Electricity Numerical Top 25 || Science || chapter 12 class 10 in one shot

[@yupitstrue2468]

52:40 Ratio = m²:1

[@pankajverma8647]

This comment brought smile on my face after 1hr of study😗😗

[@bahubaligaming4686]

True😊😊😊

[@palaksehrawat2005]

Gajab

[@bhavanachaudhary2084]

True 😂😂😂😂gjb sense of humor 🤣

[@ishikasharma9390]

Kirtichow

[@snehilraj6436]

7:07 When 1 J of work is done on 1 C of charge, the Potential difference is said to be of 1 Volt. Also, 1 V = 1 Joule/ per Coulumb And, W = VQ, therefore 3 V x 1 C = 3 Joules. 10:07 = Highest resistance is in series therefore adding them all up we get 48 Ohms. Lowest resistance value is in parallel setup therefore 1/R = 1/R(i) + 1/R(ii) + 1/R(iii) + 1/R(iv) = 2 Ohms. 14:24 i) 0.183 Amperes ii) 2.2 Amperes 16:35 i) Take 3 Ohm and 6 Ohm resistors in parallel and 2 Ohm resistor in series. ii) Take all of them in parallel. 20:01 To find : V,W/E in kWh P. V = IR(Ohm's Law), 200 Ohms x 1 Ampere = 200 Voltage. W = VQ. We need to find Q first. We know that Q = I x t = 1 x 18,000 seconds (As 5h = 18k sec) = 18000 Coulumbs. Now, W = VQ, 3 x 18,000 = 36,000,00 Joules. P = W/t = 36,000,00 J / 18,000 s = 200 Watts. Now W = E = P x t (in kWh) = 0.2 Kilowatts x 5 hours = 1 kWh or 1 unit. 25:10 R = PL/A = 1.72 x 10^6 x 10^3/ 3.14 x 10^8 = 5.47 Ohms. 26:10 R = PL/A = P x 1/4 / 4 (As Rho is constant in both the cases, but length decreases by the factor of 1/4 and area increases 4 times). = 1/16 times. 27:39 P = IV = I = P/V = 1000 watts/220 Volts = 4.54 (Approx.). Therefore the fuse rated at 5A should be used. 29:21 9 Ohms in total therefore 9/3 gives 3 Ohms each for the each resistor. Now, they are connected in parallel and the equivalent resistance becomes = 1/3 + 1/3 + 1/3 = 3/3 = 1 Ohm. 30:28 i) Rho = RA/L and unit = Ohm metre. ii) RA/L = 3 x 10^-2 x 1.7 x 10^-6/3 = 1.7 x 10^-8 Ohm m. 32:02 i) P = VI = 250 V x 0.8 A = 220 Watts. Converting into Kilowatt, 200 W = 0.2 kW. In 1 hr, 0.2 kW is used so in 8 hrs(As every day, the appliance is run for 8 hrs) = 0.2 kW x 8 h = 1.6 kW is used. Now, There are 60 days to be counted so total power consumption will be 1.6 kW x 60 = 96 kW. Now, 5 Rs. is charged for 6 kW so 6/5 = 0.8 (Approx.) is charged for 1 kW. So the bill will be 96 kW x 0.8 Rs. = 76.8 Rs (approximately). 35:46 In every conductor, Rho is constant therefore we will consider only L/A. Now, For conductor (i), 1 L/1A = 1 Ohm. For conductor (ii), 2L/A/2 = 4 Ohm. For conductor (iii), L/2/2A = 1/4 Ohm. So, highest resistance will be served by Conductor (ii). 38:10 (4 + 4) kiloOhm = 8 Ohm. Similarly, 8 kiloOhm for 2nd pair. Now they are in parallel, therefore, 1/8 + 1/8 = 1/4. Therefore, total resistance = 4 kiloOhm. 39:26 i) When K2 is open, we simply add the resistance and get 8 Ohms. Now, I = V/R = 12V/8 Ohm = 1.5 Amperes. ii) When K2 is closed, we will add the first two resistors and the bottom two resistors to get 8 Ohms on both sides. Now, they are parallel, therefore 1/8 + 1/8 = 2/8 = 1/4. R = 4 Ohms. Now, I = V/R = 12V/4 Ohms. = 3 Amperes. 41:06 The above two resistors are in series as so the bottom two are. Adding them up, we get 12 Ohms on both the sides. Now, we can get the total resistance as they are parallel now. Therefore, 1/12 + 1/12 = 2/12 = 1/6. R = 6 Ohms. 42:31 Now, 1/20 + 1/20 = 10 Ohms, as the upper two are in parallel. Now they are in series with the 10 Ohm resistor. Therefore, (10 + 10) Ohms = 20 Ohms. We've solved the first two stages of the Pyramid. Now going down, There are two resistors of 10 Ohms each combined parallel to the aboves. Therefore again 1/20 + 1/20 gives us 10 Ohms and we add it to the third resistor to get 20 Ohms as we completed the 3rd Stage. Now, there are 3 resistors in series combined parallel to the aboves. We add them up and 1/20 + 1/60 = 15 Ohms. Now we're on the last stage. Add the remaining resistance to get 45 Ohms in total. I = V/R = 20 V / 45 Ohms = 0.45 Amperes (Approx.) 45:17 We add the left side resistors and then reciprocal it by the one that is parallel with it to get 3 Ohms. Now we add those 3 Ohms with upper resistor and reciprocal it with the resistor parallel to it giving us again 3 Ohms. Again, we add the 3 Ohm resistor on the right and reciprocal it with the parallel to get 3 Ohms. We add the 3 Ohm resistor on the bottom right side to get 6 Ohms and reciprocal it with the bottom resistor as they are parallel to get : 1/6 + 1/3 = 1/2. That is 2 Ohms. 46:17 2 Ohms with the same logic. 47:51 He explained it so here's the answer = 0.45 Ohms (It can be wrong so you can check on this). 47:54 Now, with the same logic, answer should be 10 Ohms. 49:03 6/5 = 1.2 Ohms. 50:49 (3+2) Ohms = 5 Ohms as the right ones are in series. Now reciprocal it with the 5 Ohms resistor that is parallel to it to get 5/2 Ohms. Now, add 1.5 = 15/10 = 3/2 to it to get 4 Ohms. Now it is parallel with a 4 Ohms resistor on the left side. Reciprocal it and we get 1/R = (1/4 + 1/4) = 1/2. So R = 2 Ohms. 52:10 (1/3 + 1/3 + 1/3) = 1 Ohm. Now, add them with the series one to get 2 Ohms. 52:37 When connected in series, they all add up to m times. Thus, X = mR. Now, when they are parallel their reciprocals add up to m times. Thus 1/Y = m/R. That is, Y = R/m. Now, ratio of X to Y : X/Y = mR/R/m = m^2 x R / R. Dividing both sides by R, we get m^2/1 = m^2 : 1. So these all are the answers with some of them containing explanations. Hope it helps!

