Long Division Method for Inverse Z Transform: Basics, Method and Example

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Engineering Funda

Engineering Funda

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@EngineeringFunda
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@chandumamilla9146
@chandumamilla9146 5 жыл бұрын
Sir please tell some complex problems in this four methods
@learnersseries1167
@learnersseries1167 3 жыл бұрын
thank you so much sir❤️...you are life saver❤️🎈☘️
@EngineeringFunda
@EngineeringFunda 3 жыл бұрын
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
@kautukraj
@kautukraj 3 жыл бұрын
Thank you for the clear explanation.
@EngineeringFunda
@EngineeringFunda 3 жыл бұрын
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
@abdulwahoodshaikh7501
@abdulwahoodshaikh7501 3 жыл бұрын
Very Good explanation sir 👍
@EngineeringFunda
@EngineeringFunda 3 жыл бұрын
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@MohitDhigan
@MohitDhigan 4 жыл бұрын
Thank you sir
@EngineeringFunda
@EngineeringFunda 4 жыл бұрын
Your positive comments motivates me, Thanks and welcome 🙏
@Wajahat_Murtaza
@Wajahat_Murtaza 3 жыл бұрын
Sir which company Pen do u use for writing..?
@EngineeringFunda
@EngineeringFunda 3 жыл бұрын
Mitshibushi ballpoint pen
@shivangikumari2177
@shivangikumari2177 3 жыл бұрын
Sir z-1 (5/5z-1) y question bta dijiy please sir
@Divyanidubey
@Divyanidubey 3 жыл бұрын
Sir |z|>1 casual kse hoga pls explain
@ADITYAKUMAR-tb4gm
@ADITYAKUMAR-tb4gm 9 ай бұрын
Causal systems are right sided, hence their z-transform would contain terms like 1 + 2z^(-1) + 3z^(-2) + ... etc Hence, to converge a this series, clearly |z| > 1. If |z| < 1, then z^(a large negative number) would tend to infinity and hence H(z) would not converge Hence, this could only be achieved
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