 kWh = 3.6 × 10^6 J (1 kilowatt-hour = 3.6 megajoules) *Important Constants* - Charge of an electron (e) = 1.6 × 10^-19 C - Resistivity of copper (ρ) = 1.68 × 10^-8 Ωm *Other Key Concepts* - Potential difference (V) - Electromotive force (EMF) - Conductors, Insulators, and Semiconductors - Series and Parallel circuits - Short circuit and Open circuit These formulas and concepts will help you solve problems in the Class 10 Electricity chapter. Would you like additional practice questions or explanations?

[@Anish_upadhayay]

Thanks

[@dheryatak3124]

Ya i want

[@Divyaa7409]

Is this AI generated 'cause it looks like it

[@SPTHETOPG_17]

Bhaiya in 0:59 the definition of semiconductor and insulator are opposite . It is wrong.

[@MehranRT12]

Sir ne jo bola wo sunayee naii diya kya behra hai kya.

[@MehranRT12]

Bhaag yahaan se..

[@AmitSharma-rh8nb]

Shi me bhara hi 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂

[@ISAGI_NTD]

Bro it's correct i think your way of understanding it was wrong he said semi conductors do let electricity pass through them but not completely

[@Bilal-h6d3w]

​@@AmitSharma-rh8nbBhai iska matlb hai definition wrong hai not bhaiya so aise bazati nhi krni chahiye kisi ki uska mtlb vo nhi tha 😊

[@ITSME-k2]

20:14 b) It becomes half 20:19 30000 rs.

[@basabchakraborty1790]

Jisko next chapter METALS AND NON-METALS chahiye please like karo -------->

[@PoojaKhanna-x4g]

The video is very helpful sir for this complicated chapter Thanks a lot......😊😊

[@santoshnishad4657]

Jisne subscribe nhi kiya vo exam me fail ho jayega 😂

[@Soul1artist-y5d]

Kal hai science ka paper 😅

[@saiswaroop2008]

Kl h science ka paper 🙏🏻 thanks

[@MeenaKodain]

2 ohm + 2 ohm ( series) Therefore it is 4 ohm . Then 1/4 ohm + 1/4 2/4 then 1/2 therefore R equivalent is 2 ohm

[@sterixff4114]

Prashant bhaiya ko best teacher and best motivational speaker manne wale like kare 👍

[@Akshayagrawal007]

Bhaiyaa ne aj josh meter bhul gye

[@Gaming_98015]

The first question answer is b) it becomes half and the second question answer is 3,00,000

[@Thefreestyleboy]

I think it's 30000 not 300000❤

[@Theartist2785]

Yes​@@Thefreestyleboy

[@Ayanscric]

Second is 30000😊

[@minakshiJoshi-j9n]

❤❤❤❤❤ thank u bhaiya❤❤❤❤❤❤

[@ShreeBhagvan-f7w]

Bhaiya you are the best teacher in whole world ❤

[@AayushRajak-yv1wp]

I am proud of all friends that they have passed 99% successfully and more than this

[@shubhamphougat7082]

1 like = 95% ❌ 1 hour daily=95%✅

[@AnanyaJain-m1x]

One day before exam 🥱🤥💀

[@YASH_JAATZ]

Q)2) Solution:- P=100000W=100KW [1KW=1000W] time =1 hr per day For 30 days, t\time=30 hours We know that, P=W/t=,W=Pt=,W=100KW×30h=,W=3000KWh Cost- 1KW = Rs 10 3000KW = Rs 10×3000=Rs 30,000 Answer= Rs 30000

[@ApoorvaShalini]

Bhaiya aaj class mein bhi revise kara diye the ... You are the best Ye 9:59 mein class ka voh vala question 😂😂😂.. jismein mein galti ki thi..2Ω vali bacchi😂😂😂😂😂... Bhaiya maaf kar do na 👀.. harbadi mein gadbadi ho gayi... Kasam se aage se aaisi galtiyan nai karungi😭😭😭💀🥲... Bole the.. thappad maar lena ..maar Li thi 🥴

[@Sharvari10th]

Yesss .... True

[@Kanishkaarora227]

​@@ApoorvaShalini😂

[@Kanishkaarora227]

Main bhi 😂😅par phir jab bhaiya ne kaha thapad Maro tho phir meri budhi khuli aur maine sahi kar diya unke batane se pehle 😂😅

[@sharmabhanublock1814]

God bless you guys do hard work and try to get 99% In your exam

[@Mm77star]

Bhai apka exam kb hai

[@RubyGupta-x5p]

TQ so much sir I need this chapter 😊🙏🏻😀

[@AbhishekKumar-tp5wj]

💖💖💖💖💖💖💖

[@Shivkumar.comgwgw]

Kya bat ha sir moj kardi 😂❤ jisna like nahi kiya 17:29

[@ChandrabhagaDaphade]

20:15 Option (B) 20:32 answer :- ₹ 30,000

[@deepamishra224]

Respect button for Prashant bhaiya❤❤⬇️⬇️⬇️

[@Indigo_lover6hu]

All the very best dear❤for board examination

[@Ayan412-o7m]

Bhayiya yar 9th class ke bhi to kuch rapid revision Lao 25 ko exam hai

[@Pinki-h9p]

Same

[@atharvkulkarni95]

Same

[@The_Jaat_gaming]

Same bhai

[@The_Jaat_gaming]

Tum bhi kisi vidhya bharti school se ho ???

[@JAATboy284nr]

Mera kal hi hai bhai😅

[@manjurao5232]

bhaiya please magnetic effect of electric current bhaiya please because we have that for half yearly exam please bhaiya 🙏🙏🙏🙏

[@Rajeev_meena]

3-4 din mai aa jayaga

[@Secret_._girl944]

​@@Rajeev_meenatab tak exam aa jayega

[@Artoholic_Devanshi]

Vote for Ch-3 Metals and Non Metals now Bhaiya we request ch-3 next ❤

[@sarojparihar7664]

Q1.answer is b because resistance is inversely proportional to current

[@sarojparihar7664]

Q2. 30,000

[@nimitagupta6214]

Prashant bhaiya op❤

[@saifalisaifali7855]

Charge Current Potential Potential difference Circuit Omh Lay's

[@prashant_Studios]

Ty bhai

[@ankitbaloda8058]

20:33 Rupees 30000

[@helperBoii]

Yea I got the same

[@Zoya30737]

20:07 (b) It becomes half 20:21 P=100000W=100KwH t=1H Energy consumed=Pt =100KwH×1H=100KwH [1KwH=₹10] 100KwH=100×10 =₹1000 Cost for 3 days=3×1000 =₹3000.

[@Shivansh-NDA-d5o]

Bhai 3 days nhi h 30 days h questions mein

[@Shivansh-NDA-d5o]

30,000