[@as_usual3559]

Itni mehnat krne ki kya jrurat thi😂copy me solve krne pr kuch jaarha tha kya bro🌝

[@shrutiiiii7872]

@@as_usual3559 sahi bole lagta hai toppers hai😂😂😂

[@as_usual3559]

Pata nahi inhe bs show off krna rhta h gyaani bante hai jada😂

[@khushisinghi5932]

@@as_usual3559 atleast vo hamari help kr rha h ,cheak karne ke lia, be thankfull yyr

[@as_usual3559]

@Fable Corner NP Chill out❄️🏔️

[@Aim-UPSC123]

52:40 .Value of X=Rm , Y=R/m Now X/Y= Rm/R/m = Rm²/R Ratio = m²:1 HOPE IT HELPS 😊

[@SurajThakur-lu1zg]

Mha purus

[@kyciliusgaming1179]

@@SurajThakur-lu1zg 🤣

[@SHADOW786X]

Kaise

[@Hellowworld123]

Correct my answer is also same

[@SHADOW786X]

@@Hellowworld123 don't lie

[@goodgamerz3295]

Number of the Resistors = m Resistance in each Resistor = R When they are connected in series, Equivalent Resistance = R + R + R +R +........ m times. X=Rxm .: X = Rm. Now, When they are connected in Parallel, 1/Req. = 1/R + 1/R + 1/R + 1/R +........ m times. 1/Req.= m/R .: Y = R/m Now Ratio of X an Y is → X/Y = Rm/(R/m) = Rm²/R = m²/1 Hence, the ratio of the X and Y is m²:1.

[@___attu___6811]

Solution:Given: length= 1 km =1000m radius=1mm =1×10^-3m and resistivity = 1.72×10^-8 ohm m Area of cross section = πr² = 3.14×(10^-3)² = 3.14× 10^-6m² Now, resistance = (resistivity×length)/(area of cross section) resistance = (1.72×10^-8×1000)/(3.14×10^-6)resietance = 1.72×10/3.14 resistance = 5.478 ohm.

[@everythingsilently...2765]

Yes this ans is right

[@___attu___6811]

@light servant so u have to ask...

[@dhanshree26]

Thanks it really helped :)

[@___attu___6811]

@@dhanshree26 Most wlc Dear..

