Emitter-Bias Configuration

[@VimalKumar-wm4gg]

Seriously bro.. Great job..😎 I never wrote a review for any video but you deserve it.. 👍

[@Sahib909]

Was stuck in this topics for few days,Thanks man whomsoever u r keep the good work doing✌🏻️😊😊👍🏻

[@venkateshanantapalli4343]

Sir at 10:31 you said two points they are 1)If we make Re value high the power supply voltage should also be me made high. 2)If we made Rb value as low the collector-base junction will become reverse biased. Coloud you plz justify above two points?

[@youtuberbhai4129]

I think If we make Rb value low then Ib will increase because Ib = (Vbb-Vbe)/Rb and due to this Ic will reduce because Ie = Ic + Ib due to which Vc will increase because Vc = Vcc - IcRc {Vc is potential at point at collector terminal} due to which Vbc which is reverse bias voltage across J2 will decrease because Vbc = Vb - Vc i.e reverse bias voltage will become less positive. If anyone thinks this is wrong approach kindly correct me. thanks...

[@himanshu6489]

for(int i=0;i

[@riseabovehate9476]

lmao

[@pushkarsoni8927]

@@jatinthakwani5370 have your basics clear dude//

[@94D33M]

@@jatinthakwani5370 bro your loop will never run

[@Zakaria_122]

while(1) puts("Thanks");

[@ShwetaSingh-xv1lb]

HEY!! dude i am sure it will show SIGSEGV . DON'T MIND !!!

[@shreyagoyal3566]

Thank you so much for this video... It really helped me a lot as i have exams in 7 days... Thanks again..

[@souravsaha9759]

Thank you so much sir.... You have helped a lot to me.....

[@Cybernetic1]

You are amazing sir.. Please let us know who you are. Thankyou for such an amazing content.

[@kamaleshkunwar6368]

Play all these videos in 1.25 speed ..and thank me later .. :)

[@vibhaalur4078]

because he talks somewhat slow

[@harisrashid0773]

I played 1.5x

[@vibhorejain6687]

I am watching it at 2x speed:-)

[@banothpriyanka8782]

Im watching at 2x😂

[@THISISTEMPORARY.]

I play it in 2x 🙃

[@Anonymoose167]

How Ie=Ic in the output loop KVL but this is not the case in the input loop KVL where you used Ie=Ic+Ib

[@adi_reigns3470]

Ib is very small

[@snappywho666]

@@adi_reigns3470 how do you know it is very small?

[@amankumargiri3163]

@@snappywho666 coz of its low doping

[@jatinkhajuria7151]

Ib is measured in micro Amps

[@satya_k]

@@snappywho666 Because most of the electrons that emitter emits is collected by collector and almost no electron goes into the base region that's why base current remains very very low

[@amankumargiri3163]

4:00 how Ie is nearly equal to Ic They are equal in common base configuration As Ic= (alpha)Ib this equation was proved in solving common bases configuration

[@satya_k]

Since the base current is negligible compared to Ic and Ie.

[@santosh-mb5wc]

Then why we dont neglect it in input loop

[@prosaufi3692]

Because can😅😂​@@santosh-mb5wc

[@ericphilip7480]

Man thank you so much, I can skip classes now

[@alterguy4327]

while(1): print('ThankYou Forever')

[@AdityaRaj-gj4dl]

printf hoga na ki print okk

[@instinctrix]

Python mein "print" hi hota hai.

[@mankaransingh2599]

@@AdityaRaj-gj4dl Yeh python 3.x hai chutiye

[@bhushan326]

I always hit like before watching the video.

[@Priyanshu-ko6bc]

Thank u so much ❤ It really helped me a lot.

[@Sarishma-ur2yz]

Thank you so much it easy to learn because of you❤

[@juliocesarmamaniccanihua6561]

What board do you use to write? It's the best electronics I've seen

[@KAARMUKILAN-]

0:43 i think the q point must be Vceq,Icq

[@bilalqasim9930]

best explanation

[@hanishgopi]

Sir if base current decreases there will be less recombination rate ...so if recombination rate decreases there will be more carriers collected at collector region ...so we will have increase in Ic current ...but u said Ic decreases (according to Ic = beta Ib ) which reason should be considered sir....please reply

[@noorulhaquesiddiqui1800]

Lolllllmlmlllllllmlllllllllllllmllpllllmllml

[@niranjangupta3009]

as you explain increase in collector current will increase voltage drop across emitter and this lead to decrease in base current.... but we know Ie=Ic+Ib.... now Collector and emitter current increase but why base current decrease ... please explain it apart from prove by equation ... mean what exactly happens inside

[@bhu1334]

As voltage drop across Re increases there is less voltage across Rb therefor Ib decreases

[@venkatmourya5117]

thank you sir these vedios are helped me a lot

[@venkatmourya5117]

can you upload some more vedios of different subjects related to 3rd year ece

[@UECAshutoshKumar]

Thank you sir ❤️

[@nivethithanive3364]

thank u so much sir these videos r really so helpful for me.....ones again thanks a lot sir for ur help

[@divykiran]

during different bias circuit explanation sometimes Ic = B.Ib sometimes Ic = B. Ic + (B+1) Icbo what are you the conditions and scenarios for the choice?

[@gaurav3794]

Icbo is generally way smaller than Ib. So, we can ignore it if we want.

[@marissasmile7151]

Thank you so much; You are a savior

[@saptarshibarman]

Please sir upload videos about OP-AMP

[@GurwinderSingh-su2sk]

Very helpful 👍

[@kandimallajyothsna5513]

superb lecture

[@nimeshkumartailor1316]

Please provide guidance for Determine Zj, Z0 and Av for an Emitter Bias Circuit(Capacitor is Bypassed)

[@SomsClassRoom]

sir plz upload current mirror circuit. thank you for this video

[@arunlai6658]

Superb

[@sanketpatel2962]

very helpful.. thanks a lot...

