19.2c ON17 P41 Q6 Maze of Capacitors | A2 Capacitance | Cambridge A Level Physics

[@ayoo9963]

“You can’t tell me you didn’t see tht coming” pls😂😂

[@paawanjotkaur1901]

You're the best💓

[@tinasheemmanuelchaka9609]

at 14:41 how does the negative charge from the battery on its way to the negative plate of the capacitor capacitor manage to pass through resistor, R without it being dissipated into heat in the resistance of the resistor

[@n.hossain942]

That's because charge can't be dissipated as heat, energy can. Besides, there's no other way for current to flow but through the resistor

[@gonayor992]

Please I need some help for part a(i). If I instead combine the Capacitors in Series, P and Q, I get C/2. Then the combined Capacitor of the two now becomes parallel to Capacitor T. If I add them up I instead get 3C/2 - which is different from the answer. Can someone help explain where I'm wrong?

[@merajnahid9125]

The one you did is for resistance. In capacitance things are opposite to resistance watch the previous video in the playlist to get a clear idea.

[@gonayor992]

@@merajnahid9125 Thanks for the response, mate. 😊 BUT I think I followed the new rule under Capacitors. In the question, Capacitors P and Q are in series, right? When I combine them under the rule of capacitance, I get (C÷2), correct? Now let's name these combined Capacitors "S". Now Capacitor S and T will be parallel, not so? When I combine S and T, I get (3C÷2), ie (C÷2) + C. Or is it a rule that when combining different Capacitors - some in series and others in parallel - we must combine the parallel ones first? 🤔

[@osadumioluwanifemi1373]

@@gonayor992 exactly combining series first makes the answer the opposite. Idg🤔

[@abdullahahmad6697]

@gonayor992 the capacitor Q is in series to both P and T so you need to solve them first before you can find the total series capacitance

[@ew9070]

why cant we combine p and q together first?@@abdullahahmad6697

[@dragonemperor5728]

Well I am still confused like if we consider loop that has battery capacitance Q resistance R than pd across Q is 9 v then resistance R should also have pd across it so isn't it violation of Kirchhoff's second law . Sum of pd across battery= sum of pd across Resistor R and capacitance Q which in this case. Not equal can you explain?

[@wadariah3654]

I think capacitor Q and resistor R are connected in parallel, so you can say Sum of pd across battery = sum of pd across capacitor Q and resistor R = sum of pd across capacitor Q and capacitor P. Hope that makes sense?

[@n.hossain942]

After P has completely discharged, R won't have any p.d across it, as they're in parallel. That's why the sum remains 9V. The capacitor Q doesn't discharge as the negative charge has no way to travel to the positive plate without passing through the battery, therefore it will return to a charging circuit.

[@GeorgeDessa25565]

When the switch is set to Y,why is there no potential difference across the resistor R?

[@ETphysics]

At first while the charges are moving around there will be current though R and hence pd. But eventually after all capacitors have stabilized and charged/discharged, no more current will be flowing through R and hence no pd!

[@Blue-et5du]

THAAANKKKSS!! you are great💞

[@Stella-qz2is]

Hi. Why doesn’t the cap Q discharge to resistor as well ?

[@immadshah2811]

There isn't really a path that you could use to discharge Q through resistor R, keep in mind the charge cannot travel through the capacitors P or T. That's what i'd guess atleast :)

[@n.hossain942]

The capacitor Q doesn't discharge as the negative charge has no way to travel to the positive plate without passing through the battery, therefore it will return to a charging circuit.

[@tahabashir9405]

man this topic is confusing I hope they dont put hard questions for it in M/J 24 students always mess it up

[@SKB05]

inverse why

[@akilkhatri3702]

What does the resistor do to help the 3V capacitor discharge? So if there was just a normal wire it wouldn't have discharged?

[@ETphysics]

the resistor slows down the charge flow. if its just a normal wire and the loop is closed, capacitor will discharge too, but VERY QUICKLY, which can cause your circuit to burn and overheat.

[@akilkhatri3702]

@@ETphysics Thankss

[@mr-bean2306]

So the energy is due to the seperation of charges ,and what the capacitor wants to do is for negative charge to meet the fellow positive charge but they are seperated by a barrier ,and it hurts 🥲 please let them go you cannot trap them .We humans are real threat to life on earth.😔

[@khadijanasir5442]

😂

[@romanaiqbal5328]

TSYM