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evaluating a double integral using the Jacobian

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bprp calculus basics

bprp calculus basics

Күн бұрын

Calculus tutorial on double integral with Jacobian. This is a highlight from 100 integrals part 2: • 100 integrals (almost ...
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Пікірлер: 23
@Ninja20704
@Ninja20704 Жыл бұрын
I would really appreciate if you did more calculus 3 videos. I just finished high school and want to get a grasp of multivariable calculus and also more differential equation techniques before I start university. Really appreciate your content.
@matts2565
@matts2565 Жыл бұрын
I agree, I felt so lost and alone without (as many) BPRP videos during calc 3 lol
@francompalmieri
@francompalmieri Ай бұрын
@@matts2565 Professor Leonard came in clutch though lmao
@matts2565
@matts2565 Ай бұрын
@francompalmieri yes and no; I love his videos but the whole point of KZbin for me is for when I explicitly *don't have time* to watch through an entire hour+ long lecture
@francompalmieri
@francompalmieri Ай бұрын
@@matts2565 yeah in my case I used his videos as lectures pretty much so I get what you mean, I understood him much better than my professor. bprp helped me massively in my first calculus classes in uni with his million examples of integrals and series though, forever grateful for that haha.
@scottmiller2591
@scottmiller2591 Жыл бұрын
I like to think of such problems like this: 1. You want to know the weight of a piece of rubber the shape of the hatched area on the curve. The rubber sheet weighs f(x,y) unit per area, that is, the areal density. 2. It would be much simpler if the area is transformed to a rectangular area in U,V coordinates. 3. In the process of transforming the shape of the area, the rubber sheet is stretched and/or compressed so the areal density changes; the Jacobian is the new areal density of the rubber sheet once it has been transformed into a rectangle. Then it simply becomes a matter of figuring out how to transform to a rectangle (the substitution of variables), integrate the function using the new areal density from the Jacobian, and figure out the corner coordinates of the rectangle (the new limits).
@larryevans2806
@larryevans2806 Жыл бұрын
Best damn math teacher I ever met and I've been around awhile!!!!
@conanedojawa4538
@conanedojawa4538 Жыл бұрын
The vedio is very good . And I want to know how the Jacobian method works? I need a simple proof for this method
@Ninja20704
@Ninja20704 Жыл бұрын
Heres a video by Dr Trefor Bazett where he gives a explanation on why the jacobian is what it is. kzbin.info/www/bejne/rYapXp-vrryji8U (Skip to 6:44) It was very helpful to me, i hope its helpful to you too
@joansgf7515
@joansgf7515 Жыл бұрын
Note that d(u,v)/d(x,y)=(d(x,y)/d(u,v))^{-1}, so it'd have been easier to compute first d(u,v)/d(x,y), which is -2(y/x)=-2u and then to get d(x,y)/d(u,v) by "flipping" d(u,v)/d(x,y), therefore -1/2u.
@Chrisuan
@Chrisuan Жыл бұрын
Do you have a video on the basics of Jacobian, explaining why this process works?
@othila9902
@othila9902 7 ай бұрын
I can't explain the whole process, but if you notice in the video he talks about "changing rectangles", basically rectangles that do not have the same width. The Jacobian allows you to integrate a rectangular space that's equivalent to the original curved one (like this example). If you notice, the jacobian is pretty similar to the u substitution that you use for integrals of one variable, but in this case it's like u substitutuon for many variables
@waziakbar9991
@waziakbar9991 Жыл бұрын
I’m all for the calc 3 vids 😊
@cesarmoreno987y
@cesarmoreno987y Жыл бұрын
You should do more higher level calc topics!
@chessthejameswei
@chessthejameswei Жыл бұрын
What a coincidence that I just learned this today!
@torok2001kristofaron
@torok2001kristofaron Жыл бұрын
Wonderful derivation. 🙌
@wileyst.germain7374
@wileyst.germain7374 Жыл бұрын
Would be much easier to do difference of integrals for each interval between intersections?
@ShanBojack
@ShanBojack Жыл бұрын
I am wondering more about how did you get the first four relations between X and Y
@louiejohncastillo9822
@louiejohncastillo9822 Жыл бұрын
the answer in wolfram alpha is (ln 2)/2+ln 16 = 3.119
@d.h.y
@d.h.y Жыл бұрын
This was such a wonderful video !!! ,,,and could somebody elaborate why the Jacobian determinant in 6:54 has to be an absolute value?? 🙀🙀
@d.h.y
@d.h.y Жыл бұрын
@@joansgf7515 Thank you for the link! I will check it !!!
@Bruh-bk6yo
@Bruh-bk6yo Жыл бұрын
man😱
@Zeke-_-Geekin
@Zeke-_-Geekin Жыл бұрын
Hey, im a high school student trying to learn about calculus, could you tag me in your introductory video for Calculus/Pre Calc
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