Electron contribution of ligands|Electron counting Organometallic compounds|neutral ionic method

[@Harekrishna17-q8l]

Thank you dear..you are such an outstanding mentor i ever met... Be like this..May god bless you with all happiness and sucess in life..

[@ridhi9266]

Hello mam, you are really outstanding..Your methodology of teaching is so impeccable... Feeling lucky to find your channel..i can't afford coaching .. Please keep going like this

[@shahid_palguni1]

Thank you, God will bless you with great success and protect u from all deadly diseases.

[@m.shivani5165]

In the era of online classes you are our Messiah🙌❤

[@mayadellerba2005]

Up until this video, I was shrouded in the darkness of not knowing how to electron count. I can now see the light and you are the sole reason why I do not live in that dark pit any longer. May god bless your soul and your offspring for eternity, I will forever be in your debt and from this moment on my life's purpose is to serve any of your needs. May god bless you, america, and baby jesus. 🏈

[@sushmitapriya9737]

Thank you so much simplification made easy to solve numericals😊

[@9981829178]

Thanku mam.best tarike se explain krti h ap.

[@39-shwetasingh69]

"Jis jis ke man me aaya hai 2 , wou khud ko ek chata lagao".... Hehe it was damn cute... You teach as if our guardian is teaching to us.... So much of love , respect and blessings for u mam.... ❤... Forever grateful ❤

[@jyotibalikai1691]

Mam thanks for your efforts. Plz explain electron donation by the bridging ligands in the complex

[@swatighatage7014]

Thank you so much mam. Simply outstanding teaching

[@snehalmohire3934]

Thank you so much..my the best chemistry teacher...

[@upmamondal7149]

Mam...Kolkata Ka best inrgnc sir k pas tution leta hu...par class me above the head.. flying plan...abhi Pura samajh me aya...keya para raha tha sir...thank u mam

[@asmitamondal4104]

Mam 11th example me ek doubt hai.. neutral method me jab electron count kar rahe hai tab homolytically 4 bonds cleav kar rehe hai to 4 e- Mila... Per ionic method me jab e- count kar rehe hai to heterolytically cleav karenge 4bonds to 8e- milna chahiye na..??

[@146omprakashjoshi4]

Mam in previous video you told for e' s donated by lp sigma bond double bond formal charge equal to zero but in this in examples you take -2 as formal charge in M=CH

[@tarangpatel6446]

Point out this comment mam

[@successkey9041]

U r good teacher mam

[@kusumshibaranjanibohidar5996]

I literally slapped myself and couldn't stop laughing cause I was about to write hepticity 2 in question no. 3😂

[@piyushbhoi2007]

Jbaat❣️❣️

[@sohojpath2509]

I also did same thing Yar 😁

[@varshasharma5133]

Thankuh mam ...mam mujhe 3 ,4,5 question me doubt hai alkene me double bond hai aur alkyne me triple bond aapne bola tha pie bond lone pair sigma bond ke liye formal charge zero hota hai aur 5 me co hai wo neutral ligand hai uska b..formal charge zero hoga..mam plzz reply...

[@bidhankumbhakar7771]

11 month k baad again ye video dekh rha hu , aur 24:52 m fir se bohot hasi aaya . But farq h iss baar m correct tha .

[@mkmahato8351]

Mam please answer me As you told that's e- donate by line pair, double bond , Sigma bond then Formal Charge =0 but in Question no 3,4,5 is not zero why please explain me mam

[@mohilthanki2960]

Because it is directly attached to that bond.

[@himanisharma6742]

@@mohilthanki2960 but jb humne formal charge k questions kiye the usme to 8th question m formal charge 0 liya tha wha bhi to double bond directly attached tha

[@sleepysonnets]

Wha pe M double bond C hai na ki C double bond C

[@chemraza9305]

Awsome Ma'am which book u would suggest for organometallic compounds

[@apurbapal6051]

Thanks a lot 🧡🧡.......It’s very helpful🥰🥰

[@akeedasharma4249]

The examples are very good..keep it up mam

[@somnathpatra7642]

Mam app ka time hoo to ekk vidio bana dijiyee pls stereochemistry of cyclohexne kee oppor mee pls.

