Evaluating Limits Using Conjugate Expression

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[@aliscais6033]

Better to make replacement first: replace x^1/6 with a, you will have: (a^3 - 8)/(a^2 - 4), limit: a -> 2. Then all further calculations will be much simpler and clearer.

[@herbertjones144]

This is terrific work

[@jim2376]

L'Hopital's is much easier. (3 x (x^(2/3))/(2 x √x)