Fluid Mechanics | Module 1 | Numericals on Properties of Fluid | Part 1 (Lecture 6)

[@gurungkoxora3065]

sir u came as god in my life for passing back exams love from Nepal

[@apurbabauri3878]

At 50:23, you did not put the value of area. Kindly rectify it and thank you very much for amazing explanations 🙏

[@kapilverma6497]

Correct answer is 11.25m/s

[@vincentkennedymcmahon50]

Ho jaata hi yrr wuh bhi insaan hi concept samjh ayaa bss

[@lovesinghchandra6907]

The righ answer is 11.25 m/s

[@sanketdas6228]

Yes exactly

[@sanketdas6228]

The answer is to be 11.25m/s

[@aroundus3465]

Terminal velocity in question no. 4 is 11.25.. You missed to put area in 2nd last equation

[@ashutoshkumarsafi3443]

yeah exactly

[@sharat6939]

Yeah a minor mistake

[@rafaelup]

Hi, where i get questions like that this video?

[@ranakuldp6609]

4.2m/s is correct because aapne area =0.3 liya h jabki area 0.8 is given

[@debjyotidutta8285]

@@ranakuldp6609 area 0.3 hi hai....

[@pravinkumaryadav2892]

48:08 Answer is 4.2187 Good knowledge.

[@rahuls5248]

Hello good evening sir , ur teaching style is good and u teach in such a way that we can understand every concept easily .I also sharing these vedios to my frnds . Please teach other subjects related to mechanical and make us strong in this stream . Thank for your help sir

[@Dinkerchaudhary]

Sir, thank you for putting ads in starting and end only. No ads in between. Sometimes it beaks the conncentration when i am watching videos at oher channels.

[@saurabhdubey7693]

thanks you sir...and gate academy for this excellent efforts

[@prashantshelke9314]

‌A hollow shaft is subjected to steady bending moment of 40 N-m and twisting moment of 50 M-m. Outer diameter of shaft is twice the inside diameter. Calculate diameter of shaft using ASME code for transmission shaft on the basis of maximum shearing stress theory of failure. Take : yield point stress in tension of shaft material=280Mpa , factor of safety=2.0 , combined bending and fatigue shock factor=1.5, combined shock and fatigue factor for twisting=1.0

[@shashwatchaurasia8780]

Venugopal Sir Is The Best

[@pujakushwah3953]

Thank you sir......

[@manishsingh9042]

Hi

[@prafulkumarmandal5771]

Yes this sir good. , and miss the data in question no. 4

[@GTVlogger]

Puja 🤣

[@parasnirmal6417]

At 50:30 consider area also correct answer is 4.219m/sec

[@Sanjay_kumar_k_h]

Yes

[@rexxrj4526]

no correct ans is 11.25 m/s after considering area

[@pradyumnyadav5527]

@@rexxrj4526 yeah bro

[@jeniltrivedi5543]

@@rexxrj4526 can you explain the answer in two steps?

[@rexxrj4526]

@@jeniltrivedi5543 bro u r 5 months late. I forgot what I studied 😂

[@erzahidahmad8314]

4:38 it will be1.84 x10^-6 poise (kg/ms) and to convert it in pa-s it should be multiplied by 9.81

[@AkibJahangirChoudhury]

No no need to multiply because kg/ms and Ns/m2 or Pa-s are both same

[@engineerspot-umangmishra2405]

Meri duayein aapko lag jaye sir aap jahan bhi raho khush raho Love you sir

[@mr.prabhat144]

Sir drag force wale questions me Area of contact ki value chhod di apne

[@princekumar1957]

Area aise bhi differentiation me zero ho jayaga.

[@yakshsagar]

Kon se area ki baat kar rahe ho mujh bhi batao

[@TheUnthinkableEdge]

Sahi kaha bhai

[@100rabyt7]

@@princekumar1957 how??

[@lmusic2625]

Your explain is clearly and simple

[@songstersujeet5916]

its a great lecture sir ...thnk u so much sir

[@arvind3057]

Happy birthday sir ji ❣️❣️🥰🥰😇😇

[@bhaidhami955]

Thank you very much sir for this vedio.