[@raziquekhan1421]

Thanks ma'am need this likes teachers.. hindi students..

[@sanskrita4]

Ma'am in the example no. 8, electron contribution from neutral method should also be 2 since CO is a neutral ligand. I think so.

[@xb44shubhambhagat62]

-CO is neutral, in 8 it is-COR

[@chemistryworld999]

Hlw mam ! Mujhe ek confusion h ki -- hepticity to sirf no of donor atoms attached count krte h..toh zeise's salt me.. hepticity to 4 hona chaiye but 2 kyu aate hai??

[@diyakiduniya3871]

Very nice mam n thank you so much

[@jyotibhadre7627]

Nice video mam😊👌

[@djchemistrykajal]

Thnku mam bhutt helpfull rhi mam😁😁😁 mam 11 waala question smjh nii aaya ache se formal chaarge humne -2 ku Kiya mam saare carbon share krre hai toh -4 ku Ni hua ??

[@rahulsain8170]

Mam aapne bta to diya ki sb parrel hote h but mam y sb to hypothetical hota h na to to repulsion to hoga hi jisse ki unkie geometry m gadbad aaye or wo planer tut jaye or benzene ring hi khtam ho jaye??

[@riyasaha392]

Ma'am if e is donated from a double bond then FC is 0 , as u told in previous video ... So in question no.3 , formal charge will be 0 , no! Kindly clear my doubt 🙏🏻

[@miteshpadariya1540]

Ex-5 Agar carbonyl electron contribution me neutral ligand he to F. C. =0 hoga na????

[@Mshiridi]

Thank you mam for this video.. one request for u mam i,e pls make the videos of retrosynthesis, disconnection,protecting groups. u r like not just a teacher can't explain mam for our sake u can do this all.... Thank you so much mam......

[@lordganesha8572]

Ma'am all time my favorite😍😍😍so stunning look ❤❤❤❤both are so cut

[@amitkumarguin6759]

In benzene anion negative charge resides on sp2 hybrid orbital and it is perpendicular to p orbital and does not involve in resonance thats why it is aromatic.

[@ruthviksaipunitha3109]

Thank you much mam.god is always blessing you🌹🌹🌹👏👏👏👍👍👍

[@Aajkafun1]

Mam, Jo 4th question h jisme Carbonyl metal k sath attach h usme formal charge 0 hona chahiye.Kyonki CO neutral ligand h.

[@Panydebiprasad9]

HAN MAM M-CO KA formal charge 0 hoga (CO) is a neutral ligand

[@divyanshachand1840]

Thank you mam. Your lessons are very helpful

[@bitmyrtechnologies1639]

Thank you mam vese bhi electron contribution mein m bhut confuse thi

[@shamsakhan2011]

Mam please make me clear one thing that in metal Carbonyls CO is inorganic but why metal carbonyls are organometalic? Similarly O2 molecule in example 9 is organometalic?

[@ajaykumardogra1899]

Fabulous... Dear... And your dialog *chanta lgaoo😂😂😆...

[@parmarsunil8937]

Mam last in 12 example, agar neutral method se 4e contribute kar rahe hai to ionic method me 6e quie 8e quie nahi ? Aur Fe to charo carbon se attached hai.

[@jagroopsingh9349]

mam if Q will ask in exam so Which one is prefer neutral or ionic However Both gives different electron

[@niteshchawade4128]

Very nice mam

[@vishnubishnoi5463]

Thanku so much for video

[@AggarwalEducation]

In q.no 3 why f. C is not 0 as electrons shared b pi bonds.., in ist video u said f. C will be 0 for double bond

[@e9ib]

22:06 mam aapne btaya conjugation m participate nhi krta toh jb hm aromaticity calculate krte h agr hm vha y example le toh y aromatic nhi hota bu anti aromatic BN jata h ???