[@deadshorter]

Thank you so much Sir ka samagh me nhi aa raha tha App ne samgha dea 😊😊

[@dishamishra3000]

16:41 For 4 ohm, 6 and 3 ohm will be connected in parallel and with it 2ohm will be connected in series .

[@bijendervats8326]

Hlo

[@bijendervats8326]

How are you

[@ssreddy4422]

52:40 Ans : Rs/1/Rp=R1^2+R2^2+R3^2 .R^2:1 Sanjeev sir reply pls

[@indianlappygamer7222]

m²:1...👍

[@dreambig2126]

m2:1

[@dreambig2126]

@@aditishinde6603 no m:1 is right

[@mathsgalaxy3729]

no m^2:1 is right

[@gauravaggarwal1112]

Yup same here 😁😌

[@yashrao7439]

35:08 I recommend that you keep the numbers in fraction as it will give you the exact answer

[@surbhirawat272]

18:51----> 3 ohm & 6ohm resistors in parallel and 2 ohm resistor in series with them. 1/Rp= 1/3 + 1/6 = 3/6=1/2 Rp= 2 ohm Re= 2+2= 4 ohm.

[@shraddhapatel4087]

13:06 Current for first case = 0.1833 A Current for second case = 2.2 A

[@amankumarverma4650]

Thanks biroo

[@hamdatahseen2434]

Thanks sister 😶

[@manishaparmar6165]

Shukarya bayhen

[@Boss-uk1zn]

First worng answer

[@Boss-uk1zn]

5.45

[@ashusharma6118]

Sir sapka pdhaya hua sb samaj m aata h sir 😊😊 I hope every student who is studying from you will score 95 plus in boards.🤘🏻

[@Anmol_Turbanators]

Wish you same bro

[@LakhwinderSingh-bd3ty]

yeh nhi ho skta

[@suhanaperween7841]

Same wish for you 😇😇

[@aaravbhardwaj5654]

@@_Sweetmoontae_ 😂

[@shreyanshichaurasiya4446]

ys

[@whyandhowdaushitenande]

18:50 3ohm and 6ohm in parallel and 2ohm in series Rp = 1/3 + 1/6 = 2+1/6 = 3/6 Rp = 2ohm And that series one 2ohm Rs = R¹ + R²(2ohm) Rs = 2 + 2 Rs = 4ohm 25:10 My answer is 1.82 × 10¹ Around 18.2ohm 😶

[@kartikupadhayay0806]

ANSWER OF QUESTION ON VIDEO TIMING 52:40 is m²:1 AS, X = Rm AND Y = R/M THEN, X/Y = Rm/R/m = m²/1 = m²:1

[@HRajMNNIT]

Sir, the answer is *m²:1* When connected in series Resistance =mR=X When connected in parallel Resistance=R/m=Y X/Y=mR/(R/m) X/Y=m² This implies that X:Y=m²:1

[@kartikchoudhary334]

Amazing

[@rudralather6853]

Nope Y = m/r So x/Y = r^2

[@kartikchoudhary334]

@@rudralather6853 no bro in parallel we have to do reciprocal in last so it becomes R/m

[@HRajMNNIT]

@@rudralather6853 You are incorrect 1/Y=1/R+1/R+_____m times 1/Y=m/R Y=R/m

[@indianlappygamer7222]

m²:1....👍

[@doomddudc6440]

35:40 Answer 80INR /₹80

[@VANSH-s1d]

Kon kon term 2 ki taiyari kr rha h😂😂 is video by edumantra

[@shifasanimationsandgamer4625]

Obviously sabhi krrhe h ab term 3 to ane nahi wala jo uske liye karenge

[@viveksinghsisodiya9564]

@@shifasanimationsandgamer4625 🤣🤣🤣

[@harshitagarwal7090]

With the God's grace all edustends will get more than 95%

[@harshitkushwaha9000]

Lol

[@harshitkushwaha9000]

Students spelling****

[@theweebster]

Why only edustends literally everyone will get

[@tejinderkaur735]

Thank u bhai

[@abhicadburiezzz1180]

Mil jaye tho aapke naam pe mandir par archana karwawunga Julio🙏🙏

[@LakshyaUjjwal689]

16:48 The combination was 3 ohm and 6 ohm in parallel and 2 ohm in series for 4 ohm resistence

[@girrajgirraj1387]

Rp is 1/2ohm and Rp is 6 ohm

[@Noone3djdjdjdm]

25:09 Homework Answer is *5.48 ohm* 😎 47:51 homework Answer is *19.6 ohm* 😎 it is correct or not I dunno🤣but I solved it...😂

[@sharkboy1501]

Mera 18.5 aya past me 2.5 ➕ 14+2

[@pradumjadaun9227]

Mera bhi 18.60 h approx iska answer 19 ohm h

[@AMANSAIFI18]

25:09 5.47 ohm

[@yashkapoor7668]

Yr mera to 6.9 aa rha h 🤣🤣😂😂😂😂😂

[@goku69.]

