How to Solve a 4th Order Partial Differential Equation | Vibrating Beam Part 1/2

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Faculty of Khan

Faculty of Khan

Күн бұрын

Пікірлер: 36
@FacultyofKhan
@FacultyofKhan 5 ай бұрын
I've finally uploaded part 2 of this video! kzbin.info/www/bejne/mHaymptumLeKl8k
@mastershooter64
@mastershooter64 Жыл бұрын
"Are you tired of being called a scrub because you can only solve a 2nd order PDE, well worry not this video will teach you how to solve a 4th order PDE like a chad" Lmfao
@bad2thenucleus
@bad2thenucleus 2 жыл бұрын
Thanks for the video. Would also appreciate a part 2... I am not seeing one on your page...
@peterarutu1414
@peterarutu1414 3 жыл бұрын
Thank you for this wonderful video but I don't know if it is me, part 2 of the video is missing. Thank you!!!
@FacultyofKhan
@FacultyofKhan 3 жыл бұрын
Thanks to Skillshare for sponsoring this video! The first 1000 people to use the link will get a free trial of Skillshare Premium Membership: skl.sh/facultyofkhan02211
@dhondm29
@dhondm29 3 жыл бұрын
This is a great video Sir. May I know where I can watch the part 2 of it??? Thank you
@FacultyofKhan
@FacultyofKhan 5 ай бұрын
Here you go (2 years late to the party lol): kzbin.info/www/bejne/mHaymptumLeKl8k
@PunisherTR
@PunisherTR 5 ай бұрын
​@@FacultyofKhan Ahahhahahha
@mastershooter64
@mastershooter64 3 жыл бұрын
Please continue the real analysis series
@adamarana3501
@adamarana3501 3 жыл бұрын
Is there a part 2?
@erfanmohagheghian707
@erfanmohagheghian707 Жыл бұрын
I did it :) kzbin.info/www/bejne/eKO7lJVoYsSlkMU
@aldirudywinoto6758
@aldirudywinoto6758 2 жыл бұрын
Thanks a lot such a good video, but where's the next part of this?
@JUAN1TOTELO
@JUAN1TOTELO 9 ай бұрын
Amazing video!
@rachelhobbs6189
@rachelhobbs6189 Жыл бұрын
Thank you so much for these videos! Want the part 2 :)
@erfanmohagheghian707
@erfanmohagheghian707 Жыл бұрын
I did the second part for you :) Please watch and give me your feedback if you wish kzbin.info/www/bejne/eKO7lJVoYsSlkMU
@engr.israrkhan
@engr.israrkhan 3 жыл бұрын
which drawing tablet you are using???
@ozgun228
@ozgun228 3 жыл бұрын
If the wave propagation is in the x-direction and wave amplitude is vertical (u), Shouldn't the moment of inertia be w.r.t the axis orthogonal to the plane of the drawing?
@FacultyofKhan
@FacultyofKhan 3 жыл бұрын
I'm not terribly familiar with beam mechanics, so I can't speak much to how alpha was derived, but based on this link: en.wikipedia.org/wiki/Euler%E2%80%93Bernoulli_beam_theory#Static_beam_equation The moment of inertia is 'calculated with respect to the axis which passes through the centroid of the cross-section and which is perpendicular to the applied loading.' In this case, the cross section is in the uz-place (i.e. the circular cross-section of the cylindrical beam with its length along the x-axis), and the applied loading is in the u-direction. The axis which satisfies both of these stipulations is the x-axis (passes through the centroid of the cross-section in the uz-plane and is perpendicular to the applied loading in the u-direction). Hope that helps!
@crixboyca
@crixboyca 3 жыл бұрын
and the best is the derivation of the equation by using the Euler Lagrange equation on a beam
@jv2781
@jv2781 2 жыл бұрын
Raos continuous vibrations book does this for beams, plates, shells, etc. Real fancy stuff !
@adewaleoluwatimehin2696
@adewaleoluwatimehin2696 Жыл бұрын
Thanks!!!
@mokuscsik
@mokuscsik 3 жыл бұрын
Thanks for this! Can I ask what software you use for the anumation?
@MrRyanroberson1
@MrRyanroberson1 3 жыл бұрын
it's just some kind of manual drawing program combined with screen recording, but i would also like to know what program that is specifically
@ccm9450
@ccm9450 2 жыл бұрын
great video very helpful
@standowner6979
@standowner6979 3 жыл бұрын
I missed you!!!
@jarogniewborkowski5284
@jarogniewborkowski5284 3 жыл бұрын
Cool. Waiting for more PDEs connected with physics. Best regards
@gbpferrao
@gbpferrao 3 жыл бұрын
next level
@aidanatkinson7717
@aidanatkinson7717 3 жыл бұрын
wheres the part 2
@justinmartinez4519
@justinmartinez4519 3 жыл бұрын
where is the second part!?!?!?!?
@SATOUBLOGS
@SATOUBLOGS 3 жыл бұрын
Thank you.
@rashidchishti906
@rashidchishti906 2 жыл бұрын
where is part 2
@s1gaba
@s1gaba 3 жыл бұрын
GOD BLESS YOU
@mr.logzoid1302
@mr.logzoid1302 3 жыл бұрын
We are using neumann boundary conditions correct
@FacultyofKhan
@FacultyofKhan 3 жыл бұрын
I've typically heard of Neumann in the context of a boundary condition on the first derivative. In this problem, we have boundary conditions on the function itself (i.e. Dirichlet) and on the second derivative (not sure that would classify as Neumann though).
@jameyatesmauriat6116
@jameyatesmauriat6116 2 жыл бұрын
Very bad because it's quick, the writing is fast and I couldn't follow up with what you say
@Mathin3D
@Mathin3D 2 жыл бұрын
FAIL.
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