In this video we have to design for a flitch beam due to depth limitation of the supporting new beam. For structural engineering services in Massachusetts and New Hampshire please go to my web site www.garciaengineeringllc.com
Пікірлер: 33
@MolotovWithLux4 жыл бұрын
This is the most Proper, Process and Design Calculations
@ragnarmarnikulasson36263 жыл бұрын
thanks man, great video
@WoopsUforgot2Breahte3 жыл бұрын
Really helpful!
@LuisGonzalez-lb8nr5 жыл бұрын
Can you tell me how to calculate the req'd. inertia? thank you
@ledihalediha5 жыл бұрын
Dear Sir, I have watched your video and found it is quite useful for my study. I love the way you explained thats why i message. just wondering if you have time for my question. I am doing calculating about flitch beam, in which steel plate is by I shape, and considering the dowel connections. I am not a civil engineering so I would like to learn from you. Could you please kind enough to give me some clues on this field. Thank you so much and looking for your consideration!
@teeowe15 жыл бұрын
Can you give us a quick explanation why you choose two 1/4" steel plates instead of one 1/2" steel plate. I would think an (LVL - 1/2"steel - LVL) beam would also work.
@ChitownMilcrib Жыл бұрын
Probably because he needed the added bending strength of the additional lvl and 3 would help evenly sandwich the plates
@vandy97535 жыл бұрын
you forgot the shear transfer at the throughbolts from the wood to steel - pretty important
@FGJEngineering5 жыл бұрын
Didn’t forget I just didn’t have the time to put it in this video. I will do another video showing the shear transfer. Thank you though.
@jorgeibarra55725 ай бұрын
What are you waiting for? Have been 5 years ? Come on, kidding, awesome, thanks for sharing@@FGJEngineering
@saijiang51434 жыл бұрын
w should equal to 55*10.75' you times the length again
@lesdupre4667 жыл бұрын
Hi Paul. I can't seem to come up with the Ireq'd of 275 or 300 in the example.. if w=591.25 and L=12.75 and E=1700000(?) .. I get a number of 2.25 for I req'd. What could I be doing wrong?
@lesdupre4667 жыл бұрын
Sorry, had to correct units.. got it now
@jamarvisboykin44612 жыл бұрын
@@lesdupre466 I'm still not getting 275 or 300 with the correct or incorrect w. Also, i see you used 1.7 x 10^6 for Ew but he used 2.0 x 10^6, which one is correct?
@daniels59156 жыл бұрын
ok so a couple things so far. you have the wrong value in for W as you don't multiply by the length of the beam you multiply by the trib, and when you are solving out for b, I have no idea how you came up with 0.36, with the numbers you have provided it should come out as 0.29. do us a favour if you can and show the math. Thanks for the video
@FGJEngineering6 жыл бұрын
Thank you for pointing that out. The trib width is 10.66ft. 55psf*10.66ft=587 plf. I used 595 so the numbers will be off by a little bit. As for the width of steel it is 0.29. I must have plugged something wrong in the calculator. However the process of the design of the flitch beam is correct. For future videos I will be more precise with the results. Again thank you.
@garybeck72334 жыл бұрын
Exactly correct -the wrong formula was used. The video should be corrected. A 50 PSF TL applied to a long beam (100') with a very narrow tributary length (2') should generate a low 100 PLF (2' x 50 psf). But by this incorrect formula multiplying 50 PSF times the beam length of 100' the result would be 5000 plf which would be tremendously off.
@chvydrptop5 жыл бұрын
@3:07 min you multiplied 55 x 12.75 by my calculation that is 701.25 not 592.25. Did I miss something?
@blueazuro5 жыл бұрын
chvydrptop he was supposed to multiply it
@blueazuro5 жыл бұрын
by 10.75
@paulhmartin7 жыл бұрын
How do you calculate the required Inertia?
@FGJEngineering7 жыл бұрын
Hey Paul, for this example we have a simple span beam so to find the required inertia it would be I=((5wL^3)/(384E))*240. The 240 is for D+L. So if your looking for deflection of L/360 then substitute the 240 with 360. Please let me know if I was clear.
@peterdangelo87987 жыл бұрын
is it I=((5wL^3? or L^4?
@FGJEngineering7 жыл бұрын
Peter D'Angelo it's L^3. In the deflection equation we are solving for the required inertia. If we say deflection is L/240 and we solve for inertia, the L^4 becomes L^3
@johnendacot7 жыл бұрын
Thanks for the video. How can required Inertia for Dead+Live (55psf) be less than for Live (40psf) only?
@FGJEngineering7 жыл бұрын
+John Endacott it has to do with the deflection criteria.... L/240 for dead and live and L/360 for live... in this case even though live load is 40psf the live load criteria makes the required inertia large
@paulg4445 жыл бұрын
Nice video, but isnt it pounds per square feet. Not pounds-square-feet. I dont doubt his result.
@FGJEngineering5 жыл бұрын
You’re correct sir. For future videos I’ll say it correctly. Very respectfully, Felix
@paulg4445 жыл бұрын
@@FGJEngineering yes, but more important to know what lbs per square foot means so that it is not just plug and play equations but rather engineering reality that you are communicating.
@georgeegerog41757 ай бұрын
useless if you skip a the part about how you get required inertia