[@mohd.rajeen4256]

at 10:27 can someone explain how taking very small resistance Rb will reduce reverse bias at collector-base junction??

[@BADASSBLADE]

due to less resistance Rb the reverse bias voltage(Vc-Vb) decreases as Ib is increasing

[@poojaraval1078]

thank you soooo much sir : ) i thought it is quite difficult to understand

[@doronlola1763]

I think there is a mistake at 2:42, did you not forget to take into account the minus sign before (B+1)(IB)(RE)? otherwise very helpful thank you!

[@sourabhg284]

It's correct. Refer Kirchoff law

[@akashsudhanshu5420]

best for understanding.

[@SOUMYAPRAMANIK-d4i]

If collector current is independent of amplification factor β what is the advantage here ?

[@wheniambored3903]

thank you for just just wonderful and interesting lecture ,sir i have seen in book "introductory electronic devices and circuits " by robert T.paynter ,,he used two supply in emitter bias configuration one is Vcc and other is Vee,,and you have used only one supply which is Vcc,,sir please elaborate?

[@macwaysmayank8070]

It is derived from vcc only . So u can use vcc alone . It's ok u can go for any 1 of the both

[@praveengiri3047]

why collector current is equal to emitter in 2nd case but that is not in 1st ?

[@CM-hn6oc]

Why ie approximately equal to ic ???tell me please

[@satyam1945]

Sir gate questions please a separate 1-2hrs lec at the end of subject , only tell us how to slove, don't slove step by step(saves time plus more questions /concepts will be covered)

[@AlessandroBoggiano]

Can someone, please, explain why (10:17), low RB takes to reduce the CB junction ?

[@syedmuidalkais5756]

Because of low value of RB, voltage drop across RB will be less. Potential VB will be more. Reverse bias voltage, (VC-VB) will be less.

[@santosh-mb5wc]

Plz also tell How Ie=Ic (we neglect ib) in the output loop KVL but this is not the case in the input loop KVL Ie=Ic+Ib ?

[@santosh-mb5wc]

Plz also tell How Ie=Ic (we neglect ib) in the output loop KVL but this is not the case in the input loop KVL Ie=Ic+Ib ?

[@camiemengineer]

Informative video without stupid music- thank you. But please go to 1:00 and you will notice how much clearer yellow text on a black background is ...need I say more?

[@AnshulNIT_A-y1j]

why at 4:07 the Ic is equal to IE ,how can they be taken as equal?

[@PintuKumar-yo8vq]

how (Ie=Ic) in emitter bias configuration

[@satyam1945]

Pintu Kumar yeah might depend upon rb....if we consider Ie=ic+ib from output loop and also see input look so very much some assumption have been taken too....for ic=ie

[@dibakarpaul1999]

Sir u r just grt

[@ahmedghanim9829]

إلي جاي من طرف مستر فواز لايك👍🏻❤ ACT

[@kumarsapan2565]

thank you sir....

[@jasmindersingh4337]

Good Morning Sir, KVL in o/p cct, why Negative IeRe, flow is from -veg to ground. It is opposite to KVL in I/P cct. Please clear our doubt.

[@hritikasharma5713]

Why Ic is equal to Ie

[@rubelhossain6558]

Are we used Ie=Ic for conditions in all biasing system?

[@RajatSU2005]

Yeah as u know that IE = IB + IC And as IB we take it as micro ampere which can be neglected so ie=ic

[@farheenwaqar7880]

why your concepts in this video are so much different than Thomas L. Floyd (Electronic Devices)? why there aren't 2 biasing potentials Vcc and Vee and the base is grounded?

[@dellavincent8300]

Yeah....that's wat I was thinking! Emitter should be biased. Rit?

[@nasrinislamshanta]

What is phase different input and output

[@SamipSrestha]

but wasn't IE = IC ??? why the addition of IB in this case?

[@neminemii6366]

Chutiya hai kya? ie = ic + ib hota he hai gandu

[@Nikhilkumar-ce1ql]

Ramayan khatm ho gya pr ram ka pta nhi hai

[@Scientificeducation785]

thank u so much sir

[@syedtaha157]

Sir while applying kvl to input loop how to take sign in the equation

[@483_saurabhjindal6]

Current k sath chlo and current jaha se exit karta hai usko negative lo

[@jatinthakwani5370]

By taking opp polarities

[@mdmaiunuddinriad1484]

thankk u sir :)

[@ktharunkumar330]

what books do you refer ?

[@rohijulislam7539]

If vcc is negative then what will happen??

[@believer6917]

Right sir

[@vishalkumarverma7034]

Sir please speak loudly😊

[@rj-nj3uk]

You have not explained about stability factor of all the biasing.

[@sampathvinay1376]

Where it wii have -Vcc

[@hihwsjai188]

its not even a loop how did you apply KVL

[@ArnabSaha..]

Isiliaye deko exp BHI galat bansya 2nd exp

[@mominulhaqueyounus5705]

Vcc and ground will be short connection.

[@Cybernetic1]

1 love please.

[@onyxsteve2745]

better

[@SUNDHERPRAMODHMA]

Arey yaar pehle yeh operating point mein (ib,vce) kaisa ayega Kyun ki output current tho y-axis pe hoga na 😡

[@fidowahyu2080]

konkret ni channel

[@pintusah256]

अंग्रेजो के घर से आए हो क्या

[@jccapitly8379]

Can Ic(B+1/B) also be used for the solving of Ic?

[@SaiManogna-d4g]

to find Ic we cannot use Ic