@@yashkapoor7668 Becoz we are Special 😂

[@mubashir923]

53:01 :- x/y=Mr/r/m >Mr×m/r >r and r cancel >m×m=m2(m square)

[@poojachaudharyArts]

15:58Sir series me 2ohm ka resister rakha padega aur 3 and 6 ohm resisters ko parellel me rakhna padega👍👍

[@pawankumarsingh4715]

Yes bro I got the answer in the same way

[@poojachaudharyArts]

@@pawankumarsingh4715 👍yahh bro .... Good luck for your exam 💖 But ab tho hum sab ko kuch Jada he time mil Gaya ..ab to exam may me hai🥰💝💖

[@pawankumarsingh4715]

@@poojachaudharyArts bilkul bhai ab to exam me phodna hai kaher macha na hai🔥🔥🔥🔥

[@pawankumarsingh4715]

@@poojachaudharyArts all the best you too

[@sunithabansal8849]

Yes bro I also got in the same way!!

[@salonikarn2379]

Sir, while doing calculation, plz tell the minor calculations cuz there are students who get stuck and u just go with the flow.🙏 Sbka concept bhot strong nahi hai sir. I heartily appreciate ur diligence 👏

[@karan6781]

Shi baat h

[@priyankjoshi9730]

agreed

[@atulsharma332]

Yes bro

[@devishgurjar19]

Right

[@shauryasrivastava4449]

Yes sir

[@skybluegaming8836]

sir, your explanation is very nice but plz say the answers for the sums you ask us to do so that we can cross-check. I love your videos. You are multi-talented sir. You are truly a great mentor

[@bossansh2834]

52:38 ans is Given, No. Of resistance= m Resistance of each resistor=R ☆connected in series Req= R+R+........m times Req=R×m Req=Rm ~ x=Rm ~ (1) ☆connected in parallel 1/Req= 1/R+1/R+.........m times 1/Req=m/R ~ y= R/m ~ (2) # Ratio of X and Y is X/Y= Rm/R/m Therefore, Rm×m/R= m^2/1 Then, X:Y = m^2:1 ( this is our ANSWER )

[@shortsking6042]

Sir , YOU DID A LITTLE MISTAKE IN A QUESTION. Kindly notice your question's solution which was done at 32:15. In (ii) part of that question, you forgot to find the total energy consumed per day ( i.e. 1.6 KWH, but your's one was 0.2 KWH ) as the bulb was used for only 8 hrs a day. SO, PLEASE PIN IT IN COMMENT SO THE STUDENTS WHO WILL WATCH THIS VEDIO CAN TAKE CORRECT INFORMATION FROM YOUR CHANNEL.😇😇

[@The_Tormented_One]

50:40 Total Resistance is 12 Ohm and total current is 8.33 A.

[@mohinipatel7258]

1.2 ohm

[@surajtiwari2535]

14:28Answer 0.18

[@azrajaved5880]

14:30-current drawn by a bulb =0.18A

[@shubhagrahari2581]

Who wants Social Science Revision for class 10? 👇 🙏🏽Please Sir 🙏🏽

[@bhavyamacharya6711]

Happy Teacher's Day Sanjeev Sir U r one of the Best Teacher in my life Thanks for your Mesmerising Skill of Teaching Us......

[@Deepanshu12]

Kya timing hai parso science ka pre board or aaj shot clear 😄😄😄😆😆😆

[@abhaysoni1102]

Bhai sunday ko bhi

[@manishkaushik1916]

All the best friend

[@palaksehrawat2005]

Aaj preboard tha science ka😭😭😭

[@manishkaushik1916]

@@palaksehrawat2005 keesa gya

[@palaksehrawat2005]

72 to 75 out of 80 according to me

[@krrrrupa]

Formulae 00:48 Questions 07:00

[@kumar.b384]

He is the only one teacher to explain sst and science outstanding ❤️

[@sanketverma4497]

@magnetbrain is also good for sst

[@savitakhadse672]

According to me no 🖕

[@harshitkulshrestha3394]

@@sanketverma4497 ye zaroori toh nhi tha batana

[@englishphobia5853]

He teaches maths and language tooo

[@englishphobia5853]

He teaches maths and language tooo

[@adityarana7438]

14:25 ANS is 0.183 A

[@jyotigupta6990]

Yes you are right

[@ayushtiwari2048]

From my experience only power numericals of electricity come and a 3 marks resistance question Note:- got 90+ in science in 10

[@Sudhanshu_IITIAN29]

App kis class me ho??

