Nicely explained. I use your videos to relearn my lost knowledge. Thanks for taking the time to make them. Best wishes from Norway.
@sambenyaakov16 күн бұрын
👍and returned wishes from Israel.
@ats8911718 күн бұрын
Another excellent tutorial on the inner working of transformers.
@sambenyaakov16 күн бұрын
Thanks for the kind comment.
@tamaseduard514518 күн бұрын
👍🙏❤️
@sambenyaakov18 күн бұрын
Numero Uno😊
@ebarbie501617 күн бұрын
I think you accidentally drawn a reversed second winding direction in the first schematic of the video.
@sambenyaakov16 күн бұрын
Thanks for pointing this out.
@constantinemihailov421818 күн бұрын
⭐⭐⭐⭐⭐
@sambenyaakov16 күн бұрын
👍😊🙏
@electrowizard200018 күн бұрын
Prof, could you take a look at a question someone asked on the riddle, about open circuiting one leg of the parallel MMF situation? This video cleared up a lot, thank you again, but that situation remains unintuitive to me. Based on another comment about parallel MMFs reflecting to input in series, one open circuit must stop current in all branches. I now think it must relate to 9:20 here about the pure inductor case, that only Lm would have current and none flows in the loads.
@sambenyaakov16 күн бұрын
I thought I have answered it. If one leg is shorted flux will not enter it due to Lenz's Law. So now there is a 1:1 transformer.
@electrowizard200015 күн бұрын
@sambenyaakov sorry the modified question was if we *open* one of the three legs, not your original question if it was shorted.
@sambenyaakov14 күн бұрын
@@electrowizard2000 Flux will not enter practically into the loaded winding and will be diverted to the leg with the open winding. So you end up with an inductor from input side, practically no output voltage at the loaded winding and the voltage of the open winding is now like a 1:1 transformer , in this case 10V.