Finding the Area of a Region

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Dr Barker

Dr Barker

Күн бұрын

We find the area of the region where | |x + y| - y| ≤ |x - y| ≤ 3.
00:00 First inequality |x - y| ≤ 3
01:42 Second inequality x + y ≥ 0
06:35 Second inequality x + y ≤ 0
11:25 Finding the intersection

Пікірлер: 22
@user-cd9dd1mx4n
@user-cd9dd1mx4n Ай бұрын
I really appreciate the step-by-step approach. Your way of explaining things is really effective. Thank you very much❤
@russelltownsend6105
@russelltownsend6105 Ай бұрын
Another absolutely brilliant delivery, I just love your clarity and timing.
@vvop
@vvop Ай бұрын
That was so enjoyable. I can't wait until next week, now! Thank you.
@ronbannon
@ronbannon Ай бұрын
First, a trivial (by inspection) solution is x = y = 0. Second, two simple lines emerge from | x-y | = 3. From this, you get y = x + 3 and y = x - 3, which can be used to solve | |x + y| - y| = |x - y | for points of intersection. A series of lines emerge, forming regions that can be tested for shading.
@boringextrovert6719
@boringextrovert6719 Ай бұрын
I live in Korea. Every Friday after I leave work, I open KZbin, and it recommends me your videos. Good way to end my week
@vvop
@vvop Ай бұрын
I live in Australia, same for me, a great way to end the work week!
@brendanmccann5695
@brendanmccann5695 Ай бұрын
Nice job. Very clean. Thank you.
@magicmeatball4013
@magicmeatball4013 Ай бұрын
Has a week really passed again??
@gael8828
@gael8828 Ай бұрын
For the case x+y>0 (7:47), I think the point where you're closest to -2y than -y is -3/2*y, not -y/2 as you mentionned.
@davidcroft95
@davidcroft95 Ай бұрын
The singular y is with a plus sign, and the mean between y and -2y is (y-2y)/2=-y/2
@gael8828
@gael8828 Ай бұрын
@@davidcroft95 You're perfectly right, my eyes saw a minus sign where there was not...
@davidcroft95
@davidcroft95 Ай бұрын
@@gael8828 ahah don't worry, it got me fooled too, I had to stop the video and do the math in my head 😂
@ShanBojack
@ShanBojack Ай бұрын
Dang man this was nice stuff really 👏
@jim3129
@jim3129 Ай бұрын
clear explanation
@lenskihe
@lenskihe Ай бұрын
Excellent presentation and explanation, as always 👏 But I personally do not find these absolute value inequalities very interesting. They just boil down to a lot of case differentiations. Still a very valuable lesson for people who have never seen this kind of thing before.
@user-wu8yq1rb9t
@user-wu8yq1rb9t Ай бұрын
The beautiful mind is here ... Now I should go (I have exam) ... Then I'm back and watch it. Thank you dear Dr Barker
@andriworld
@andriworld 28 күн бұрын
Can this be solved with integrals?
@jbrecken
@jbrecken Ай бұрын
Is absolute value called modulus now?
@brendanmccann5695
@brendanmccann5695 Ай бұрын
in the UK, yes
@davidcroft95
@davidcroft95 Ай бұрын
Within real numbers they are synonyms, things start changing with complex numbers (and vectors ofc)
@psiphiorg
@psiphiorg Ай бұрын
@@brendanmccann5695, I had never heard this term applied to the absolute value before, so I was also very confused at first, because I didn't know how the absolute value applied to modular arithmetic. After thinking about it, I can see a similarity between the absolute value and the modulo operator, since one is a distance from zero and the other is a distance from a multiple of the divisor. But 19 % 5 = 4, not 1, so they're not quite the same. Is "absolute value" just the American way of saying this, or do British people use both terms interchangeably? I tried some Googling to see if I could answer this question myself first, and from the queries I did, it looks like most sources in the UK use only modulus and not absolute value. I did find a few, but now I'm wondering if these might be from Americans working on British websites.
@BUY_YOUTUB_VIEWS_2273
@BUY_YOUTUB_VIEWS_2273 Ай бұрын
I wish I had found your channel earlier. Amazing! 😃
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