Thanks dude...Was stucked in derivation of refraction due to spherical surfaces where this was used. Thanks again buddy...You saved my day🌷💯💯
@DdoubleB033 ай бұрын
Very interesting proof. Thank you!
@qimingtian4 ай бұрын
Thank you so much!!!! such a great video
@sohamroy4742 жыл бұрын
I totally understood the proofs. But when I am actually trying 'em on the calculator, I am not able to verify. For example, if I google tan3, it says -0.14... which is not even close to 3. What exactly am I doing/understanding wrong?
@aidantransitus95852 жыл бұрын
This is only true for small angles, 3 radians is not that small of an angle (around 172 degrees). Generally if x
@Prathum012 жыл бұрын
up to which angle can each of these be used pls help
@Anjalikumari-ex2db4 жыл бұрын
Thank you sooo much .
@ExamSolutions_Maths4 жыл бұрын
That's okay. Pleased it helped.
@algobrax4 жыл бұрын
thank you!
@kirilljohnson24745 жыл бұрын
Could you please advise on what would be an approximation for cos 3 theta?
@isaacjacobharris5 жыл бұрын
1- (9*theta^2)/2
@akhilesh14663 жыл бұрын
Thanks
@Wowow100003 жыл бұрын
Thanks helpfull
@theodoresweger49483 жыл бұрын
MY big mistake not using radian mode in my HP 35s now works out great..
@trollghostol9 жыл бұрын
couldnt you just look at the graph of sin(x) and tan(x) and see that their gradient approaches 1 at x=0?
@ExamSolutions_Maths9 жыл бұрын
+Ell “christkidz” Op How does that show that sin(x) is approx x, tan(x) is approx x and cos(x) is approx 1-(x)^2/2
@trollghostol9 жыл бұрын
ExamSolutions well, if the gradient approaches one, the tangent to the graph as x approaches 0 is nearly y=x, and since y is sin(x), it shows that sin(x) is approximately x, same with tan, although it dont know how it would work with cos(x) sorry
@ExamSolutions_Maths9 жыл бұрын
+Ell “christkidz” Op There are several ways to prove this these results as I said at the beginning, this was just one way.