Excellent Quadratic Question on Basic Concept | Quadratic Equations Class 11 |JEE Advanced PYQ |

[@Sujal2007-v6y]

An inductance coil has a reactance of 100 Ω. When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45 deg The self-inductance of the coil is [JEE (Main)-2020]

[@aryabhataiitmaths]

Dear, Ask maths questions ... I'll start Physics soon...🙂

[@Sujal2007-v6y]

@@aryabhataiitmaths I have another doubt please 👇🏻 A 750 Hz, 20 V (rms) source is connected to a resistance of 100 Ω, an inductance of 0.1803 H and a capacitance of 10 µF all in series. The time in which the resistance (heat capacity 2 J/°C) will get heated by 10°C. (assume no loss of heat to the surrounding) is close to

[@ByRoadPrim]

15 mH ???

[@Sujal2007-v6y]

@@ByRoadPrim i don't want copy paste solution

[@devanshgoel1803]

Good Question

[@aryabhataiitmaths]

Thanks dear 🙂

[@Gurucharan-b3u]

Tq for explaining this type of question sir please explain more problems like this❤❤❤❤❤

[@aryabhataiitmaths]

You are most welcome 🙂, sure dear 👍

[@binayakbanerjee9294]

You could have used the value of 5 and 65 to evalute the values of root (alpha - 1) and root (beta - 1). Why did you sqare and found in a lengthy way 🙄

[@rhythmvaishnav7402]

came here to write the same loll

[@aryabhataiitmaths]

Yes dear you are absolutely right ✅️ That didn't strike to my mind ... Thank you so much for your comment...😊

[@VinayVerma__.999]

4:42 Multiplication nahi smjh aayi😢

[@aryabhataiitmaths]

Dear it's just multiplication of two algebraic expressions. Please try multiplying by your own then you get that point easily 🙂

[@VinayVerma__.999]

4:42 (alfa-1)(ß-1) maine bahut try Kiya but nhi kar paya 😢😢

[@aryabhataiitmaths]

@VinayVerma__.999 Dear (a-1)(b-1)=ab-b-a+1 Ab dekho aap ki samjh aa gaya ya nahi...

[@VinayVerma__.999]

​@@aryabhataiitmaths are han aapane to (alpha bita ko braiket me kiya h qki value rakhna hai😊❤

[@aryabhataiitmaths]

@VinayVerma__.999 Yes dear 🙂 Good 👍

[@surendrakverma555]

Thanks Sir 👍

[@aryabhataiitmaths]

Welcome dear 🙂