[@mohdmahmood8136]

Please consider area too in 90- Shear force× area=0 at 50:00

[@keertanas.233]

What is the answer u got by solving dat question?..... I got 11.25m/s does it match

[@RISHAV007SVM]

@@keertanas.233 correct

[@BrijeshKumar-sd1eq]

@@keertanas.233 Yes my answer is also 11.25

[@kohinoorsinger-z9s]

50:03 min sir area ki value put nahi ki he jo ki 0.3 he answer is 11.25m/s hoga🙏🙏

[@riyakatre9982]

U r teaching style is very nice sir

[@abrarcivilacademy1396]

In the second last que. W-tou×A=0 Then 90-dynamic viscosity ×v/h ×A=0 Then 90- .8v/10×3×10^-3 × .8=0 hona chahiye tha aapne last me Area multiply nhi kya Solve krne pr velocity 4.21 aayga

[@rajatkaushal2527]

Bilkul sahe bro

[@pallabdas5656]

ho jata hai

[@engineerspot-umangmishra2405]

Questions was very helpful sir thanks

[@jaypatel7632]

Awesome👏✊👍..

[@prashantshelke9314]

. A jet of water with a velocity Vi (Figure shown below) and area of cross-section Aj entersa stream of slow moving water in a pipe of area A2 and velocity V2. The two streams enter with the same pressure P. After thoroughly mixing in the pipe the stream emerges as a single stream with velocity Vs and pressure pa. If there are no losses in the flow, determine P2-Pi) for Vi 20 m/s, Va = 10 m/s, A = 0.01 m, A 0.02 m?, density of water p= 1000kg/m*.

[@sunderprakash9288]

Hello Sir, thank you for guidance, at question from terminal velocity(vertical type) you didn't consider Area of contact due to which result came as 3.375 meter per second square, but after considering Area of contact answer is 4.22 meter per second square. could you please confirm!!

[@mohitmukherjee5998]

no i guess after considering the area of contact the terminal velocity is 11.25 m/s2 could u plz confirm that brother ?

[@astitvakgupta]

Mine answer is 4.21

[@Mr_Secret_Poet]

Sir aap terminal viscosity ka 2 nd question wrong solve kia hain if you will multiply the area then calculation is to be right.

[@yogitathawari8770]

Thanks sir, Good teaching sir

[@niteshjaiswal1221]

Sir 3rd question me D sir length liye h to usko dia meter mankar kyn question solve kiye h

[@amitmandal9209]

Sir at 38:00 u will not change dynamic viscosity ( mu ) in si unit....

[@arihantjain7096]

good evening sir sir is vedio me 49:38 pe Area ki value ku nhi likhi?....sir pleases give me answer🙏

[@shubhamwr]

In question 3...how did u take dia as D... If dia is to be D then front view and side view are not correctly matching

[@sps0414]

Sir pls upload video more quickly .. bhut wait krna pada apki video k liye ,☺️☺️☺️☺️

[@deepikasinha1110]

Thanku so much for this coarse ; Sir plzz add qucikly all topics of module 5 and also module 6 and add privious year gate questions also

[@souryachakraborty6009]

@Piyush Kumar sahi bola bhai

[@harkishanpatil5723]

@Piyush Kumar bhai ek kaam karle... ek account bana fake wala ladki ka photo daal or naam bhi ladki wala aur comment krde tujhe bhi attention mil jayega

[@manavdesai1048]

in 3rd question area should be pi * D * h + 4pi R^2 ( surface area of cylinder)

[@mantoshpatra7643]

I also think so but why he has taken in this way I don't have any idea...

[@ramusurepally8880]

you are the BEST .

[@believer1201]

Sir 3rd question me surface tension kuch angle b to bna rha hoga plate k sath...apne wo consider kyu nahi kia equation me ? Its not water na

[@rahulsingh-ez8km]

Sir thank you and do please make videos for engineering mechanics in a serial order.

[@bizayyadav8440]

water is flowing through a pipe of 100mm diameter with an average velocity of 100m/s. determine the rate of discharge of water in letter/sec. also determine the velocity of water at the other end of pipe if the diameter of the pipe is gradually to 200mm.please solve

[@smitparmar8080]

All this lacture is useful for chemical engineering aspects .??

[@technicalaakash1689]

sir 46:47 par jo ans 266.67 v aaya vo kaise aaya bataye aur ek video banaye aisi hi calculation kaise solve kare fx-991ms ka use karke .

[@angitakar9168]

Sir in question no. 2 how soap bubble area u have taken as sphere.previously when we found out the the excess pressure it was considered as circle

[@mukeshramani5043]

Work done is equal to surface tension * increase in surface area And in case of excess pressure Pressure force is equal to surface tension force Surface tension force is a line force that's why taken peripheral distance

[@ankit13825]

@@mukeshramani5043 well explained :D

[@mantoshpatra7643]

@@mukeshramani5043 Q2 mein initial surface area 0 kyon hai thoda bata de....??

