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epsilon-delta proof ultimate study guide

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bprp calculus basics

bprp calculus basics

Күн бұрын

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@bprpcalculusbasics
@bprpcalculusbasics 11 ай бұрын
New video: Your first and second day in college calculus: kzbin.info/www/bejne/fXvXfn6fqqaUe5Isi=GTBLG_F3moYnhvJq
@annaholm9704
@annaholm9704 Жыл бұрын
Oh my God😃 This guy is a godsend. I'm so glad he made this video! I'm only in calc 1, and because of him, I already know the lectures before they are taught.
@kingbeauregard
@kingbeauregard Жыл бұрын
Can I say a conceptual thing? Imagine you've got your function f(x), and there is a point (a, L) on the function and you want to prove that it's continuous. So, imagine a rectangle centered on (a, L), and it is tall enough that the function never touches the top or bottom edges of the rectangle. Now, can you resize the rectangle down to nothing, without the function touching the top or bottom edge at any resizing? That's what epsilon-delta is trying to do, abstractly rather than visually: the rectangle would be 2*delta wide and 2*epsilon high. So you're just working out the proportions of the rectangles; if you can derive proportions for the rectangles, the function is continuous.
@iteoluwaoladejo4240
@iteoluwaoladejo4240 Жыл бұрын
@@kingbeauregard W concept. I never thought of it that way. Thanks a lot for sharing.
@josefmakili4062
@josefmakili4062 Жыл бұрын
To dopa nena
@IncendiaHL
@IncendiaHL 10 ай бұрын
My mathematical analysis exam coming up, I realized how rusty and inexperienced I am with these. There are plenty of videos explaining the concepts, but that's not the hard part. The hard part is actually getting experience in using them, and this video!!! Is!! Exactly!!! What I wanted!! An incredible teacher just trucking through a boatload of Proofs. Thank you so much!
@batteryjuicy4231
@batteryjuicy4231 10 ай бұрын
this man is an absolute legend. When he learned this stuff, there was no black pen red pen and when he learned it so well to create this channel to teach us bozzos
@leseagleexe6947
@leseagleexe6947 10 ай бұрын
Youre an absolute gem sir
@bprpcalculusbasics
@bprpcalculusbasics 10 ай бұрын
Thanks!!
@omerdogancanbilgili7401
@omerdogancanbilgili7401 Жыл бұрын
bro you literally save my academic career thank you
@wesc6452
@wesc6452 Жыл бұрын
This is very helpful! I am in intro to proofs this semester but also in an analysis class that is graduate level so it has been challenging so far. This really makes things much more understandable - thank you!
@hyde_stopStealingMyUsername
@hyde_stopStealingMyUsername 7 ай бұрын
Thank you so much, at first I didn't understand anything but because of your explanations I was able to solve the last 3 by myself
@antipsikiyatriKizi
@antipsikiyatriKizi 9 ай бұрын
Best video about this topic on KZbin.
@nvapisces7011
@nvapisces7011 Жыл бұрын
It would be great if you could make a video on a guide to prove one sided limits as well as infinite limits and a mix of both. Then make separate videos proving the different limit laws (sum, product, quotient, power, root law)
@rain-uw9ju
@rain-uw9ju Жыл бұрын
isn't epsilon delta the method used to prove all of the different limit laws? I thought it was the basis for limits in general.
@alibinnaseer
@alibinnaseer 2 ай бұрын
thank you soo much!!! I watched sal's video, then yours and then again sal's video and then went to ChatGPT and then came back to this, rewatched it and now i finally understood it !!! May Allah bless you !! 💖💖
@eddiephysics
@eddiephysics Жыл бұрын
Condensed and extremely easy to follow along!
@luciekiss1618
@luciekiss1618 Жыл бұрын
Thank you for your passion ! This video is so helpful. Keep doing what youre doing.
