Engineering Mathematics 10 | Linear Algebra : Eigen Values & Eigen Vector Decoded- Episode 3 | GATE

[@GATEWallahbyPW]

Dear GATE Aspirants, Lecture notes, DPP, Video, and everything related to the class will be provided on the PW App. Inside the PW App, Gate Crash Course and Abhyas Batch for every class are created in the GATE category. There you can enroll in a free batch and access Videos, Notes, and DPPs. 👉PW App link: bit.ly/GATE_PW 🌐 GATE Wallah - ME, CE & XE - kzbin.info/door/Grrw9x3_B_fItUIBMvqAUw 🌐 GATE Wallah - EE, EC & CS - kzbin.info/door/uGWIkiNaWjsCqybgxGuxfg ▶ Our Telegram Page: t.me/gatewallah_official ▶ Telegram Group for Electronics & Communication Engineering : t.me/GWElectroandcom ▶ Telegram Group for Computer Science and Information Technology Engineering : t.me/Gwcomsciandinfo ▶ Telegram Group for Mechanical Engineering : t.me/GATEWallahMechanicalengineering ▶ Telegram Group for Civil Engineering : t.me/GATEWallahCivilEngineering ▶ Missed Call Number for GATE Related Enquiry : 08069458181 ▶ Our Instagram Page : bit.ly/Insta_GATE Dear GATE Aspirants, Any irrelevant/abusive comment will not be tolerated, students doing so will be blocked immediately

[@letsbethechange481]

sir have lot of practical experience

[@RomanReigns-ub4jc]

10 points AX=lemdaX Determinant row change - Form of 4×4 for short cut Option for eigan vector

[@Amhi_shivbhakt]

20:43 elementary transformation should be R2= 2R-R1

[@shreyas.p4129]

or may be r2 - (1/2)r1

[@universeisherestudytime8701]

1:09:04 sir yeh kidhr symmetric matrix h ?

[@ShivamSingh-m7q]

22:58 if we take x2=c then x1= 2c After this a1+a2 comes out to be 1

[@gauravS_07]

Thanks a lot sir.

[@thanosgaming5639]

question 10 mein lamda ka value 1 hoga ...

[@eet_kashyap4103]

Yes lamda=1

[@Reddy1-m4x]

Nahi.....lamda =1 .....pe voh do equal nhi hote..... lamda =16 pe all correct

[@universeisherestudytime8701]

1:07:32 sir isme toh AX=R diya hua hna toh aapne AX=lembda times R ku krdiya solve krte time ?????

[@vishalmishra1807]

nice

[@AbhishekBiharWala_]

Thank you sir ❤️

[@priyanshupraveen6067]

Sir ye civil engg ke liye v h yhh sirf electronic nd communication engg ke liye

[@Pallabipal706]

Q12 main det A=-2 but product of eigen value is not equal to -2 why?

[@Physicslover1729]

1:05:56 sir bridge banane ke lie toh use kr sakte hai linear algebra ka stress calculation me metric analysis me .

[@shubhamkanojiya4834]

Q10 me lembda = 1 ayega sir

[@IQshorts2384]

sahi kha Maine bhi dekhna

[@annapurneshwarikuri1724]

Nahi 16

[@041pranvatsingh7]

HOW @@annapurneshwarikuri1724

[@devanshtanwar28]

Kese​@@annapurneshwarikuri1724

[@shitalprasad6245]

​@@annapurneshwarikuri1724kaise bro??

[@thegamersleague934]

31:18 but when finding 'b' ,using second row doesn't work, only first row works unlike finding 'a'.

[@parthajitbhar7683]

sir, communication ayega ka in crash courses? thora clarify kar dijiye?

[@TonyStark-yj8iy]

Woo Sab thik hai hair ke liyen kya istemal karte hai, aapke jitna Aate Aate vin diesel ban jayenge

[@Megabyte403]

😂😂😂😂 vin nhi Thanos 😅

[@MayankSingh-ky9pz]

Same bro😢😢

[@aardhya1082]

Sir eigen values find karne ke kiye matrix transformation ka use nhi kr sakte ..... Us matrix ko upper triangular ya lower triangular me convert krke...?

[@KS-su6fb]

nahi

[@dipendrakumar7301]

Aardhya nahi

[@thegamersleague934]

i think you can since determinant value doesnt change. He also mentions you can use determinant operations to find lambda. I'm not sure though

[@aardhya1082]

@@thegamersleague934 nhi kr skte ese ans alg aata hai mai kai question me ki hu 🥲

[@livewithwisdom1]

maja aa gaya sir but notes kaha melaga ?

[@malick1003]

Where r dpps and notes available???

[@inferno2927]

sir yeh mock test kahan access krna h ... ya kahan se krr skte h ?

[@shubhamkanojiya4834]

Q6 me b,and d ans hogw

[@souravbhagat1358]

Sir LU Decompsotion bhi baki hai abhi sir linear algebra mai pls isko jaroor karana sir

[@updeshsingh9837]

Sir mere samajme nhi hai aap ek baar phir se btna sir jii

[@SaloniSingh-lj3nr]

😂

[@takshpatel8109]

Thank you so much sir for your help