Simplification of Boolean Expression using Boolean Algebra Rules | Important Questions 1

In this video, we are going to discuss some important questions on simplification of boolean expression using rules of boolean algebra.
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#digitalelectronics #booleanalgebra #engineeringtutorial

[@jerrysterling4432]

Started today with no knowledge of solving these expressions. Watched all the videos here to the point I will look at the problem you write, pause the video and solve it just to see that I did it right! Keep up the good work and thank you for these videos!

[@ENGINEERINGTUTORIAL2468]

Thank you for your valuable feedback.

[@BrandtClarentina]

Thank you. The transparency in your teaching is priceless

[@hrishitachatterjee6371]

thank you so much sir bcs of u I got good grades in my digital electronics paper and internal exam and also in 1st semester tysm

[@dineshsingha7519]

Awesome bro I was searching for this n I finally got 🙂

[@toluwanidaniel7841]

I love how comprehensive your videos sir

[@ENGINEERINGTUTORIAL2468]

Thank you for your valuable feedback.

[@roshnisingh6914]

sir I was commerce student but your teaching method make me understand but if you use little bit hindi then it's great. by the way what's your name sir?

[@ushakumari7486]

Tq so much jii... Vaise aapki voice badi pyari h 😁😊

[@ayanalam020]

video starts at 1:40

[@fifid7660]

Why did you put +1 in B'C(A'+1)?

[@nadeesharathnayake89]

Thank you very much

[@bradleydauria5920]

I'm confused why @10:13 you OR A' with 1? Where does the 1 come from? I thought it was going to be B'C(A'), not B'C(A'+1). It would be great if someone could explain this to me please

[@happyted1622]

Because B'C(A') =B'CA' , while B'C(A'+1)=B'CA'+B'C which is the original

[@RvGeral]

Thank you so much!!

[@sairamrangoliart9499]

Nice I have done with it 🎉👍

[@hforhuzi6497]

How x+xy=x? I watched your previous videos but there was no proof for it

[@usmankhalid2292]

It isa boolean algebra rules that x+xy=x Simplification x(1+y)=x x(1)=x. [(1+y)=1] x=x

[@subhajitsd1066]

Bhaiya ye wala please pls 🥺🥺 solve kar dijiye na --> A[B+C(AB+AC) whole bar] whole bar of only (AB+AC)

[@deekyrie8725]

Using Boolean algebraic techniques, simplify the following Boolean expression Y (A+B+C)(A+B)

[@eloquent_boy4065]

A(A+B+C)+B(A+B+C) A+AB+AC+AB+B+BC A+AB+AC+B A+AC+B A+B A OR B 🤔

[@rimshaiqbal1564]

good job bro........

[@nareshabhira8728]

Nice sir

[@NiisExperience]

Just Incase any Atu lv200 student is watching I’m here

[@malithransika3568]

Z =AB + AC + B + BC Z =B( A+C+1) +AC [(A+C+1) = 1] Z = B+AC// This way is also correct, isn't it?

[@jeanabogdon1471]

super helpful

[@bisoyismitanishakar]

Thanks 😊

[@shdkdell]

Thank You Sir :)

[@kaverikanna-dw1rw]

Tq so much sir

[@mujeebafatima8742]

ABC'+ABD' ko solve kr k kia ans aye gah

[@saadatullahkhan7099]

Ya kaha gaya ha b.b bar =0 but ya A D kaha gaya ha

[@Sharma__karan]

Last wale me A ki existence hi khtam uska circuit me koi vajood hi ni 😅

[@shreyanene368]

BC+AC'+AB+BCD give me solution of this please

[@celinetws6922]

Is it coming out to be A +BC ?

[@muthulakshmirengarajan4236]

Sir aapka naam kehe

[@kaverikanna-dw1rw]

I have one doubt 1+x=1.....then 1+x'=?

[@destroyerplayz7465]

is both equal to 1

[@kaverikanna-dw1rw]

Tq sir 👍👏

[@GameGuftuGu]

Ager tum Hindi mai Explain karte to phir Mai Tumse Sikhta

[@Hamzahamza-xf8on]

There is full of confuse

[@hsmughalhsmughal5022]

"It's confusing"