I've finally uploaded part 2 of this video! kzbin.info/www/bejne/mHaymptumLeKl8k
@mastershooter64 Жыл бұрын
"Are you tired of being called a scrub because you can only solve a 2nd order PDE, well worry not this video will teach you how to solve a 4th order PDE like a chad" Lmfao
@bad2thenucleus2 жыл бұрын
Thanks for the video. Would also appreciate a part 2... I am not seeing one on your page...
@peterarutu14143 жыл бұрын
Thank you for this wonderful video but I don't know if it is me, part 2 of the video is missing. Thank you!!!
@FacultyofKhan3 жыл бұрын
Thanks to Skillshare for sponsoring this video! The first 1000 people to use the link will get a free trial of Skillshare Premium Membership: skl.sh/facultyofkhan02211
@dhondm293 жыл бұрын
This is a great video Sir. May I know where I can watch the part 2 of it??? Thank you
@FacultyofKhan5 ай бұрын
Here you go (2 years late to the party lol): kzbin.info/www/bejne/mHaymptumLeKl8k
@PunisherTR5 ай бұрын
@@FacultyofKhan Ahahhahahha
@mastershooter643 жыл бұрын
Please continue the real analysis series
@adamarana35013 жыл бұрын
Is there a part 2?
@erfanmohagheghian707 Жыл бұрын
I did it :) kzbin.info/www/bejne/eKO7lJVoYsSlkMU
@aldirudywinoto67582 жыл бұрын
Thanks a lot such a good video, but where's the next part of this?
@JUAN1TOTELO9 ай бұрын
Amazing video!
@rachelhobbs6189 Жыл бұрын
Thank you so much for these videos! Want the part 2 :)
@erfanmohagheghian707 Жыл бұрын
I did the second part for you :) Please watch and give me your feedback if you wish kzbin.info/www/bejne/eKO7lJVoYsSlkMU
@engr.israrkhan3 жыл бұрын
which drawing tablet you are using???
@ozgun2283 жыл бұрын
If the wave propagation is in the x-direction and wave amplitude is vertical (u), Shouldn't the moment of inertia be w.r.t the axis orthogonal to the plane of the drawing?
@FacultyofKhan3 жыл бұрын
I'm not terribly familiar with beam mechanics, so I can't speak much to how alpha was derived, but based on this link: en.wikipedia.org/wiki/Euler%E2%80%93Bernoulli_beam_theory#Static_beam_equation The moment of inertia is 'calculated with respect to the axis which passes through the centroid of the cross-section and which is perpendicular to the applied loading.' In this case, the cross section is in the uz-place (i.e. the circular cross-section of the cylindrical beam with its length along the x-axis), and the applied loading is in the u-direction. The axis which satisfies both of these stipulations is the x-axis (passes through the centroid of the cross-section in the uz-plane and is perpendicular to the applied loading in the u-direction). Hope that helps!
@crixboyca3 жыл бұрын
and the best is the derivation of the equation by using the Euler Lagrange equation on a beam
@jv27812 жыл бұрын
Raos continuous vibrations book does this for beams, plates, shells, etc. Real fancy stuff !
@adewaleoluwatimehin2696 Жыл бұрын
Thanks!!!
@mokuscsik3 жыл бұрын
Thanks for this! Can I ask what software you use for the anumation?
@MrRyanroberson13 жыл бұрын
it's just some kind of manual drawing program combined with screen recording, but i would also like to know what program that is specifically
@ccm94502 жыл бұрын
great video very helpful
@standowner69793 жыл бұрын
I missed you!!!
@jarogniewborkowski52843 жыл бұрын
Cool. Waiting for more PDEs connected with physics. Best regards
@gbpferrao3 жыл бұрын
next level
@aidanatkinson77173 жыл бұрын
wheres the part 2
@justinmartinez45193 жыл бұрын
where is the second part!?!?!?!?
@SATOUBLOGS3 жыл бұрын
Thank you.
@rashidchishti9062 жыл бұрын
where is part 2
@s1gaba3 жыл бұрын
GOD BLESS YOU
@mr.logzoid13023 жыл бұрын
We are using neumann boundary conditions correct
@FacultyofKhan3 жыл бұрын
I've typically heard of Neumann in the context of a boundary condition on the first derivative. In this problem, we have boundary conditions on the function itself (i.e. Dirichlet) and on the second derivative (not sure that would classify as Neumann though).
@jameyatesmauriat61162 жыл бұрын
Very bad because it's quick, the writing is fast and I couldn't follow up with what you say