Energy of CT Signals (Solved Problems) | Part 2

[@masonp1599]

hey im a university student and I would be literally hopeless without this series. Much Appreciated.

[@eneskuzuoglu1422]

hi neso academy, me and my roommate are a very huge fan of you. we learnt signals and systems in a last day for our exam u thnk you

[@B_I_N_G_0]

Love to see that you are still liking the comments even after 6 yrs❤

[@AManou19]

nice

[@sairamesh1394]

Sir I have gate 2018 exam after 2 months.because of ur lectures i become strong in electronics. Plz upload zt,Fourier transform,series as early as possible.plz sir plz

[@BhanuPratap-fk3uq]

and also which other subjects you would complete before next year gate

[@manmeetsingh2401]

The second problem as mentioned in your previous lecturers is that the energy is equal to the area under the graph so if we subtract the area of triangle from rectangle we'll get the same answer.

[@ayanhaider5579]

the energy is actually the area under the graph of the signal squared.

[@adityaswaroop1596]

In the second problem if do it by area the answer is 4 joules and if we do it by conventional approach the answer is 32/3. Please tell why both the answers are not the same and which is the correct one

[@pawanraj-vu9wd]

thanks

[@kalyanjana3524]

If we apply area concept to find out the energy then it's giving different results for the second case can any one give the proper reason??

[@kalyanjana3524]

If we squre a linear equations it becomes parabolic equations so we are getting Wrong answer.

[@pavankumar-in1ro]

If you square then it Is parabola 1/3* b*h= 1/3*2*16=32/3

[@adedayosadiqadewale1246]

@@pavankumar-in1ro could you please explain how you come about 1/3? I believe the area of a triangle is 1/2*b*h....

[@srimoyeeghosh4575]

@@kalyanjana3524 But we squared for the first sum

[@hoq7944]

Please can you solve more questions

[@humorouslyrics]

Sir make a video on frequency response

[@BhanuPratap-fk3uq]

by which time you would complete signals and systems

[@JunPrg]

In the right problem, it is not possible to use triangle area formula, right? why?

[@srimoyeeghosh4575]

Did you get the answer?

[@JunPrg]

@@srimoyeeghosh4575 No,

[@sayedrezasadat4881]

Sir, can you please solve this problem without using formula for multiple choice?

[@sushmanaik2228]

Sir, for second problem when I apply area formula iam getting 32 as answer

[@_SyedIqlaqAhmadShah]

i am also wondering this too

[@narendersingam8442]

What is the energy of signal for time scaling??

[@nirdoshkumarnarayan471]

❤❤

[@biomedizintechnik]

2:44 Isn't the area 8? It's 2 width and -4 amplitude So the square² must be 64 not 16 Someone tell me plz

[@siddeshs7893]

area of a triangle = 1/2 * base * height so we get 1/2 * 2 * 4 = 4 so its square is 16

[@backbenchers636]

sir for this 1st problem the amount of area is 24 but energy is 96J.. you said energy us amount of area right??

[@VamsiKrishna-zv1tv]

For Energy we have to Square the Area. (Mod of Signal)Square = Energy. Note :: Sqaure the Signal 1st and Find Area Later then Only U will get Correct answer. eg. Area of 1st cycle 2*16=32 like that 32+32+32=96Joules. If U square the area later u will get wrong answer :: 8+8+8=24 24Square = 576J Wrong Answer. Hope U understand

[@lumenkinga4777]

hey i am just wondering if you could answer my question regarding a signal that looks like this: →2 /| / | →1 | | _____| | ← 2→-3- get the energy of this signal in one period. the pulse width of the combined triangle over a square wave is 3 (amp of square is 1 while amp of triangle is also 1). this is a periodic wave. note : what i have drawn is one period of the signal already. hope you could answer me cause i am really confused.

[@sachinchouhan5508]

How to calculate energy of two non orthogonal exponential signals ...do we calculate energy of two signal saperately and then or we have to solve complete function

[@bradleyheath7277]

I realize I am quite off topic but does anybody know of a good place to stream new tv shows online?

[@gideonjonathan1984]

@Bradley Heath flixportal :D

[@bradleyheath7277]

@Gideon Jonathan Thanks, I went there and it seems like a nice service :D I really appreciate it!

[@gideonjonathan1984]

@Bradley Heath You are welcome :D

[@dibysahu89]

Sir can we able to solve second triangular questions by area under the curve..I solve but getting different ans

[@sunnykhatri9016]

in the 2nd question we have a time dependent function,so if we square that function we will get a parabolic curve.so,we should use conventional method here.

[@yacinetebbi9007]

how do we integrate if there is no graph

[@rahkumar6351]

night good

[@mullaiselvanr7478]

we hurt u.. sorry for that. we are at in serious tight exam scheduled category so far we need urgent completion of each subject as much soon. we requesting u plz at least complete , wt u take in such as power system , network etc

[@pragyanshu518]

Mullaiselvan R tere naukar hai kya yeh neso academy unka jab man kare woh video karenge upload.......koi order nahi de sakta unko

[@MuddasirJahangir22]

Can anyone please tell how did we get T3 (T cube) inside the square?

[@mischievousmisu]

we get t square but after integration it became t cube

[@eresheru6573]

@@mischievousmisu but previous problem in same video, T is not squred & not integrated

[@basheerbasha2752]

Hai sir.can you please tell me how to solve the second graph by area of triangle method by squaring the signal