Inverse Laplace Transform

[@marfmag-abo9020]

thank you Eng. cram ang finals na inverse laplace

[@yashdas7772]

Thanks a lot for making videos on these problems and big thanks for solving last problem . keep it up

[@RonelNebresSOE]

Galing mag turo👏

[@AL-wc8oy]

Thanks ! ang dami kong natutunang techniques sa vid na to

[@babarilion3350]

Salamat sa mga vids mo sir wait ko vid mo about sa gears hehe

[@EngineerProfPH]

Yes po..Sa MD po. God bless!

[@muwongeevanspaul9166]

Sir, true it may be all about Algebra but my dear it's not easy to capture as one my hear or see u doing it .... Am taking time to digest the idea but it's really not that easy. Though I believe after proper digestion,it will be swift....thanks for the video,it has helped me much. Real much.

[@kalbs1355]

Thank you! ❣️

[@EngineerProfPH]

Thank you din po!💛

[@colenayson]

hello question lang, yung w po ba sa cos wt formula or w in general, can be a square root or raised to a number? May nakuha kasi kaming e^t cos sqr(7)t and I'm not sure if it's applicable sa situation na yan. Just asking if applicable, di naman yung sagot.

[@syikinmausa6805]

thank you sir 😭😭😭

[@carladrianlarraquel7679]

Big help!

[@marygracemaniaul3226]

May vid po ba kayo for Laplace Transform of Derivatives?

[@EngineerProfPH]

Hi! For this po, wala pa as of now. I will make videos for this in the future. Thank you!❤️

[@allencadavos9711]

sir pano po pag (s+a) yung po mga formula sa 18:15

[@dkraken7454]

Sir yung ex. mo #4 ata yun yung 1/(s^2 +2s) hindi ba pedeng mag add and minus 1 tyo sa denominator para maging perfect square. Then solve for the standard formula? Just asking lang po tnx.

[@carultch]

For 1/(s^2 + 2*s), we can factor out a sole s, which leaves us with: 1/(s*(s + 2)) This means our partial fractions starts with: A/s + B/(s + 2) Both of which we can get with Heaviside cover-up: At s=0, A = 1/(0 + 2) = 1/2 At s=-2, B = 1/(-2) = -1/2 Thus we get: 1/2/s - 1/2/(s + 2) Inverse Laplace: 1/2 - 1/2*e^(-2*t)

[@toughconstruction5044]

Yes po pwede, the answer will be (e^(-t))(sinh(t))

[@airamaealimbuyong1937]

Thank you Engr!

[@hanzjoshuadelatorre7256]

Nung napunta sa parte na "balancing" nawala na ako. Di ko na gets