Five Number Summary, Boxplots, and Outliers | Statistics Exercises

We find the 5 number summary of a data set and use it to construct a box and whisker plot and then a modified boxplot which represents outliers specially. The five number summary of a set of data consists of the minimum, the first quartile, the median, the third quartile, and the maximum. Then, Q3-Q1 is the interquartile range or IQR, and this can be used to classify outliers. #statistics
What is a 5 Number Summary? • What is a 5 Number Sum...
Interquartile Range: • How to Find the Interq...
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[@WrathofMath]

I tried to be exceptionally brief but still helpful in this video - as brevity seems to be one of the primary ways to break into highly competitive video topics such as this one. If I can spend all my time making math videos someday, I'll just make hour long Game Theory and Graph Theory lectures.

[@pickelsandnickels2487]

You explained this better than my math teacher

[@starGirl-dl1rx]

Thank you, Teacher , that was very well explained. I just have one question : When working out whether 10 is an outlier or not, where/ how did you get the 4.5 value?

[@arisrodriguez620]

Thanks this helped me study for my upcoming test!

[@JuvBhodey]

How is Mr beast following u 😮

[@andrewbroschart9445]

Thanks!

[@WrathofMath]

Glad to help! Thanks a lot for the Super!

[@janiceanne1032]

Thank you so much.

[@WrathofMath]

Glad to help!

[@auntsquidwardd]

im writing my exams soon and i want to understand if my maximum is only 6 on the box whisker plot and calculating the upper whisker limit is more than my maximum, do i include the outlier in the box whisker plot or just leave it out? i dont know if im making sense your video helped me a lot btw, thank you

[@devsimx-me4vn]

Thanks for this I have an exam tomorrow on universal data or whatever and I play games in class normally so this really helped me out.😁

[@WrathofMath]

Glad to help, good luck!

[@CindyNamazzi]

Thank you so much❤

[@WrathofMath]

Glad to help - thanks for watching!

[@RONINMN]

thanks for the carry

[@WrathofMath]

i gotchu

[@radha792]

You’re the best math teacher ever!!❤❤

[@WrathofMath]

Thank you!

[@jacinthpaul6629]

Well explained 😮

[@WrathofMath]

Thank you!

[@ndk8009]

Hi I’m not sure if I’m wrong but to fine the median the formula is (n+1)/2 so n = 10 number, (10+1)/2 = 5.5 so it would be at the position 5.5 in the number range, there fire the mean would be (3+4)/2 = 3.5 which u r correct. But for the Q1 the formula would be (n+1)/4 so (10+1)/4 = 2.75, so it would be at the position 2.75 therefore cannot be directly in the middle of 1 and 2, you are wrong because u didn’t count in the 0.5 between 3 and 4. The correct answer for 1st quartile would be (10+1)/2 = 2.75 So it would be at positron 2.75 Position 2 = 1 Position 3 = 2 And you want to find position 2.75 so you would need to find the 0.75 between 1 and 2 To do that: You take 2-1 = 1 and then 1 x 0.75 which would give you 0.75 0.75 then add to 1 (position 2) and you get 1.75 1st quartile would be 1.75 So your answer is wrong And the 3rd quartile is wrong also

[@josezuniga3503]

Just draw a cf table and find it man.

[@victorbakanda9966]

Is the diagram skew to the left or skew to the right

[@RockWhisperer577]

Cool

[@WrathofMath]

Statistics is!

[@esmatullah873]

Q1=n+1/4 and Q3=3(n+1)/4 🤨

[@nasimaowais7530]

How did you get 6 ?

[@jocelynguzman8303]

Since the outlier is 10, he changed the graph so that the max would be 6

[@user-ht4cp8oq7e]

Isnt the median 3.8?

[@mattlan37x21]

That is the “mean”, look up definition of median for how to find the median