Evaluate || lim_(𝒙→𝟎)⁡[𝟏/𝒙^𝟐 −𝟏/((𝒔𝒊𝒏)^𝟐 𝒙)] || Differential Calculus ||

[@zemiremukelabai7002]

What do you call that technique where you divide and multiply by x²

[@ayoubmj7732]

How can you slove it without using hoptal's rule or approximation change?

[@fewclgd8497]

Could you make a video solving the same limit but without using l'hopital? I would appreciate it very much, it is a question that I could not solve in my exam

[@rafiyamajeed1102]

thank you

[@MathEConnect]

You're welcome

[@zaifasyd]

Sin 0 is zero right st the end

[@MathEConnect]

For which step u asking.

[@MathEConnect]

If u asking for last step, then, it's a property of limit. That is limit as x tends to 0 into sinx/x =1