[@ayushtiwari2048]

@@Sudhanshu_IITIAN29 ab 12 Mae aane wala Hu bro

[@avikachaturvedi5018]

plz help me out in science

[@ayushtiwari2048]

@@avikachaturvedi5018 just read carefully all in one and ear your concept plz plz try most the example of balancing and some parallel and series electricity numerical also read carefully biiiology from all in one or you can watch videos of Edumantra to clear Concept

[@avikachaturvedi5018]

@@ayushtiwari2048 thank you so much for your supportive suggestion

[@tanishkra5214]

at 32:03 is good for board point of view

[@manojsingh3724]

18:57 sir has paused video 😂

[@afshashakil45]

Yes

[@shorya_mehta_193]

52:43 M×R =X M×1/R=Y X/Y =R square /1 So X:Y = R2/1 Sir pls tell if it it right? I watched the entire session live and it was really helpful 😃 Thanks ❤️🔥

[@navyaaggarwal413]

It will be m^2:1

[@navyaaggarwal413]

How u written x^:1

[@shorya_mehta_193]

@@navyaaggarwal413 by mistake but It will be R2/1

[@shorya_mehta_193]

@@navyaaggarwal413 m will be cancelled

[@pranjaliarela3821]

It will be m^2:1

[@Anonymous-2005]

47:50 ka ans 18.6 ohm....am i right???

[@shifamonam6131]

Mine is also same

[@arhamkhan8097]

Yes bhai 18.61 Is my Answer

[@adityasinha6039]

Bro kaise aaya zara batana pls

[@Psyonic_07]

52:30 Sir X/Y= m^2/1, X:Y= m^2/1, As when we combine them in series then Rs = m(R), and in Parallel the 1/Rp= m/R, so Rp= R/m and when we will do X/Y then the ratio will be equal to m^2/1 :)

[@lisavader8231]

Sir: 37:46 slow kar ke dekho.. Me: watching it on 2x..

[@ChandniSingh-sr9cr]

17:56 let us try all pyarelal 🤣🤣

[@shorya_mehta_193]

52:43 M×R =X M×1/R=Y X/Y =R square /1 So X:Y = X2/1 Sir pls tell if it it right? I watched the entire session live and it was really helpful 😃 Sir I just have problem while solving when resistivity is given and I am unable to devide! Anyway --I ❤️ huge thanks to u🎉🔥🔥 love u❤️

[@indianlappygamer7222]

m²:1........👍

[@dineshthakare9963]

Bro the answer is n^2

[@sanjanarajbhar1169]

14:28 .....Ans - 1st case = 0.183 A , 2nd Case - 2.2 A

[@ayesha3561]

Me trying to solve electricity numericals Le ad : ( tony kakkar ) tera suit bda tight 5 foot ki tere height uspe krti rehtii fight , pyaar bhi krle na .... Me : " 🙂🙂🙂🙂🙂 "

[@KHAN-zh8le]

😂

[@aayushimehta5892]

😂😂😂

[@aasthar.7580]

Haha same😂😂

[@AshokMeena-mq1li]

🤣😂

[@jhulanchatterjee3098]

😂😂😂😂😂

[@isodimetrix]

52:57 m^2:1 sir 🥰👍👍 Thanks a lot sir!! Helped a lot!!!!! 😍😍😍😍😍😍💖💖💖

[@indianlappygamer7222]

m²:1....👍

[@shubnotfound1200]

How bro plz tell me?

[@AbhishekMishra-do6fc]

how????

[@chaitanyadwivedi3047]

Last question ans is.... Rs : Rp for 'm' resistor of same resistance 'r' will be always equal to m^2:1...in each and every cases..... Thanks sir...

[@indianlappygamer7222]

m²:1....👍

[@adarshpal9142]

Yes

[@aadityasharma3586]

51:26 answer is 7.5 ohm

[@kavitaupadhayay51]

X/y =m^2 (Answer of H.W. QUESTION )

[@asthamishra4542]

Same mera bhi yahi aa rha h

[@kimtaeni8713]

Bhai please briefly explain kardo kaise ayega iska answer 🙏🏻🙏🏻🙏🏻

[@saetofficial6397]

14:23 ---0.183A ............

