A good simplistic approach to explaining the alchemy of RF.
@4acae8629 күн бұрын
Great explanation, thank you!
@theoldhobbit36403 жыл бұрын
Excellent explanation. I have built several /P fan dipoles, mostly 10, 20 & 40mtrs and tuned each leg little by little, but never really understood the "magic" behind it, now I do. Thank you.......
@foxonem7dfh2572 жыл бұрын
Thanks Mike love the round peg in a square hole analogy
@BoB4jjjjs3 жыл бұрын
Yeah, good explanation. I wouldn't have thought of the child's toy bit, but it explains it well for those that struggle with it. Well done Mike.
@Rotanrider3 жыл бұрын
Great video and easy to understand. I‘m right learning vor my Class E License in Germany. You are a great Inspiration for this hobby.
@robjackson413 жыл бұрын
Nicely explained. I have an indoor fan-dipole and it works well. I'm amazed your able to get the vswr so low with the ends of the wires being so close to each other. All of the fan-dipole designs I've come across suggest keeping each dipole end well apart (18 inch) or so.
@abrahamnorthhampton33273 жыл бұрын
Terrific explanation. Learning a lot about antennas from you, Mike! 73
@mike-M0MSN3 жыл бұрын
Thanks
@Ron_pd3ron3 жыл бұрын
That is a simple explanation and easy to understand 👍🏻
@MAV88653 жыл бұрын
Mike - cracking video! Callum could learn lot from you, hahaha (sorry Callum if your reading this but couldn't help myself mate)
@fredflintstone80483 жыл бұрын
I like Callum's explanations with everything explained in terms of 'bananas'. However not useful for taking the Ham exams.. They don't have that kind of sense of humor and want you to understand dB, dBm, dBV, and how to do the math.
@hedgerowpete Жыл бұрын
brilliant video , well done, very clear and understandable
@mike-M0MSN Жыл бұрын
Many thanks!
@gilcomnz Жыл бұрын
Wow. Brilliant way of explaining. Thank you
@thork0tjt5153 жыл бұрын
Brilliant explanation! Thank you Mike!
@clivebannister70163 жыл бұрын
I did wonder. And now it makes sense. Thanks Mike 😀
@BobMellor19542 жыл бұрын
Like the analogy Mike
@mike-M0MSN2 жыл бұрын
Thanks
@G5XDX3 жыл бұрын
I only watched for the mention of inclement weather things 🤔 Seriously though, I'm a fan of an hf fan dipole. No pun intended. Good video, well explained
@ReedAB8AS3 жыл бұрын
Interesting. Great Explanation.
@mike-M0MSN3 жыл бұрын
Thank you!
@daviddavidson1372 Жыл бұрын
Great video.
@MW6PNW3 жыл бұрын
Well explained. Cheers Mike
@Mottersmotters3 жыл бұрын
Hello Mike great video super work. Radio magic. Its just works. 👍🏻 Motters M7TRS 73's
@iestynwyn43113 жыл бұрын
good video as always thanks mike
@Airconed3 жыл бұрын
Thanks M8. Great Vid and explanation
@whymarko Жыл бұрын
If the antenna radicals and reflectors are all insulated copper wire can you cable tie them together...all radicals together in parallel and all 3 reflectors together in parallel? If not how far apart should they be?
@graemeeuk3 жыл бұрын
Another great video, thanks. I’ve been experimenting with a homebrew fan dipole but I’m struggling a bit with the elements interacting with one another, simply too close I suspect. Irrespective, they’re a great idea and this video is a super explanation of the theory. 73 M0EUK
@DonDegidio3 жыл бұрын
Hi Mike, Very plausible and understandable explanation. Stay safe. WJ3U
@mike-M0MSN3 жыл бұрын
Thanks Don, it’s never easy to explain what my head is saying 😂😜🤪
@DustInTheWindAZ Жыл бұрын
I was following along fine with your description until you tried to use the analogy of the different shaped blocks. They're NOT 'different shapes", but rather different sizes of the same shape! In your first drawing, you drew antennas (antennae) of lengths that were exact doubles or halves of their adjacent ones (harmonic lengths, if you will). As a musician and guitar player, I recognize that these antennae will also resonate sympathetically on their first and second harmonics. I get the "path of least resistance" analogy. Is it more an issue of the "reactance" of each leg at the transmitted frequency that causes the resonance? Obviously, the transmitted signal is going through ALL of the legs. Is it the reactance to the frequency that causes each antenna leg to be resonant in the proper frequency or band? I'm thinking the signal is resonant to some extent on ALL of these legs!
@VK5KU3 жыл бұрын
Beautifully explained! A hexbeam works similarly to a fan dipole with the centre hub representing 50 Ohms. Keep up the good work Mike and stay safe. Kevin, VK4KK
@saaqisms10 ай бұрын
Classic explanation
@SuburbanDXing3 жыл бұрын
Another solid video, Mike...no ad issues, as well...thank you! 73! de WX0V P.S. You coax line drawings rule... :-)
@mike-M0MSN3 жыл бұрын
Cool, thanks!
@chrisbartlett60223 жыл бұрын
Well said that Man.
@2E0LMI3 жыл бұрын
Well presented, but I have a related question I think it does not answer... I built a fan dipole that includes a 10m band element and a 15m element. If I were to add a 40m band element, when transmitting on 15m which element would radiate, as I understand a 40m band one works for 15m? Serious question as I do want to add 40m to it, but I really want my 15m element to continue radiating on 15m as I have put a lot of effort into creating an efficient wideband element (more to it than just a thin single wire). So what happens in this instance when there's two holes that a peg will fit into? Wonder if you know, I haven't found the answer anywhere else yet. M7TDV
@mike-M0MSN3 жыл бұрын
Great question and the answer is: there both do, however the 40m element is going to resonate slightly higher up the band than the 15m element unless you are going to load the 40m element in the same way that the DXCommander. You should find that most of the work will be done by the 15m element as it will be on the primary unlike the 40m which is on the 3rd harmonic.
@2E0LMI3 жыл бұрын
@@mike-M0MSN Thank you Mike for taking the time to answer, very much appreciated. And with the answer I was hoping for too :)
@NamasenITN Жыл бұрын
An elementary explanation of Kirchoff's law of currents and of the maximal power transfer with a parallel of resistors. However the intuitive analogy you illustrated works only in the limit of a parallel of resistors with infinite values (and one finite). It doesn't address why resonance is not affected by neighborhing branches.