[@ashishj9497]

best , to the spot explaining

[@dibyaranjansamantray2647]

Mam ye dono method mai answer to 2 type ka aya hai na to konsa answer thik hai

[@ssgf3963]

Asslam o alaikum maam. Ye organo-transition or organo metalic same subject hota hy kiya?

[@swatisingh.]

Mam please do make video on chapterwise weightage for gate chemistry 2020

[@shaolinaguha1547]

Maam ques 5 mein carbon monoxide is a neutral ligand so it donates by lone pair that's why N=2 but f.c =0 hona chaiye na??? Apne -1 likhaya

[@shaolinaguha1547]

Jyoti Rathi maam plz reply??

[@beehive9103]

11. formal charge sayad 0 hona sahiye kya ma'am.. kyu ki covalent bond hein dono dien hein...????????

[@ntspectra13]

thank you so much ma'am for this video.. I am preparing for entrance solely from your explanations... I have a doubt... in q.11 the electrons are donated from pi-bonds..so shouldn't the formal charge be zero?

[@tannu6751]

Electrons are not donated by pi bonds because in that case, the structure will be antiaromatic and hence unstable. So we first change it to aromatic form by putting negative charges on 2 of the ligands, hence it becomes stable. And then we see the formal charge that will come to be -2

[@pratikshachauhan2976]

Mam formal charge in case of co =0 hoga ????!

[@parthkhanayat420]

Thank you so much ma'am

[@shiladityaroy7611]

Mam in the example 11 ,is the f.c 0 because all the pi bonds are participating for donation like simple alkene..

[@gopalkrishnaniyogi5941]

very good mam.

[@anujkashyap904]

Mam example no. 6 m, ,pie bond metal k anti orbital m e sharing krra h to isse aromaticity pe effect pdega ya nhi

[@leapchemistry9285]

Thanks ma'am for ur videos which are beneficial ever for those students who belongs from village area or small towns. I was one of those student. I suggest another book. Organometallic compounds by Dr Indrajeet Kumar which explains maximum property of the organometallic compound in Lucid manner and very beneficial for Net, Gate and set

[@amnasarfraz2414]

Is book ko download krny ka link send kr do plz

[@ashigoyal5390]

Can u plz explain me qtn 12 its f.c N how it can be +1

[@nidhiborkhatariya6197]

24:50 chaanta lagao 😂 that was epic. Obviously ma'am we are talking about Hepticity not denticity. Maza aa gaya 😂

[@santanupatra3171]

Excellent lecture but phenyl cation or phenyl anion is not correctly explained mam. Both are aromatic since charge is residing at sp2 hybrid orbital which is orthogonal to pure p orbitals resulting localisation of the charge.

[@rohitsanap7502]

Nice explanation mam

[@soniyasingh7290]

Can someone explain me the 10th example it's already aromatic so f.c should be +1?

[@harshitagupta6239]

Mam in example 5 there is carbonyl so formal charge should be zero?

[@Amirfayazbhat193]

Wow amazing...

[@HiteshSaini]

It's helpful or maine sach me chanta mara khud ko coz pahle Mene 2 hi consider Kiya tha hepticity lekn thik Kar diya tha chanta maro bolne se pahle 🤣🤣🤣🤣

[@gaganyadav9]

mam aape bhut achhi h

[@aishakhan9976]

Maam ek request hai aapne organometallic start kiye hai to please please ismai catalyst ,hydroformylation sb kuch padhn please bcoz aapki teaching bhaut bhaut zayda understanding

[@krushangpatel1839]

Hello mam , 5th example me agar C O neutral ligand he to fir uska formal charge 0 hona chahiye na aapne uska f.c . -1 likha hai why ???? Big Question ⁉️

[@pritamde1634]

Mam question 5 may to f.c=0 hoga?? CO to neutral ligand hay....

