Evaluating Limits by Rationalizing | Calculus 1

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Wrath of Math

Wrath of Math

Күн бұрын

Пікірлер: 18
@WrathofMath
@WrathofMath Жыл бұрын
Help support this course by joining Wrath of Math as a Channel Member to get exclusive videos, lecture notes, music, and more! kzbin.info/door/yEKvaxi8mt9FMc62MHcliwjoin Calculus 1 Exercises playlist: kzbin.info/aero/PLztBpqftvzxUEqGGgvL3EuIQUNcAdmVhx Calculus 1 playlist: kzbin.info/aero/PLztBpqftvzxWVDpl8oaz_Co6CW50KtGJy
@jan-willemreens9010
@jan-willemreens9010 2 жыл бұрын
...Good day to you, Thank you for your clear presentation. After watching I want to share with you an alternative way to solve the same two indeterminate limits: 1) For your limit: lim(x-->0)((sqrt(x+1) - 1)/x) I first start by rewriting the denominator x as follows: x = (x + 1) - 1, then I treat this expression as a difference of squares: x = (x + 1) - 1 = (sqrt(x + 1) - 1)(sqrt(x + 1) + 1), and finally after replacing the denominator x in your original limit by this last factored expression, we can cancel the common factors of top and bottom, resulting in the solvable limit: lim(x-->0)(1/(sqrt(x+1) + 1)) = 1/2, and 2) For lim(x-->3)((sqrt(x+1) - 2)/(x - 3)), first rewrite the denominator x - 3 as follows: x - 3 = (x + 1) - 4, again think of difference of squares = (sqrt(x+1) - 2)(sqrt(x+1) +2), resulting after cancelling common factors of top and bottom in the following solvable limit: lim(x-->3)(1/(sqrt(x+1) + 2)) = 1/(2 + 2) = 1/4; the same outcome! I hope you appreciate this way of solving too. Finally, this was my Wrath ON Math (lol)... Thank you for your math efforts, and take care, Jan-W
@Ixzumix
@Ixzumix 4 ай бұрын
Thank you good sir, you helped me tremendously, I appreciate your existence. Don't stop.
@WrathofMath
@WrathofMath 4 ай бұрын
I'm glad to help - thank you for watching!
@infectedswarm3078
@infectedswarm3078 2 жыл бұрын
thank you so much for this wonderful video.. You nicely explained the concept..and plz post more videos about calculus.
@WrathofMath
@WrathofMath 2 жыл бұрын
Thank you! Any specific requests for what calculus videos you want to see next?
@evelynnjoroge3859
@evelynnjoroge3859 3 ай бұрын
Really helpful
@kakuluandrew-nq1vk
@kakuluandrew-nq1vk 4 ай бұрын
hi, hw can i come up with a conclusion of how rationalisation helps in solving limits
@RachaelAnike
@RachaelAnike 7 ай бұрын
Please when do we know if we're to rationalize the numerator or denominator....and hoe do we know when to use the differentiation method or rationalization method in an equation?
@RuthChikapa-bk8yn
@RuthChikapa-bk8yn 10 ай бұрын
Thanks sir🥺✨
@WrathofMath
@WrathofMath 10 ай бұрын
Most welcome!
@AAT-s2p
@AAT-s2p 4 ай бұрын
Thanks👍🏻
@WrathofMath
@WrathofMath 4 ай бұрын
Glad to help, thanks for watching!
@ftbex9224
@ftbex9224 2 жыл бұрын
nice.Thanks!
@JosephMutua-tv7bs
@JosephMutua-tv7bs Жыл бұрын
Understood 👍
@punditgi
@punditgi 2 жыл бұрын
I thought real square roots had both a positive and a negative solution. Why ignore the negative root?
@itzz_just_me2984
@itzz_just_me2984 8 ай бұрын
because its an equation not an expression, you write it as is, not with a plus/minus
@VinayakTupkari-je3wn
@VinayakTupkari-je3wn 9 ай бұрын
Kon kon hindi samjata hai 😂😂😂😂
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