These are amazing and the professors voice is relaxing to me for some reason haha, much easier to understand than my professors
@filchaneco5062 жыл бұрын
to find the IbB. you could just use the same way like you did in IaA.
@abromchris76705 жыл бұрын
Sir ,in 16:15,there are two unknown values ,one is zita ,the other is V sub m (Some Maximum value ,but I don't know why it called Vm instead of anohter variable cuz Vm had been used in another chapter , in AC signal(Peak Value))
@sohamkhisa18316 жыл бұрын
Sir, how will you solve these last three equations? I mean these are unsolvable, no valid result comes out of this. Your are not going to get any of these three unknown currents through these equations.
@HaiderAli-nm1oh6 жыл бұрын
so true
@sa0o9235 жыл бұрын
Actually there are 2 unknowns. Theta and Vm Currents inside delta are shifted 120. They aren't entirely unknown. You just need to solve for Vm and theta
@danielgmilne62806 жыл бұрын
At about 7:40, did you divide by 3 because there are 3 “loads” or it that just general?
@BalkanManic6 жыл бұрын
He's finding the parallel equivalent of the 3, I believe.
@malganis38476 жыл бұрын
Late reply , it's because all three sides have equal values .. so as long as that's the case , you can apply the formula that he used
@Quran_memorization6 жыл бұрын
when u want to turn delta load into star load u should divide by 3
@markmeii21094 жыл бұрын
you should still use the standard formula for transforming delta to wye, it's just that the load is balanced so you can apply dividing it by 3