[@mukeshramani5043]

@@mantoshpatra7643 because intialy soap bubble is not exist there may be a film we have to blow a bubble from zero to a sphere of 12 cm diameter thats why initial area is zero In other problems say example if we blow bubble from 6cm to 12cm dia than we will take increase in surface area

[@mantoshpatra7643]

@@mukeshramani5043 thank you 👍

[@abhishekyadav3033]

Sir may u explain why dF/dy =0 for minimum skin force ???

[@abhishekyadav3033]

In last question

[@BrijeshKumar-sd1eq]

You must have read in maths that to find out the maximum or minimum value, its difference station is zero

[@akashvaishnav6627]

Sir At 50:00 why not take waight of water ? And you not take area in this question Final answer after taking area is 4.21875 Thanks for giving this usefull leactur

[@DeepakGupta-uv1oh]

Thank you sir for video 😊

[@anjalishekhar9014]

Sir how in question 3 the area will be π/4 D×D

[@rajatkaushal2527]

Madam g area of circle pi ×r^2 hota hai aur diameter = 2r hota hai to area of circle diameter ki form mei solve karkei pi D^2/4 HOTA HAI

[@Theek001]

@@rajatkaushal2527 thanks bro..

[@ghanshyamyadav1064]

In question 3,Force is acting on plate. I think,we should use plate area .

[@keertanas.233]

50:28min par apne Jo answer Diya hai vo match nahi karraha hai the answer which I got is 11.25m/s... Please verify once

[@AbhishekKumar-lo8es]

4.22 m/s hoga

[@jeniltrivedi5543]

Can you explain me the answer in two steps?

[@amitkumar-xh3ks]

@@AbhishekKumar-lo8es haa Bhai tu sahi bol raha hain

[@keertanas.233]

@@AbhishekKumar-lo8es plz justify it answer

[@angitakar9168]

Sir in the first question it is given that the liquid is in temperature of 20 degree centigrade,then how can we take density of water value 1000 kg/m^3

[@riturajbarman4345]

value dia nehi hein toh vahi pakad le ab har tempr pe density yaad rakhega kya ......yaad rakh sakta hein toh sahi hein tu veise krke ana......

[@shivamagrawal1182]

Temperature change hone pr water ki density me bhut negligible change aata h....to hum sabhi temperatures pr 1000 kg/m^3 hi assume krte h.

[@ankitburnwal8848]

sir forgot to divide terminal velocity with area at 50:30

[@maliwad01]

Thank you sir❤❤

[@rajatverma9068]

Sir in first question kinetic viscosity is given in centistokes 1cm=10^-2m 1cm²=10^-4m² But we use 1cm²=10^-6 m²

[@ritenshah3966]

Bro, 1 stoke=10^-4 m^2/s. Hence, it can be understood that 1 centistoke=10^-4/10^2 m^2/s or simply 10^-6 m^2/s. FYI, This was taught in previous lectures involving the discussion of kinematic viscosity

[@rajatverma9068]

@@ritenshah3966 ok bro

[@sauravbasnet5382]

Very best sir...keep going

[@pankajvlog1369]

Exlent sir

[@rajatpathak82]

sir are these videos usefull to the gate point of view... ( i mean these numericals) . plz reply

[@Pky_vlogs]

Hi Questions no. 3 mein jo access pressure hai wo cross section area per lagna chahiye Ku ki pressure to cross section per lagata hai AAP net cercumference area Liya Ku....?

[@rajatkaushal2527]

Na bhai ismei hm projected area lengheu

[@rajatkaushal2527]

Aaap isska section cut karo aur us par sir pressure ki baat kar rahe hai jo circle hoga

[@jigvig3240]

Sir in second question you did not conver diameter to meter as it was given in centimeter. Surface tension was given per metre

[@gamingfever3699]

At 49:50 , apne Area of contact (A) ki value kyu nahi likhi?????

[@parveshpal1863]

Sir grt effort....thanks ..pls make vedio on HMT ...sir pls... needs..thanks gate academy...

[@umeshchauhan7450]

sir why in last problem F is differentiate with y ?

[@samyuktharamesh5968]

sir, great lecture, but at 17:44, the shear stress on the wall must be -39.269N/m^2

[@anuraagsharma77]

why?

[@abhishekphilip2929]

Sir mujhe 1st question k second part ka unit convertion samjh nahi aaya🙄 centi stoke kaise change kiya aapne

[@priyasahu5213]

1stoke = 10^-4 m^2/s Centistoke is a CGS unit So centi is nothing but centimeter & 1m=100cm ,therefore 1 centistoke = 10^-6 m^2/s

[@nimeshsingh4787]

Nice sir .want more videos

[@kunalverma4237]

Do suggest me best books for fluid mechanics with having complex problems

[@NikhilMBagde]

50.29 sir, you forgot to put the value of area. Please edit that, and thank you for your teachings.