@user-qj3rv2mo1b
@user-qj3rv2mo1b 7 ай бұрын
At the end of each proof u prove it by deducing δ to get ε. It definitely makes sense, And grateful to you for wonderful explanation and so many interesting examples. Now I feel comfortable with proving limits using your GCSC process. However, I have also seen few other proofs, they determine δ like u do and then back track through the key controllable factors to the start, to show |F(x)-L|
@danni4451
@danni4451 Жыл бұрын
God, I learned a lot from this video. Thank you so much! You teached so well. I couldn't even understand how this actually works, and after watching your video it makes me 恍然大悟.😁😁😁😁😁😁
@bprpcalculusbasics
@bprpcalculusbasics Жыл бұрын
Glad to help!! 😃
@user-oh4tf8lj9y
@user-oh4tf8lj9y Жыл бұрын
you are amaizng toutr i hope you are my proffessor instead of my profferssor THANK YOU A LOT
@Sdw_Bld
@Sdw_Bld 7 ай бұрын
How is this guy such a good teacher?!
@del3t3d
@del3t3d Жыл бұрын
Wonderful, exam tomorrow and you simplify things so that they can be easily well understood :)
@bhavishaysharma8648
@bhavishaysharma8648 Жыл бұрын
Okay. This was crazy!!! If you read this, thanks a lot bud :)
@bprpcalculusbasics
@bprpcalculusbasics Жыл бұрын
Thank you!
@kingbeauregard
@kingbeauregard Жыл бұрын
I notice a pretty common practical methodology on each of these, almost a road map for what to do with the math: 1) You start with "f(x) - f(a)"; find some way to mingle those two terms, such that an "x-a" emerges in there somewhere. 2) Separate the "x-a" from the rest of the expression, so you have something like "(x-a)*(other stuff)". That "x-a" will become our delta. 3) Get rid of any instances of "x" that appear in "other stuff".
@user-vr2ny2ff9u
@user-vr2ny2ff9u Жыл бұрын
You are outstanding, thanks you, i understood this !! In my institution no one explained this...
@Akane_Kana
@Akane_Kana 11 ай бұрын
This video explained everything. Love that!
@macdaveshub
@macdaveshub Жыл бұрын
I love your teaching sir 🥰🥰 This is a topic I have been finding soo difficult to understand. But you have elaborated it completely. And I have learnt it. Keep up the good work ✌️🥰
@emmecuh
@emmecuh Жыл бұрын
Great video as always, would love to see some one sided and infinite limit proofs someday.
@leonardobarrera2816
@leonardobarrera2816 Жыл бұрын
Thanks If you don’t want to do the problem that I am solving for x^(x+1)=10 Don’t do it, I will se how I can solve it But thanks about all your videos Loves and prayers from Ecuador
@bprpcalculusbasics
@bprpcalculusbasics Жыл бұрын
I don't think that's doable algebraically. We can use Newton's method, or graphical method. Here's the answer on WFA www.wolframalpha.com/input?i=solve+x%5E%28x%2B1%29%3D10
@leonardobarrera2816
@leonardobarrera2816 Жыл бұрын
@@bprpcalculusbasics Thanks a lot for respond my comment, I don't know, but I would like to go to the event that will be in North California, because I love maths, and also you will be there, and it will be great for all your subcribers that also will be in there, and I would like to subscribe for the event. Thanks a lot for the feedback Remember, you are genious, I would like to be like you, I guess, if the things go in the right way, I will be like you!!! Cheers!! Loves and players from Ecuador!!!!!!!
@SuperYoonHo
@SuperYoonHo Жыл бұрын
@@leonardobarrera2816 u soUnd like sir premath LOL
@leonardobarrera2816
@leonardobarrera2816 Жыл бұрын
@@SuperYoonHo really???? I express like that because I didn’t now how to say like we say in Spanish!! Thanks, I would like to be in the tour mente of north California (Steve send in the channel of blackpenredpen)
@SuperYoonHo
@SuperYoonHo Жыл бұрын
@@leonardobarrera2816 Oooh that's cool! 👍👍
@mecidgaliba2854
@mecidgaliba2854 Жыл бұрын
Thanks a lot for this comprehensive video. I was just wondering if you could make a video about how to write down this proof in exams. I mean not by using arrows or red markers. Thanks in advance!
