Even and Odd Decomposition of a Signal

[@getsetdesign3333]

thank you adam, you are the best teacher. i had given up on this subject until i saw this video

[@AdamPanagos]

Don't give up, this entire area of information is very fascinating. Once you start figuring things out it's a lot of fun. Glad to help.

[@ibrahimh.2828]

Stumbling across your channel just saved my semester. Thank you!

[@AdamPanagos]

Thanks for the kind words! If you found the video useful make sure to check out my website adampanagos.org where I have a lot of other resources available and consider supporting development of new videos through www.patreon.com/agpanagos. Thanks! Adam

[@vaikh8450]

Thanks sir, glad to see a teacher like you . Doing a group work .

[@AbhishekKumar-wm6nn]

A very good explanation for a complex problem

[@AdamPanagos]

Glad I could help, thanks for watching. Make sure to check out my website adampanagos.org for additional content (540+ videos) you might find helpful. Thanks, Adam

[@Diaryofaninja]

Thank you sir. You're a valuable educator. I don't know how the kids before me grew up reading from textbooks, I understand much better with pictures and a "one-on-one" feel like these youtube videos provide that textbooks can't provide. I pretty much owe all my academic success to youtube haha.

[@AdamPanagos]

Thanks for the kind words. Glad I could help!

[@ruibarbosa24]

came looking for copper, and struck gold

[@AdamPanagos]

Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam

[@360xi]

I love your video!!!! Thank you for breaking everything down step by step!!!!

[@jazminmosqueda8263]

thank you!!!! it's totally clicked just now!

[@AdamPanagos]

Glad to hear that; thanks for watching!

[@leolorenzo52raylewis]

your step process was clear and simple thank you!!

[@Footballistaas]

Props to u man, it takes so much determination and effort to make these videos.!!

[@mohammedirfanuddin4274]

Thanks alot, I was learning Fourier series representation , but i was so confused about even and odd compunent, as in terms of even bn=0 and in terms of odd an=0, Your video did clear my confusion for even and odd signel.Thank you so much.

[@AdamPanagos]

You're welcome, glad I could help. Thanks for watching!

[@mohammedirfanuddin4274]

@@AdamPanagos my pleasure

[@sriranganayakulugadey202]

Thanks Adam sir best explanation that was from you

[@AdamPanagos]

Thanks for the kind words! If you found the video useful make sure to check out my website (adampanagos.org) where I have a ton of other resources available and it's easier to watch my videos in a more organized fashion. Thanks, Adam.

[@TheWweweeklyshow]

I did not understand how you added the signals, also did not understand how you subtracted them, you did not really explain what you were doing well.

[@AdamPanagos]

+nabil samy I'm sorry you weren't able to follow the descriptions provided. Practically the entire video is dedicated to explaining how to add/subtract the two signals on a per-time-interval basis. I don't know any other way to explain addition/subtraction in a more detailed manner.

[@TheWweweeklyshow]

It's OK, I'm just frustrated because I can't seem to understand anything today, but your lectures really are very helpful thank you!

[@AdamPanagos]

+nabil samy Maybe it would be easier to think of it terms of equations instead of the pictures I drew. If we have xe(t) = 0.5*(x(t) + x(-t)) we can compute the signal xe(t) one point at a time. For example, let t = -0.5. Then we have xe(-0.5) = 0.5*(x(-0.5) + x(0.5)) = 0.5*(1 + 0.5) =0.5*1.5 = 0.75. The values of x(-0.5) = 1 and x(0.5) = 0.5 I got by just looking at their plots. See how this value of xe(-0.5) = 0.75 is what we have in the plot for xe(t)? You could repeat similar computations for any value of t you wish (e.g. t = -1.5, 0, 0.25, etc.). Once you do this a few times maybe that will help things "click".

[@samgbtembo]

You just earned s subscriber

[@mohsenssalem9661]

Hi Adam I am really interested in this video and it is very helpful. May I ask you a question? I am confused. How did you draw the signal and divided by 2 I don't understand it? Thank you.

[@lpjtechno4612]

did you get an answer? I am also a bit lost

[@zahirshah8748]

Sir i want to ask that from which book u took this example ,plz must reply

[@varunsingh9432]

please explain how to decrease this rectangle and triangle from 1 to 0 ,i am little confuse here in order to get after dividing from 2

[@swarupsarangi734]

very well explained ! thanks

[@AdamPanagos]

Thanks!

[@hycesar]

Hi there, when we have a imaginary part, like e^ix? Have we two decompositions for each part (Real and Imaginary)?

[@pkboy546]

adding the ramp to the rectangle is a bit confusing. can't complain though this is a thousand times better than my book...

[@AdamPanagos]

Just try to picture the rectangle being "boosted" by the rectangle. Just shift everything up by the height of the rectangle. Just takes some practice......

[@pkboy546]

yeah it took me a while but i think i see it now. thank you!

[@Taucioks]

thank you

[@AdamPanagos]

You're very welcome, thanks for watching. Make sure to check out my website adampanagos.org for additional content (435+ videos) you might find helpful. Thanks, Adam.

[@zak11elevenstudentaccount80]

i love you man, just save my a$$ with this video

[@ahmedbadia1485]

Great Video, much thanks!

[@oshin7132]

THANK YOU

[@Kerozen911]

Excellent video :)

[@AdamPanagos]

Thanks!

[@kaursingh637]

excellent -excellent

[@AdamPanagos]

Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content you might find helpful. Thanks much, Adam

[@thegreatworld5460]

Great 👍

[@shubhampatil.6861]

Thanks

[@AdamPanagos]

You're welcome, thanks for watching.

[@nurhassen8191]

thank you!

[@AdamPanagos]

You’re welcome, thanks for watching. If you found the video useful make sure to check out my website adampanagos.org where I have a variety of other resources available that you might find helpful. Thanks, Adam.

[@md.muhibullahshah646]

bangali?

[@divakarkeshri1212]

NICE

[@telugubudds1975]

gud lectures ever seen

[@OmarChida]

Thanks

[@souravuh4965]

very nice :)

[@AdamPanagos]

Thanks!