Chemistry Electrochemistry part 8 (Measure Electrode Potential of half cell) CBSE class 12 XII

[@VamsiKrishna-qq6xe]

EVEN THANK YOU IS NOT ENOUGH FOR YOUR EFFORTS.......... GOD BLESS YOU FOR MAKING CHILDREN'S CONCEPTS CRYSTAL CLEAR AND FINALLY NO MORE FEAR FROM EXAMS!!!!!!!

[@barryallen6385]

Mera lowda

[@deepthireddyvasi2075]

electrochemistry is one of the cumbersome artefacts in chemistry to deal with! but these videos really are of great aid.

[@avyudecentdevil]

Thanks

[@VamsiKrishna-qq6xe]

modepally deepthi yes of course these videos are really helpful

[@krishnatri6237]

Thank u you helped me remember the right concept 🙏🙏🙏🙏

[@vondhanaramesh4365]

best channel ever.. keep it up😀😄🤗

[@myhomecountryindia5618]

should we learn SEP @ 298K tabulation ?

[@krishnagoel3629]

Why salt bridge is not required in H2-Cu electrochemical cell??

[@sundaranarasimhan58]

superb excellent efforts

[@santoshparab3407]

NO MORE FEAR FROM EXAM!

[@70venkatesh77]

is it necessary to remember the values?

[@Srimathi.20]

Yes ofcourse

[@Srimathi.20]

Atleast few values which we use regularly

[@hc8451]

How come there is no salt bridge in the first part where you are explaining the potential versus Standard Hydrogen Potential. Is that correct?

[@VamsiKrishna-qq6xe]

Hans C yes it is correct as there is no need of salt bridge in that case

[@dhirendra31]

how we have got .34

[@peterlohnes1]

There are redox tables for all reductions: in aqueous solution, in acidic and in base www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm hyperphysics.phy-astr.gsu.edu/hbase/tables/electpot.html

[@payaldadhich8263]

thanku so much sir.........finallly doubt cleared.........:-)

[@UnprivilegedDelhi]

SHE is always taken at anode(left) side???

[@ritvikbhatia99]

+sagar pawar not compulsory .. can be taken at cathode .. result won't change 0-(-E) =E E-0=E

[@navneetgkp]

sagar pawar nice comments

[@aryansingh-ob2jd]

sagar pawar no

[@mehbubahmed7973]

why salt bridge is not required in H2-Cu electrochemical cell

[@ashishsharma8756]

thank you so much