In one-one case, a^r = a^s it doesn't imply that r=s...The counter eg is e € G where G is a Group, e³=e² but 2 is not equal to 3
@UbaidMasud7 ай бұрын
Last lec m hm ny G ko Z ki isomorphic prove krwna tha mapping jo define hoe us m domain G and range Z the yhe bhi hm ny G ko isomorphic to Zn prove krwna ha to mapping m domain G or range Zn q nai
@CPMathsWorld7 ай бұрын
The fact that under zn ,we cant guarantee injective as we dont know the value of two numbers r and s under mod n.