[@naseerkhan2848]

Shi Kaha londe

[@ayushshekhawat4927]

yes sir mera bhi yahi aa raha hai

[@dilipsubedi05]

bhai kiya tum mujhe 47:00 ka answer bta doge

[@sam_infinity6223]

Only 1.81 lenge

[@dattebayo8121]

Mera 5.454..... aarha hai pls help

[@SonuSharma-hb1ox]

52:37 sir answer us m² total resistance in series is x=mr and the total resistance in parallel y=R/M therefore ratio =x/y so ratio will m² 😁

[@indianlappygamer7222]

m²:1....👍

[@Nik.Beast.]

Oh thanks I was doing that wrong My ans was R² bcoz I do not reciprocal m/R

[@Nik.Beast.]

@Neelam Gupta Konsi file

[@SCOY2006]

27:30 this answer is wrong correct answer is 16 times because here said that length is doubled on itself. And. This process repeated again means L+L+L+L means 4L and A/4. So. 4×4 and hence answer is 16 times 🧐🧐🧐🧐

[@ujjwalpandey5440]

🙏🙏हे भगवान लाख लोग चाहे बुरा हमारे सर का पर हमारे सर कायम रहे लाखो सालों तक 🙏🙏

[@Saurabh_Rao_1111]

Ha bhaii😘😘😘😘

[@dr.sunshine16]

52:41 Sir, Here, X=mR Y=R/m so, X/Y=mR/(R/m) =m*m/1 =m²/1 Therefore, X:Y=m²:1 The session was amazing Thank you!

[@harshalkore4961]

25:05 the answer approx is 5.4 ohm.... 😊i solved

[@ZicktaGaming]

Wrong

[@amaleswaleha5632]

25:30 Sir according to me the lenth5is doubled it means that if length was 2 meter then it was doubled to 4 meter and then again process is repeated And you have bend it Please everyone reply if I am correct or not??🙋‍♂️

[@psteeljam]

it is said that length is doubled on itself. hence, it is bend

[@studynepal4029]

A complete circuit consists of a 24.0 V battery, a 5.60 ohm resistor, and a switch. The internal resistance of the battery is 0.28ohm . The switch is opened. What does an ideal voltmeter read when placed (a) across the terminals of the battery? (b) across the resistor? (c) across the switch? plz do this🙂🙂

[@vanshdixit3889]

Hey, just read your question, and i believe the answer to this will be, "In all the situations, the voltage or the potential difference would be the same". if somewhere you find the answer that proves this wrong, plzz tell me, so that i can also know the correct answer. Other wise according to me, this is correct....

[@sukshamsharma1038]

bro it should be ammeter , i think :(

[@SatyajeetKV]

1V = Potential difference between a 1ohm resistor when 1A of current is passed through it. ( V=IR ) IS IT CORRECT ? Plz reply 🤓

[@1020bsss]

No

[@dhairyaparmar65]

noo bruh 1 v potential difference is the the 1 joule of work done to move 1 coloumb of charge from one place to another 👍 Hope it helps you😊

[@SatyajeetKV]

@@dhairyaparmar65 That's according to the formula V=W/Q What about V=IR

[@evilamrit]

Potential difference always exists between two points. And you have introduced only a single one. So, you are not correct broth...

[@manassaxena5386]

No bcoz that happens when there is something on division like v=w/q this means that 1v = 1joule of workdone by 1 unit charge, which is not the case in v=ir as v is not equal to current by unit resistance and v= product of current & resistance. I hope it helps you to clear your doubt. Peace

[@Nothing-hm8pj]

Sirji apki Tshirts bhot shi hoti hai... Bhut baar to motivate bhi krti hai...😂

[@Teacher_Ji]

47:23 R= 18.5 Ohm 52:40 Ratio = m²:1

[@pranjalsinghrathore294]

X=Rm------------(1) Y=R/m-----------(2) (1)/(2) X:Y=m^2:1 That's the answer of the last question....................

[@indianlappygamer7222]

m²:1....👍

[@ritikgupta6042]

Best teacher for science is only to only Sanjeev sir🤘😊

[@s.k.8773]

for 4 - 3 and 6 in parallel and 2 in series : for 1 - all in parallel

[@friendlypadhai]

47:49 :- 0.39 ohm 52:45 :- 1:4

[@Yadavshubham0001]

25:08kya clear karo wahi calculAtion me to problem thi

[@BHAVISHYEAHH]

video starts at 7:01

[@1vs1op]

Thanks 😊😊

[@ravindersolanki6509]

41:00 sir ya kya kar Rahi ho😂😂

[@psagaming5111]

Search PSA Gaming on KZbin

[@ravindersolanki6509]