@ngozikanwachukwu6623
@ngozikanwachukwu6623 Жыл бұрын
honestly, I really don't like the epsilon delta proof at all. But thank you for making it easier and tolerable for me❣
@yakobbeyene8764
@yakobbeyene8764 Жыл бұрын
Thank you for your help! Would you proof this question by using epsilon and delta definition. Limit x approaches 1 ( 5x^5+4x^3+x^2+x+1=12
@SuperYoonHo
@SuperYoonHo Жыл бұрын
Thank you so much!
@ronycb7168
@ronycb7168 2 ай бұрын
21:00 we could just get rid of only the square root like you had shown in another video, I just want to see if this is also correct
@ryanfox6260
@ryanfox6260 11 ай бұрын
I've been exploring a different technique perhaps you can comment on. I would set up the equation 4+e = 6(x+d)+2 and solve for d = e/6. I visualize it as setting one of the bounds on the y-axis equal to the outer bound on the x-axis. In general it's L + e = f(x+d), where you know values of L and x. thoughts?
@stevenstone7101
@stevenstone7101 8 ай бұрын
Can you explain further?
@Music-zx4po
@Music-zx4po Жыл бұрын
Thank you for your work! I could follow your first example, however why exactly may one introduce the epsilon - what exactly permits this step? This is probably like proofing the premises.
@mikesmithyes967
@mikesmithyes967 Жыл бұрын
Do Measure Theory practice problems.
@markobavdek9450
@markobavdek9450 Жыл бұрын
Torture of mind with these letters. Anyway I'll watch this...
@Yt-ff6hn
@Yt-ff6hn Жыл бұрын
Right said ...
@jeloabmelak9783
@jeloabmelak9783 Жыл бұрын
Really helped me save the semister🎉❤
@cyrusdeng0108
@cyrusdeng0108 6 күн бұрын
keywords: Given, Choose, Suppose, Check !
@monsieurlambertz7706
@monsieurlambertz7706 Жыл бұрын
I'm sort of confused. When he says a/b0, it's all fine. But I've been thinking what if a=b? If a=b then a/b = 1 < a, so in this case a must be greater than 1. In other words, can I just assume a/b < a in all cases? Even when |x-a| = sqrt(x) + sqrt(a)?
@sihlec1047
@sihlec1047 10 ай бұрын
24:19 I'am dead... use pi... use 1/e
@kingbeauregard
@kingbeauregard Жыл бұрын
What if we were doing f(x) = e^x? Here's how I think it goes, but I'll show you where I run into trouble: |e^x - e^a| < epsilon e^a*|e^(x-a) - 1| < epsilon |e^(x-a) -1| < epsilon/e^a -epsilon/e^a < e^(x-a) - 1 < epsilon/e^a 1 - epsilon/e^a < e^(x-a) < 1 + epsilon/e^a Next step is to take the ln, which I can do because ln(x) is an increasing function just as e(x) is increasing. In other words, it's not going to flip the sign. BUT -- you can't take the ln of a negative, which means that epsilon must be less than e^a. Right? This is ultimately my question, but I'll continue the arithmetic. ln (1 - epsilon/e^a) < x - a < ln(1 + epsilon/e^a) Now we want to put this back in absolute value form: |x-a| < ln(1 + epsilon/e^a) ... and I took the "plus" term rather than the "minus" term because its magnitude is smaller. Finally, we have: delta = ln(1 + epsilon/e^a) In broad strokes, this holds up: since epsilon is always positive, the ln() is always positive; and when epsilon equals 0, delta also equals 0. But again, the epsilon-delta definition specifies "for ANY epsilon", and I'm only allowing 0 < epsilon < e^a. So, is this an invalid proof, because I'm specifying a maximum epsilon?
@dalek1099
@dalek1099 Жыл бұрын
If mod(e^x-e^a)< epsilon then it is also less than epsilon' where epsilon'> epsilon so the maximum epsilon isn't a problem.
@magnetic_monopole
@magnetic_monopole Жыл бұрын
This helps me a lot!
@kiri0725
@kiri0725 6 ай бұрын
Thank you very much !!!
