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@jan-willemreens90102 жыл бұрын
...Good day to you, Thank you for your clear presentation. After watching I want to share with you an alternative way to solve the same two indeterminate limits: 1) For your limit: lim(x-->0)((sqrt(x+1) - 1)/x) I first start by rewriting the denominator x as follows: x = (x + 1) - 1, then I treat this expression as a difference of squares: x = (x + 1) - 1 = (sqrt(x + 1) - 1)(sqrt(x + 1) + 1), and finally after replacing the denominator x in your original limit by this last factored expression, we can cancel the common factors of top and bottom, resulting in the solvable limit: lim(x-->0)(1/(sqrt(x+1) + 1)) = 1/2, and 2) For lim(x-->3)((sqrt(x+1) - 2)/(x - 3)), first rewrite the denominator x - 3 as follows: x - 3 = (x + 1) - 4, again think of difference of squares = (sqrt(x+1) - 2)(sqrt(x+1) +2), resulting after cancelling common factors of top and bottom in the following solvable limit: lim(x-->3)(1/(sqrt(x+1) + 2)) = 1/(2 + 2) = 1/4; the same outcome! I hope you appreciate this way of solving too. Finally, this was my Wrath ON Math (lol)... Thank you for your math efforts, and take care, Jan-W
@Ixzumix4 ай бұрын
Thank you good sir, you helped me tremendously, I appreciate your existence. Don't stop.
@WrathofMath4 ай бұрын
I'm glad to help - thank you for watching!
@infectedswarm30782 жыл бұрын
thank you so much for this wonderful video.. You nicely explained the concept..and plz post more videos about calculus.
@WrathofMath2 жыл бұрын
Thank you! Any specific requests for what calculus videos you want to see next?
@evelynnjoroge38593 ай бұрын
Really helpful
@kakuluandrew-nq1vk4 ай бұрын
hi, hw can i come up with a conclusion of how rationalisation helps in solving limits
@RachaelAnike7 ай бұрын
Please when do we know if we're to rationalize the numerator or denominator....and hoe do we know when to use the differentiation method or rationalization method in an equation?
@RuthChikapa-bk8yn10 ай бұрын
Thanks sir🥺✨
@WrathofMath10 ай бұрын
Most welcome!
@AAT-s2p4 ай бұрын
Thanks👍🏻
@WrathofMath4 ай бұрын
Glad to help, thanks for watching!
@ftbex92242 жыл бұрын
nice.Thanks!
@JosephMutua-tv7bs Жыл бұрын
Understood 👍
@punditgi2 жыл бұрын
I thought real square roots had both a positive and a negative solution. Why ignore the negative root?
@itzz_just_me29848 ай бұрын
because its an equation not an expression, you write it as is, not with a plus/minus