Electro Magnetics - Poynting Theorem Part 1

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TutorialsPoint

TutorialsPoint

Күн бұрын

Пікірлер: 23
@TutorialsPoint_
@TutorialsPoint_ 10 ай бұрын
Electro Magnetics Theory Course: www.tutorialspoint.com/electromagnetics-theory/index.asp Use coupon ""KZbin12"" to get “FLAT 12%’’ OFF at Checkout.
@tadehmirzakhanian893
@tadehmirzakhanian893 3 жыл бұрын
my EM knowledge is so rusty from undergrad and my MS class is killing me. You're doing an amazing job helping me not to throw myself from the bridges around here LOL thanks bud!
@tomkruise7542
@tomkruise7542 5 жыл бұрын
very good way of teaching.. don't listen negative people SIr...
@nasheelimuniya5147
@nasheelimuniya5147 5 жыл бұрын
This was not disappoynting.
@AnujKumar-sx6ws
@AnujKumar-sx6ws 3 жыл бұрын
Let take two identical positive charges q1 and q2. There are four points (a), (b), (c), (d) . q1 was initially located at point (a), and q2 was at point (d). Distance between (a) to (d) is taken 1 lightsecond. Distance between (b) and (c) is also about 1 lightsecond ( a little less) (a)...(b)................(c)...(d) q1.................................q2 q1is moved from (a) to (b) toward q2, and in a similar way, q2 is moved from (d) to (c) toward q1. Let say they both were pushed for half a second. (For Energy given) Force on q1=Kq1q2/r^2 (For energy output) Force on q2 =Kq1q2/r'^2 When we think about r, we found that it would be somewhere between distance of (a) - (d) and (b) - (d), as the electric field of q2 will be the same there for 1 second. But for r′, it is between (a)-(d) and (b) - (c), so r>r′. Therefore, the force on q2 is greater. Assume that you are q1 and are pushed for 1/2 second over a very short distance. You will find that field of q2 were the same there for that time period as a result of the velocity of the electric field. So, the q2 for q1 was at (d) during push. Thus, q1's average distance from q2 was somewhere between (a) - (d) and (b) - (d). However, for r′ taken for force on q2 for receiving signal was different from r. Here, I am q2 and was moved at the same time, but when your changed electric field reached me after 1 second, I was also moved closer. So, for me, you moved closer, and I also moved a little closer to you, which makes my average distance from q1 less than r. Seems like output energy(signal) was more than input given on q1. Tell me how the velocity still not violating the law of conservation of energy
@allanraju1570
@allanraju1570 5 жыл бұрын
Keep making videos sir , but involve little more descriptive understanding of the topic🙂🙂
@selvakumar-ik3vg
@selvakumar-ik3vg 6 жыл бұрын
@10:25 I think there will be by 2 there
@sohanroy7833
@sohanroy7833 5 жыл бұрын
selva kumar yes
@joshuacole8284
@joshuacole8284 5 жыл бұрын
This video is nothing but...Poynting Theorem.
@karthikpspk6756
@karthikpspk6756 2 жыл бұрын
👏🙌
@vedantshah4230
@vedantshah4230 3 жыл бұрын
Content is good but very slow (even at 2x)
@himanshusingh6223
@himanshusingh6223 5 жыл бұрын
please can somebody tell me whether this way of proving is write or wrong I have proved this way in my exam
@dollymeena4715
@dollymeena4715 5 жыл бұрын
This is wrong way u need to draw diagram first
@PintuKumar-ni6fo
@PintuKumar-ni6fo 5 жыл бұрын
This video is nothing but....🤣🤣🤣🤣help to undrstand better
@BaibhabRoy-i4f
@BaibhabRoy-i4f 10 ай бұрын
can you stop saying "nothing but" before every answer
@d7aconic
@d7aconic 6 жыл бұрын
How the hell is H magnetic field??? B is magnetic field not H
@lakshyakwatra2408
@lakshyakwatra2408 5 жыл бұрын
B is the magnetic induction or magnetic flux density and H is the Magnetic field strength.
@NithinGigi
@NithinGigi 4 жыл бұрын
B is magnetic induction while H is magnetic field intensity
@dawnofred8524
@dawnofred8524 3 жыл бұрын
u just get B by product of H and permittivity of the space
@anirudradabas7546
@anirudradabas7546 5 жыл бұрын
plsss stop saying "its nothing but" .... its so irritating ...
@bibinjohn4035
@bibinjohn4035 4 жыл бұрын
It's his way of teaching
@anirudradabas7546
@anirudradabas7546 4 жыл бұрын
@@bibinjohn4035 yes it is!!😇
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