Example of Link Power Budget Analysis of Optical Fiber Communication System by Engineering Funda

[@EngineeringFunda]

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[@MuslimAmmayi]

It's amazing 🤩 sir... Tomorrow I have semister exam on optical communication subject today I'm learning from your channel thank you so much sir for sharing 🤗🤗🤗

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@301sivakumar4]

Superb sir.... Nice explaination 👌👌👍👍

[@aditishah4220]

Very helpful video sir

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@sukhadavelankar7404]

Ps = -10dBm , Pr=-46dBm Pt=Ps-Pr =( -10 ) - (- 46) =36dB..........(when you are subtracting powers in dBm the resultant answer is in dB)

[@VKCreation1]

How to get value of ps

[@yakagegura1467]

clear nice

[@EngineeringFunda]

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[@ashishgupta5491]

Awsom.... explaination....

[@mohamedafkar7848]

Useful

[@EngineeringFunda]

Your welcome 🙏

[@sahilshirke3948]

@@EngineeringFunda system margin and safety margin both are same or different?

[@drivesim2678]

Nice

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@kiranbabu2211]

good class

[@shyamsundard5824]

Sir is this also known as loss margin calculation

[@funny-dh3fw]

Please drop the video in the form of .Pdf on the descriptions

[@rafunongrum7085]

Hi! I wanted to ask... What would be different if this was for a WDM system?like would the losses be multiplied into the number of channels?? Or not

[@Rin-xy4tt]

Very helpful video, but your labeling made it a bit difficult to understand at the start.

[@anirudhjadhav7688]

Connector loss is only at reciever so it should be 1.5 itself

[@payalchaudhary__]

Components are chosen for a digital optical fiber link of overall length 7 km and operating at a 20 Mbit/s using an RZ code. It is decided that an LED emitting at 0.85 µm with graded index fiber to a p-i-n photodiode is a suitable choice for the system components, giving no dispersion equalization penalty. An LED which is capable of launching an average of 100 W of optical power [including connector loss into a 50 urn core diameter graded index fiber is chosen]. The proposed fiber cable has an attenuation of 2.6 dB/km and requires splicing every km with a loss of 0.5 dB per splice. There is also a connector loss at the receiver of 1.5 dB. The receiver requires mean incident optical power of-41 dBm in order to give the necessary BER of 10-10, and it is predicted that a safety margin of 6 dB will be required. Write down the optical power budget for the system and hence determine its viability.

[@payalchaudhary__]

Please solve it for us

[@takawiradzoro2237]

The conversion of Tx power from mW to dB is not accurate. In optical communication systems, power levels are usually an absolute unit measured relative to 1 milliwatt (mW). So we can just use Ps = -10dBm and Pr = - 46dBm to get same answer but in this case it makes sense in the real-world context in which the calculation is applied.

[@sarthaksoni3712]

for Pr why did you minus 30 to convert from Db/Km to Db

[@EngineeringFunda]

It is dBm to dB conversation

[@indraprakash2393]

@@EngineeringFunda it should be dBw not dB because dBm is the unit of power while dB is the ratio, dBw is unit of power.

[@akshaychandrarox]

7:47 attenuation loss is 2L so it must be 2*25=50db right? Please correct it

[@vinayakrpatel5029]

That's alpha*L not 2*L

[@yeswanthyadala5313]

@@vinayakrpatel5029 yes

[@MuslimAmmayi]

It's not 2 It's alpha Alpha value 2.5 Length L value 10 Soo 2.5* 10 then it will be 25

[@AbhishekSingh-fc8xn]

The connector is only at receiver end it mentioned so connector loss is only 1.5

[@fernandoarielfretesaraujo9932]

dB is a adimensional unit, dBm is unit referred to 1 mW.... You can´t change that unit to other... your dB is dBW no dB

[@asheerali2376]

👍

[@adarshmadhusoodanan2927]

sir please try to reduce the surrounding sound noise in your videos...

[@MrShaneemibnshereef]

i have a doubt. how the dBm is converted in to dB? i think the way used here is wrong. we can convert dBW to dBm using this formula P(dBW) = P(dBm) - 30 (The power in dBW (P(dBW)) is equal to 10 raised by the power in dBm (P(dBm)) divided by 10 )

[@EngineeringFunda]

What you are saying is false

[@serBarcla]

@@EngineeringFunda wow.

[@serBarcla]

you are right.

[@gireeshkumarkancharla4176]

@@EngineeringFunda sir please explain how you have converted dBm to dB

[@rafunongrum7085]

Someone plz tell me how would the calculation be different if this was a WDM system??

[@uzmagul9462]

How you convert dBm to dB??

[@EngineeringFunda]

dBm is decible of mili. dBm = -30 dB

[@uzmagul9462]

@@EngineeringFunda and please confirm me that losses if are in dm/km we should convert it to dB just or solve it in dB/km