@heroasik5423
@heroasik5423 10 ай бұрын
in limsqrt(x),x----->4 delta=4epsilon
@user-qy9py4lv9e
@user-qy9py4lv9e 11 ай бұрын
Loved itt!
@ishanschneider9289
@ishanschneider9289 Ай бұрын
absolute legend
@Firefly256
@Firefly256 Жыл бұрын
What should I do if I can’t get the |x-a|? For example, [limit of 2x+1 as x->1] = 3 0 < |x - 1| < delta |2x - 1 - 3| = 2|x - 2| |x - 1| < 1 -1 < x - 1 < 1 -2 < x - 2 < 0 |x - 2| < 2 So I can only get to: 2|x - 2| < 4 I don’t have delta in the above, how should I approach this?
@fretzyjanebares2257
@fretzyjanebares2257 Жыл бұрын
Hello, I think you have incorrectly written I f(x) - L | in your proof. You wrote |2x - 1 - 3| instead of |2x + 1 - 3|. The 3rd line should be |2x + 1- 3| = | 2x -2 | = 2 | x-1 | < 2 * delta. Hence delta is epsilon/2. Hope this helps. 😀
@Firefly256
@Firefly256 Жыл бұрын
@@fretzyjanebares2257 oh right 😅, so does this situation never appear at all for other functions?
@dearlymats428
@dearlymats428 10 ай бұрын
The most humorous lecturer in my life 😅😅😅😅😅😅wow I enjoyed the lecture , best lecture in my life ,you make it easier to understand with jokes # if you want to be adventurous put something like pi or root of 17 got me offf😅😅😅😅😅etc
@waldomonroy452
@waldomonroy452 Жыл бұрын
Right on time
@Drum11craze
@Drum11craze Жыл бұрын
Can you do a video showing a proof of a limit as x goes to infinity? Can't find anything on this subject.
@TazzD83
@TazzD83 Жыл бұрын
lucky that I found you!! 😁Thanks a bunch!
@NWS390
@NWS390 11 ай бұрын
It's grate sir❤
@stewartgarikayi4560
@stewartgarikayi4560 Жыл бұрын
Thank you Professor
@jtlbb2
@jtlbb2 9 ай бұрын
Something doesn’t make sense. Around the 40 minute mark you had (x-2/2x) and you split it up into (x-2)(1/2x). Previously in similar problems you said to ignore the denominator because the numerator was greater than the whole fraction. Why is this different? After all (x-2/2x)< (x-2), so why is this different than problems you did earlier?
@bprpcalculusbasics
@bprpcalculusbasics 9 ай бұрын
Could u please give the exact time stamps?
@jtlbb2
@jtlbb2 9 ай бұрын
Of course. At 16:00 and then 39:09. I’m confused why the approaches are different.
@jtlbb2
@jtlbb2 9 ай бұрын
@@bprpcalculusbasics I think I might’ve figured out why. Is it because in the problem at 39:09, you can’t be sure the denominator is greater than 1? For example, the bottom could be 2x = 2(0.25) making it less than one meaning the fraction is larger than just the numerator. I think I just figured out the difference and didn’t think it through enough before asking.
@bprpcalculusbasics
@bprpcalculusbasics 9 ай бұрын
@@jtlbb2 Yes, exactly! If it was a 2+x on the bottom at 39:09, then we could also ignore the denominator. Also, if you would like to see other examples with x->inf or the limit being inf, this video is more complete: kzbin.info/www/bejne/d5fVn4yJarhrjKcsi=V8rMFSOiXrsenyz6
@jtlbb2
@jtlbb2 9 ай бұрын
@@bprpcalculusbasics thank you. I subscribed because you’re a very good teacher
@kaistrandskov
@kaistrandskov Жыл бұрын
This is a little confusing for me. I prefer to do this: 1. We need to figure out how to choose a delta, when given an epsilon. So start with |F(x)-L| < epsilon, and plug in all the numbers for F(x) and L. This is what we know because we are given an epsilon. 2. Next, figure out how to choose a delta based on epsilon. Now, get this inequality into the form of |x-a| < G(epsilon), where G is some junk involving epsilon that we just solved for. Since our goal is to choose a delta so that |x-a| < delta, we can just choose a delta = G(epsilon). 3. Now go through the proof from the beginning, and choose a delta = the G(epsilon) we found earlier.