[@CE--AbdulMusavir]

Sir in last question.. For minimum value we put df/dy =0 But isnt that be for maximum value as well.

[@drip888]

time 12:53 why did u say AREA for pi*D*h. isn't that value the volume of the liquid?????????????????

[@soumyaprakashsahoo2127]

50:26 min - sir , area of contact ka value add nahin kiye haun ..

[@AtulYadav-yk3oh]

Sir incase of linearity slope =tanө will be equal to dy/du so why written du/dy

[@mxjjubhai7982]

Sir can you plz clear my doubt at 39:08 why du/dy is constant and how did u divide 1.5/3 ?

[@mukeshramani5043]

Because u is function of y of power one So du/dy is always constant du is change in velocity which is from 0 to 1.5 And dy is change in distance which is from 0 to 3

[@maheshkamath8068]

Last question ,for minimum resistance you differentiated wrt y ,but shear stress as well as shear force should not vary wrt y so it should be zero am I right?

[@MrSaurabh162]

in question no. 2 @10:00 can we calculate work require to blow a bubble by integrating W=∫Pdv???

[@souryachakraborty6009]

No bro

[@MrSaurabh162]

@@souryachakraborty6009 why so?

[@Village_vlogs94]

This is only reversible, and closed system work

[@hasanshaikh2046]

@Sishir Das Sir, Please upload next videos of EDC

[@freedom3983]

Sir plz solve GATE and ESE conventional level like questions also ...thnks a lot

[@artistic-v8411]

Addy Lone wait for next video

[@freedom3983]

Thnks sir a lot. .I appreciate the help

[@deepparmar9893]

Sir isme total surface area 4πr2 kaise hua at 9:15 in video in fluid mechanics module 1 lacture 6

[@divyanshushah9342]

Bro its area of a sphere

[@divyanshushah9342]

4πr^2

[@saurabhmishra-jh1te]

Agar sir es number 2 may surface tension na dia ho to kaise calculate karte

[@Sid-te6yu]

In the first question of Linerization of Newton's law of viscosity u haven't changed the dynamic viscosity from Poise to standard unit.

[@songstersujeet5916]

its very helpful

[@deepagusain2573]

nyc sir ....thanku so much

[@MuhadisaishaqZehra]

Thank u so much

[@ridwanmandal5280]

In the last question why VA is not taken ????

[@somuseth]

at 50:15 sir forget to take A in the formula.

[@mohammadwaseembangash3612]

In 3rd question plates have 2 open ends. At left end force is 2*Pi*D*sigma . What about force at right open end ?. Considering it, total force due to surface tension will be 4*Pi*D*sigma. If anyone can clear my doubt.

[@arunff3905]

Sir ap ek problem me Area calculate karna bhulgaye😢

[@anushaanu7013]

Sir circle circumference formula 2pi r but u write 2pi D in 3rd sum....

[@manishshandilya7206]

Sir. the terminal velocity is 11.25 in question no. 4 because you are not put tha value of area

[@pushpendraverma1554]

sir, I think you forget to consider area while solving, at 50: 00, kindly correct it if possible please let me know if I am wrong

[@anandh1967]

4.21 m/s

[@rajatsoni6774]

sir question 1 density of water at 20 degrees will be less than 1000..?

[@rajatsoni6774]

at 49:31 I think there is error sir area value 0.8 is not added in equation...

[@Abhinav-bp8pi]

@Rajat soni density of liquid at 20 degree is given Not that of water

[@ramnarayan5711]

Answer of one question is 11.25

[@GaganSingh-op4vw]

Great sir

[@khushtailor7887]

in problem 3 first u considered area as pie*D*h but afterwards u considered the area as pie*D^2 why?

[@nusrattasnim5959]

In the last problem, why df/dy=0?? Didn't understand it.. Can anyone tell me?

[@rajahsekhar5077]

For maximum value of fr? also same?

[@sourabhvishwakarma1843]

At 50.01 the velocity will be 11.25m/s

[@pro-people3757]

sir is this also for chemical engineering students?

[@somyakumar9861]

Ty sir plz made vedio for SOM too

[@Chandler-xd1zs]

17:44 , poise ka conversion SI unit me nhi kiya kya?

[@anshumanparida5902]

right ans will be 4.219 of q.4 of terminal velocity

[@ashwinghag8510]

Which book should we refer for fluid mechanics b tech engineers mechanical

[@Sinurjoda02]

very very thank you sir