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@tadehmirzakhanian8933 жыл бұрын
my EM knowledge is so rusty from undergrad and my MS class is killing me. You're doing an amazing job helping me not to throw myself from the bridges around here LOL thanks bud!
@tomkruise75425 жыл бұрын
very good way of teaching.. don't listen negative people SIr...
@nasheelimuniya51475 жыл бұрын
This was not disappoynting.
@AnujKumar-sx6ws3 жыл бұрын
Let take two identical positive charges q1 and q2. There are four points (a), (b), (c), (d) . q1 was initially located at point (a), and q2 was at point (d). Distance between (a) to (d) is taken 1 lightsecond. Distance between (b) and (c) is also about 1 lightsecond ( a little less) (a)...(b)................(c)...(d) q1.................................q2 q1is moved from (a) to (b) toward q2, and in a similar way, q2 is moved from (d) to (c) toward q1. Let say they both were pushed for half a second. (For Energy given) Force on q1=Kq1q2/r^2 (For energy output) Force on q2 =Kq1q2/r'^2 When we think about r, we found that it would be somewhere between distance of (a) - (d) and (b) - (d), as the electric field of q2 will be the same there for 1 second. But for r′, it is between (a)-(d) and (b) - (c), so r>r′. Therefore, the force on q2 is greater. Assume that you are q1 and are pushed for 1/2 second over a very short distance. You will find that field of q2 were the same there for that time period as a result of the velocity of the electric field. So, the q2 for q1 was at (d) during push. Thus, q1's average distance from q2 was somewhere between (a) - (d) and (b) - (d). However, for r′ taken for force on q2 for receiving signal was different from r. Here, I am q2 and was moved at the same time, but when your changed electric field reached me after 1 second, I was also moved closer. So, for me, you moved closer, and I also moved a little closer to you, which makes my average distance from q1 less than r. Seems like output energy(signal) was more than input given on q1. Tell me how the velocity still not violating the law of conservation of energy
@allanraju15705 жыл бұрын
Keep making videos sir , but involve little more descriptive understanding of the topic🙂🙂
@selvakumar-ik3vg6 жыл бұрын
@10:25 I think there will be by 2 there
@sohanroy78335 жыл бұрын
selva kumar yes
@joshuacole82845 жыл бұрын
This video is nothing but...Poynting Theorem.
@karthikpspk67562 жыл бұрын
👏🙌
@vedantshah42303 жыл бұрын
Content is good but very slow (even at 2x)
@himanshusingh62235 жыл бұрын
please can somebody tell me whether this way of proving is write or wrong I have proved this way in my exam
@dollymeena47155 жыл бұрын
This is wrong way u need to draw diagram first
@PintuKumar-ni6fo5 жыл бұрын
This video is nothing but....🤣🤣🤣🤣help to undrstand better
@BaibhabRoy-i4f10 ай бұрын
can you stop saying "nothing but" before every answer
@d7aconic6 жыл бұрын
How the hell is H magnetic field??? B is magnetic field not H
@lakshyakwatra24085 жыл бұрын
B is the magnetic induction or magnetic flux density and H is the Magnetic field strength.
@NithinGigi4 жыл бұрын
B is magnetic induction while H is magnetic field intensity
@dawnofred85243 жыл бұрын
u just get B by product of H and permittivity of the space
@anirudradabas75465 жыл бұрын
plsss stop saying "its nothing but" .... its so irritating ...