Finding inverse functions: rational | Mathematics III | High School Math | Khan Academy

[@navaneethmukund3013]

it's -1-3y

[@bracemouthify]

The 1 in your answer should be negative, so x= (-1-3y)/(y-2)

[@spurti]

yes me too

[@Dylan-hx1oo]

thanks! This kinda help me to understand our lecture better...

[@valerijavalerija7134]

I solved it a little bit different. The first time I got x=(3y+1)/(2-y), the second time x=(-1-3y)/(y-2).After substituting y with different numbers, both functions had the same x outcomes. Are the two function equations correct in this case?

[@andrewfeng3403]

yes, both are correct, it's like 1/2 = -1/-2

[@ariturbo4094]

That should be negative 1 sir!!!! If count from range to domain youll see the digference

[@mauricioruacho6207]

🤯

[@danielweinstein5923]

Mistake at the end!

[@Macky91SWE]

haha I'm so going to use a happy face instead of x on my exam this friday

[@water6133]

hows it going haha

[@Macky91SWE]

@@water6133 Graduating as a Software Engineer this summer :D Khan Academy ftw!

[@water6133]

@@Macky91SWE whoa, that is cool!

[@NewWesternFront]

@@Macky91SWE have you found a job

[@GaNk1n1t]

You killed a puppy.

[@rosacruz8479]

You zmade a miztake

[@NewWesternFront]

you made a mistake the smiley face should be frowny face :(