#06 Coding Challenge - 1 | Java Tutorial Series | For Beginners | In Tamil | Error Makes Clever

In this video tutorial, you will embark on a coding challenge journey delving into Java, where we present coding problems sourced from the past five videos of our series. Solving these problems will not only reinforce your Java programming skills but also provide a hands-on opportunity to apply concepts learned throughout the series.
The challenge begins with a thorough introduction to obtaining user input in Java, a fundamental aspect of programming essential for dynamic interaction with your programs. We'll explore the intricacies of utilizing the Scanner class to receive input from users, storing the input in variables, and showcasing the retrieved data using the println() method.
Moreover, the video will shed light on the significance of casting in Java and its practical applications. You'll gain insights into the various data types in Java and master the art of converting data from one type to another seamlessly.
As we navigate through the challenge, common pitfalls associated with data type casting will be addressed, equipping you with the skills to effectively manage and troubleshoot errors that may arise.
Whether you're a novice venturing into the world of Java programming or seeking to solidify your understanding of user input acquisition and casting, this video tutorial is tailor-made for you. By the culmination of the challenge, you'll possess a firm grasp of obtaining user input and performing casting in Java, empowering you to tackle coding challenges with confidence in your Java endeavors.
Java in Tamil.
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14:05 Float datatype is also working,by replacing "double" that you put data type in this line

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This video was incredibly helpful! It really helped me practice and strengthen my basic coding skills. Thanks for creating such valuable content

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Q1 prgrm la enakku output varudhu but string print aaga mattingudhu...what happened???

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1. import java.util.Scanner; public class hello{ public static void main(String args[]) { Scanner scan = new Scanner(System.in); System.out.print("enter the name:"); String name = scan.nextLine(); Scanner sca = new Scanner(System.in); System.out.print("enter the age:"); int age = sca.nextInt(); System.out.println("your name is:"+name); System.out.println("your age is:"+age); } }

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We can use scan.next() instead of scan.nextLine() so we can avoid the line scan.nextLine()

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Integer input vangitu string input vanguna error varuthu epdi

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Integer input vanguna apuroom you have to mention- object name . Nextline() And then exexute string okay

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Addrss input line la 'nextLine' nu podama 'next' nu potalum work aaguthu . age input line ku apram scan.nexLine nu kuduka thewa illa.

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double or float ?

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Why + operator is used +name ??

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