@@psagaming5111 kyo😈

[@aakash__14ry]

Bhai 42:28 par bhe kya kar raha hai sir

[@ravindersolanki6509]

@@aakash__14ry sir na esma kya kar rahiii ho kha hai

[@aakash__14ry]

@@ravindersolanki6509 😂😂

[@killerop3218]

14:35 1st case I=0.183A (approx) in second cass I=2.2A

[@anupamdarpan7679]

No words to explain edumantra channel This channel ID one of the best educational channels on KZbin I will support edumantra if I ever get a chance to do so. 😀

[@imadahmed1857]

@Neelam Gupta kis chiz ki file hai ......I'll help you

[@technogamerzfan7709]

"Congrats to everyone who is early and who found this comment "🇮🇳🇮🇳🇮🇳🇮🇳".............

[@trickylearningbyrachitsing4411]

@@imadahmed1857 ...... M

[@nanms828]

Then why you didn't subscribe this channel.

[@himanshushekhar1528]

Thank U sir kal tuition mai test hai acche se revision ho gya

[@shahinapraveen6723]

Same

[@arafatmohammadasifbamboowa2211]

Why do you need tutions when sanjeev sir is their🤔

[@eztalkexpress]

30:33 But resistivity does not depend on length and area of cross-section then why we took "rho=R*A/l".Please clear the doubt.

[@Freefire_66789]

Yes sis resistivity does not depend on length and area of Cross- section But we need the exact value of resistivity. So we know the formula of resistance => R= rho × length / area of cross-section . By rearranging the formula we get rho (resistivity) = R×Area of cross-section / Length We can easily find the exact value of resistivity.

[@addyarani8532]

25:06 Answer is 5.4 ohm

[@ishikachhajed7088]

X/Y = m^2/1 Is the ans of last question Thanku sir for this amazing session of electricity...😍

[@prathamkumar9639]

Can you please explain how?

[@ishikachhajed7088]

@@prathamkumar9639 Resistance in series (X) = Rm Resistance in Parallel(Y) = R/m X/Y = mR / 1× m/R Hope you got this😊

[@prathamkumar9639]

@@ishikachhajed7088 thank you very much 🤗, मेरी तो हालत खराब हो गई थी। पता नहीं क्या क्या फॉर्मूला लगा रहा था

[@Madhavjindal]

Any students of Batch 2023-2024😢😢❤

[@madhukc352]

No

[@shreyshukla7496]

25:11 the answer should be 5.47 ohms i guess..... pls tell !!!!!!!

[@omkarholkar9504]

My 5.48 (approx) ohm

[@rohitraj1038]

My is 5.4ohm (approx)

[@prathamkumar9639]

@Shrey Shukla भाई तू correct है

[@prateekyadav3234]

Nhi yr wo 4.54 hi hai shayad. But fir bhi Tu ek baar check kar la

[@shreyshukla7496]

@@prateekyadav3234 check kiya tha maine 4 bar par tab bhi yahi mila Maybe I am wrong😂😭

[@riteshjagtap7992]

52:40 R^2/R = R:1

[@aryan7013]

answer of the last question: There are m resistor each of resistance R. First, they all are connected in series and equivalent resistance is x. Now they are connected in parallel and equivalent resistance is Y. What is the ratio of X and Y? soln: Given, Number of the Resistors = m Resistance in each Resistor = R When they are connected in series, Equivalent Resistance = R + R + R +R +..... m times. X = R × m ∴ X = Rm. Now, When they are connected in Parallel, 1/Req. = 1/R + 1/R + 1/R + 1/R +..... m times. 1/Req.= m/R ∴ Y = R/m Now Ratio of X an Y is ⇒ X/Y = Rm/(R/m) = Rm²/R = m²/1 Hence, the ratio of the X and Y is m² :1 thank you

[@KraToss0418]

Great

[@abhicadburiezzz1180]

Kyu baaapuji

[@abhicadburiezzz1180]

Bilkul samaj nahi aayi

[@ChandniSingh-sr9cr]

16:23 , sir to get 1ohm the resistors should be connected parallel!!

[@AnandSingh-no7hp]

Yes

[@tirthpatel8711]

47:36, sir 24 ohm not 22

[@legiongamer7179]

52:38 X equal Rm Y equal R / m X:Y equal m^2 : 1

[@panchusinghrawat4079]

If we assume Resistance in series be 2 then Resistance in parallel should be 1. ✨✨ Ratio will be 2:1

[@abhishektamjhamcenterkhair9370]

Sir, 18:37 time vale question me aap kr kr ke dekh rahe ho. Hme direct kaise PTA chlega ki ye question aise hi hoga , agar hm aise krenge board me to hmara pura time aise hi nikal jayega.🤔😥🙄

[@AmanP2006]

12:28

[@ramanmathur4467]

47:12 the answer is right but the unit will be killo ohm

[@nehaindian5492]

Sir You are such a great teacher cannot be explained in words. No words to define you. I love your teaching style.

