How to Find the GCF of Large Numbers Easily

In this video I'll show to you the tricks on how to find the GCF of Large numbers easily and quickly.
#gcf #greatestcommonfactor #tricksgcf
#mathtricks
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[@frankdiaries]

According to her method: 1. Divide the greater number and least number. E.g: 945/630 = 1 r. 315 r. means remainder. 2. Divide divisor by the remainder. E.g: 630/315 = 2 with no remainder. 3. If it no longer has *no* remainder, then the _previous remainder_ is the CGF. Eg: 945/630 = 1 r. 315 630/315 = 2 (r. 0) Therefore, 315 is the GCF. If there is still a remainder, keep dividing the divisor by the remainder until it has no remainder. Apparently Quotients, ie. results of a division process, has no use here, lol.

[@Jraifamilyophanlan]

Thank you so much for sharing like +1🛎🤝👍🙏🙏🙏

[@itsallaboutjesus777]

Hello Ma'am, nice teaching, very helpful, I'm not good in mathematics lol so this is good for me to learn😂👍, thanks for sharing❤. Have a great week.

[@akikosugpatan6197]

thank you po sharing this trick♥️

[@dulcejorolan6702]

Thank you ma'am 😭😭😭😭 planning to take civil service exam this march very helpful 😭

[@jomarmendellore]

Thank you ma'am

[@adrianpoblete8129]

Salamat po

[@minerva6814]

Hello ma'am, may I ask what is the logic behind this? I would like to understand more about how and why it works. Thank you!

[@yelenavitoriagonzales69]

sameee, I dont get the logic either

[@jonawiththejapanese]

❤️👍👍

[@cherylsugpatan2177]

maam request po ng addition fraction pero 3 or more fraction with large number.the eassiest way po.sana po mabasa mo po.salamat

[@sheishou5686]

Salamat ma'am bobo ako sa mga GCF of larger numbers 😅😭

[@joshuasarmiento820]

I couldn't understand anything.

[@joshuasarmiento820]

Yea it was hard.😒

[@frankdiaries]

​@@joshuasarmiento820 To find the GCF between two larger numbers. According to her method: 1. Divide the greater number and least number. E.g: 945/630 = 1 r. 315 r. means remainder. 2. Divide divisor by the remainder. E.g: 630/315 = 2 with no remainder. 3. If it no longer has *no* remainder, then the _previous remainder_ is the CGF. Eg: 945/630 = 1 r. 315 630/315 = 2 (r. 0) Therefore, 315 is the GCF. If there is still a remainder, keep dividing the divisor by the remainder until it has no remainder. Apparently Quotients, ie. results of a division process, has no use here, lol. Tested it, it works for smaller numbers too.