@tarundeeparora865
@tarundeeparora865 Жыл бұрын
love you
@alpasamudra3479
@alpasamudra3479 3 ай бұрын
sir please do calculus 3 multvariable case
@evanssmith1327
@evanssmith1327 Жыл бұрын
Man please do you have moment of forces channel??? You are just good
@alexei2985
@alexei2985 Жыл бұрын
At 45:50 you write down 1.7 as if it would technically work, then you suggest to use 1 instead because it is easier. I’m confused why 1.7 would technically work because when I use 1.7, I get a different answer at the end. Why would 1.7 work if it gives us a different answer?
@giana.2381
@giana.2381 11 ай бұрын
The epsilon-delta definition of a limit only requires us to prove that a delta (such that the conditions are satisfied) exists. It doesn't require us to find all delta that satisfies the conditions. It also doesn't require us to prove that the delta is unique. So having a different delta is fine, as long as the conditions are satisfied. Sorry, this might not be useful to you anymore since I'm replying to you a couple of months late. 😅
@creepsow1236
@creepsow1236 Жыл бұрын
I love the shirt
@cunningham.s_law
@cunningham.s_law Жыл бұрын
thanks can you do one where you prove inf and sup of a bunch of sets
@energy-tunes
@energy-tunes Жыл бұрын
by the supremum axiom all finite subsets of real numbers have a supremum. then you can easily prove that they also have infimum given this axiom
@tahastm2522
@tahastm2522 9 ай бұрын
hello thanks for your video can you help me to solve lim(x^1/2+1)x=1 =1?
@heroasik5423
@heroasik5423 10 ай бұрын
graphically study the epsilon delta you will get simple epsilon/delta=f'(a)
@niteshgiri8369
@niteshgiri8369 Жыл бұрын
lim x -> - 2 (x ^ 2 + 3x) = - 2 solve it by delta epsilon definition
@KIYAFey
@KIYAFey Жыл бұрын
what if as x goes to infinitive instead of constant number
@user-bd8gv6po5w
@user-bd8gv6po5w Жыл бұрын
Appreciate that a lot sir
@Paparazzi1e
@Paparazzi1e Жыл бұрын
This is cool 😎
@MicaelSLopes
@MicaelSLopes Жыл бұрын
Nice algebra class
@Professor-Q
@Professor-Q Жыл бұрын
I love you
@velmagiah4310
@velmagiah4310 Жыл бұрын
Amazing
@paulpitters2185
@paulpitters2185 Жыл бұрын
You’re so smart
@thomasjefferson6225
@thomasjefferson6225 Жыл бұрын
Helped me in analysis a lot.
@salvadorsabateromero9707
@salvadorsabateromero9707 3 ай бұрын
21:40
@salvadorsabateromero9707
@salvadorsabateromero9707 3 ай бұрын
13:48
@retro_cody_
@retro_cody_ Жыл бұрын
This is really cool. So it’s basically mathematical manipulation 🤣. Finishing up calc1. I somewhat get the proofs but ofc need some practice and help :)
@energy-tunes
@energy-tunes Жыл бұрын
were you recording this for hours you sound like youre going to pass out in the entire second part
@salvadorsabateromero9707
@salvadorsabateromero9707 3 ай бұрын
32:43
@user-kh6cm1kd6y
@user-kh6cm1kd6y 9 ай бұрын
14:40
@DBD253
@DBD253 Жыл бұрын
Man this shit annoyed the hell of me. Wish this video was out during covid when i was finishing my degree advanced Calc kicked my ass a bit...
@heroasik5423
@heroasik5423 10 ай бұрын
simple epsilon/delta=f'(a)
@rafiqqayumi5957
@rafiqqayumi5957 3 ай бұрын
you are wrong in first suppose part
@salvadorsabateromero9707
@salvadorsabateromero9707 3 ай бұрын
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