[@aakashsarpale9996]

Nice one

[@asmarakhilji2336]

Superb mam

[@priyajakhar3122]

Clear...👌👌👌👍👍

[@neelamsingh3110]

Reaction mechanism bhi oMC ki complete krayengi

[@samikshagarg6340]

Plz Ek query solve krdo method do lgarhe h apne ionic and neutral to find electron contribution that's fine but unka answer to alg alg aarha h.. Dono method se electron ka no. To different aarha h to hm konse answer pr tick lgayenge.. Bhut confusion horha h..

[@yadavprabhat2844]

Mam neutal and ionic method me humlog no of electrons on metal count karte hai na.... Then mam 7 example dekhiye na wapas ek baar

[@cheminblack3583]

Mam, 5 q. m carbonyl to neutral ligand h na To uska formal charge 0 hona chahiye. (-1) nhi hoga na??

[@anjaliupasana1037]

Respected friend....From a little knowledge I think that when metals are attached to neutral ligands through coordinate bonds ,then only the formal charge is equal to 0.

[@shwetachandel4029]

@@anjaliupasana1037 thank u... I m very confused about this.. But u solve my prblm

[@chinmayeeswain3933]

Mam.. In question no. 5 why the formal charge is -1not zero.. Though it'a neutral ligand...

[@shrikantpadhy3416]

Same question !

[@chinmayeeswain3933]

Plz answer this ques..

[@sandeepmunnur7315]

it's 0

[@pinakikhan5434]

Thank u mam....as expected lit one 🔥

[@mayadellerba2005]

amen!

[@RoziKhan-w9w]

In the question number 3. Metal is Directly attached to tha double bond ... Why formal charge is -2 ?? It should be 0

[@muskansaher2703]

U r magic...and great

[@Anglemisty358]

Thankyou mam you are very outstanding mam

[@justchemistry757]

Mam in case of carbene why don't we consider one of the bonds as pi bond and co nsider its formal charge as -1

[@ankitazirekar5980]

Mam double bond agar rahe to f.c zero hona chahiye

[@muneerhussaindar]

Thank u very much

[@motivation7050ready]

Thank you ma'am 🙏🙏🙏

[@VinodKumar-hx9vh]

Nice mam

[@kanchanmaurya1285]

Thanks 😊 ma'am 👍😀

[@arihantjain209]

Mind blowing am fan of you pls help me to give notes PDF for net okk jii very amazing

[@Roshan_1045]

At 28:40 CO is neutral ligand so FC should be 0 right ?? as like que. 9

[@babitachaudhary5447]

In 5 example the formal charge of CO should be 0 as it is a neutral ligand n donating lone pair to the metal..pls check once again n correct me if i m wrong.😊😊

[@JChemistry]

Yes it's my mistake, formal charge will be zero. Sorry !

[@babitachaudhary5447]

@@JChemistry it's ok beta...ho jaata hai kabhi kabhi...😊😊

[@meruguakhil5206]

Formal charge of metal attached to double bond is zero u said in previous video but in this video u taken as -2 for 3rd compound

[@shwetachandel4029]

Because I think in 3rd qstn no coordinate bond is formed... Nd FC is 0 only when there is coordinate bond

[@AkashDas-rl5vs]

Thank you ma'am....😊😊😊

[@khushboosaini2785]

I like the way you say, ek chata lagao 😁.

[@ritikakhrb]

Mam app toh bol rhe the ki ansr same aayega neutral aur ionic dono method se... Par in sab ques m toh alag aa rha h

[@krishna047-h5u]

Aise toh electron donating capacity alag alag ayega, exam main Kya likhe??2-2 answer?

[@058khantparthkarshanbhai4]

Hello mam Kya msc chemistry Karne ke bad gate ki exam de sakte hai??

[@parulchoudhary3567]

Mam ,in quest 8th.formal charge is 1 bt u said earlier that carbonyl group has zero formal charge...plz mam clear my douby

[@amitsinghchemistry68]

Yeh bhi btao cluster ke structure kaise identify krte hai