Finding the Vertex of a Parabola Using the X-Intercepts | Quadratics Series Ep. 3

In the 3rd video of my quadratics series we look at how we can find the vertex using the x-intercepts, NOT vertex form! This is a quick and easy way to find the vertex when graphing a parabola, because finding the x-intercepts and vertex will get you enough points on the parabola to get a good idea of what it looks like. These 4 simple steps will have you graphing quadratics like a pro!
Timestamps
0:15 - How is the vertex different from our x and y intercepts?
1:20 - Step 1
1:36 - 1 X-Intercept
2:09 - No X-Intercept
3:37 - 2 X-Intercepts
3:50 - Step 2
4:03 - Step 3
4:11 - Step 4
4:19 - Example 1: y=x^2+2x-15
5:47 - Example 2: y=x^2-16
6:37 - Example 3: y=x(x+4)
7:10 - Example 4: f(x)=2x^2+11x+5
Other videos you may find helpful:
Episode 1: Finding x-intercept(s)- • Finding the X-intercep...
Episode 2: Finding the y-intercept- • Finding the Y-Intercep...
Solving in Standard Quadratics form where a=1- • Diamond Problems | The...
Solving in Standard Quadratics form where a is not 1- • Factoring Made EASY By...
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