[@gauravdeshmukh9906]

How depresssing it must be for sanjeev sir while reading the comments ...its just legends and ultra legends everywhere instead of the answers he has asked to give us in comment section🙂

[@rinkisingh7466]

Sab like ke liye comment karte hai..

[@gauravdeshmukh9906]

@@rinkisingh7466 true that 😂😂

[@adwaithkr8398]

Finally someone with a brain

[@ukohf]

Answer in 0.18333333333333

[@anushkasharma5523]

Then you give answer of the question

[@KuchBhi-ji3tl]

जय महाकाल🙏🏻 राधे राधे🙏🏻 नारायण नारायण🙏🏻 जय माता दुर्गा🙏🏻

[@garimavashishtha1062]

Sir... In the question..it is written power consumed.... So we should have used the formula I²rt.. i.e. VIT... Because power consumed in time T is energy...

[@kiranakella6784]

Ans for the last Q- m2:1 Thank you for the session sir! It was amazing🔥☺

[@indianlappygamer7222]

m²:1....👍

[@prathamkumar9639]

Can anybody explain how?

[@dreambig2126]

@@prathamkumar9639 in series R+R+R+...n =mR --1-- For parallel. 1/R+1/R+1/R.....m/R Therefore resistance in parallel is R/m--2--- divide 1 and 2 mR/R/m mR×m/R r gets cancelled therefore ratio is equal to m×m/1 m2/1 m2:1...🙏🏻😊

[@devdatt4583]

@@dreambig2126 thanku👍

[@dreambig2126]

@@devdatt4583 most wlcm

[@diwakersingh3444]

You are only who understand us ❤️❤️🙏

[@omvirsingh1233]

Sir ji numericals Karne Mai mja arha hai Isliye app or series laiye numericals ki Hmari practice axhi hoske 😍😍😍😍😍😍😍😍😍Sanjev sir is best teacher in the earth 😊😊😊😊

[@amanpal5253]

All teachers are best its depends on your consideration 😄

[@PAPAJI-n8h]

35:00 in this question don't multiply by 0.8 after you get E=96 KWH then divide by 6 and multiply by 5 You get 80₹ Agar ab bhi dikkat hai to 1 bar lecture dekh lo

[@shrutishukla-11thh28]

Sir 😮 equivalent Resistance figure se nikalne vale question itne easily aapne karva Diya ... Maja hi aagya session dekh Kar 🤩.... Thank you Guru ji ❤️😇✨🙏🏻 52:30 - X : Y = m² : 1 ✳️

[@TinkerBell070605]

i think it's r square:1

[@AdityaSharma-ux3ld]

anybody for 2023 completing syllabus for science

[@Itsanuuu637]

Only one month remaining for boards and still I don't understand this chapter 😑😑😭😭😭

[@i_manish005]

47:50 ANSWER IS 18.8 ohm 😊😊 I HOPE ITS HELP ☺☺🤩

[@osheenchandel2224]

I got 18.6 and thanks i was literally searching whole comment section for this ans 😌..

[@i_manish005]

@@osheenchandel2224 thanks 😊

[@osheenchandel2224]

@@i_manish005 i think i was the one who was supposed to be thankful 😂.... Ok thankyou and welcome at same time 😄

[@happyranjan8383]

2 MINUTE SILENCE FOR THOSE WHO ARE FINDING TIME STAMP🤣🤣🤣🤣

[@8BitGamerYT1]

I was bro....

[@Maithily-2954]

😅😅

[@happyranjan8383]

@@8BitGamerYT1 yes it comes naturally...

[@yashwardhansinghsikarwar7074]

😂

[@achievingdreams8944]

51:16. I am getting the Req as 330/41 ohm which is around 8.04 ohm.. Tell me if I am wrong

[@ishant_SM]

My correct answer is 7.5 ohm

[@seemajain4506]

@@ishant_SM my also 7.5

[@snehayadav7054]

My is 7.2

[@KunalKeshri]

Who r watching in December 😂.....with full concentration 😉 👇......All the best guys..🙃🙂❤

[@psagaming5111]

Search PSA Gaming on KZbin

[@princekumarprasad6333]

.Value of X=Rm , Y=R/m Now X/Y= Rm/R/m = Rm²/R Ratio = m²:1