couldn't have found a more useful video! i missed a lecture and when i looked at the powerpoint all i saw was numbers, but i actually understand it now!
@itthus95524 жыл бұрын
great video, I watched the lecture first before I watched these videoes, and I had to keep pausing it to think about how he got the numbers. This is so much better having it in short video. Thanks again for the great explanation! I look foward to mastering this fluids mechanics class!
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 💐💐💐
@numankashif6158 Жыл бұрын
Sir you are awesome . One of the finest videos on KZbin for fluid mechanics topic. And you have gain one more subscribers.
@CPPMechEngTutorials Жыл бұрын
Hooray!
@김찬수-i9j8 жыл бұрын
awesome! I'm the korean middle school student who has suspected about the Pascal's law for quite a long time. But because of your proof, I think i can sleep well tonight!
@CPPMechEngTutorials8 жыл бұрын
Sweet dreams!
@김찬수-i9j8 жыл бұрын
I think I almost understood the whole proof but let me give you some questions that i hardly understood. By proving P1=P2=P3, can we say that pressure is independent of direction if no shearing forces exist...? + why can we suppose that dx,dy,dz go to 0...?
@김찬수-i9j8 жыл бұрын
Sorry for bothering... but I was just curious about some parts of proof.
@CPPMechEngTutorials8 жыл бұрын
If we shrink the cube to a point in space, we find that the value of P is the same from all directions (we initially did not assume that). This implies that pressure has no preferred direction and we can treat it as a point function -- that is, pressure only depends on position in space. We say the pressure is XX Pascals at a given location, not that the pressure is XX Pascals to the left at a given location. Rather, the pressure force has a direction.
@김찬수-i9j8 жыл бұрын
CPPMechEngTutorials Got it! Thanks a lot! :)
@wolframalpha8634Ай бұрын
Sir, is there a particular reason as to why we assumed a wedge shaped fluid element to prove this? , can we prove the same using cuboidal or other eucledian elements?
@CPPMechEngTutorialsАй бұрын
The shape doesn't matter.
@willofdodge16 жыл бұрын
These videos are extremely helpful, Thank-You!
@CPPMechEngTutorials6 жыл бұрын
You're welcome!
@ralphanthonymallillin27123 жыл бұрын
I don't understand what he mean at 3:15..I'm finding answers why the back and front pressure are always separated unlike the other 3 equal pressures..Because pascal said the pressure are all equal in all direction then why does the front and back pressure are separated from the others??
@mujeebkhan097 жыл бұрын
I have one doubt...... at the end of proof, our conclusion was dependent on limit i.e dx,dy or dz approaches zero, which is correct but brings ambiguity. It could be much simplified if static equilibrium equation was applied initially as our assumption was already for static fluids, then RHS would have been zero, and then effect of differential increment in pressure due to weight of differential element could be ignored. Then things would have been much simple and easy to understand. Inclusion of acceleration, then applying limit at end brought ambiguity to a considerable extent.
@hassanaleian31114 жыл бұрын
Yes this proof states that pressure in any direction at a point is equal but it doesnt explain why. However your suggestion is to my understanding incorrect. That is because their can be non-zero acceleration and this law still holds. As long as all fluid elements accelerate at same rate there will still be no shear stress as the video suggests.
@pstark45 жыл бұрын
Hi, the description of the surface forces acting on only three surfaces "for clarity" looks like a Cauchy stress tensor. Why is it only 3 faces, nine components, rather than 6 faces, 18 components? What about bending?
@ralphanthonymallillin27123 жыл бұрын
That's also my question because pascal said that pressures in all directions but they always omit it without further explanation!!!
@arthikalexander3168 жыл бұрын
why do you particularly take a wedge or prism shaped fluid element?
@maheshk33688 жыл бұрын
I think if we use cube shape, all pressures acting on opposite sides will cancel each other except weight of fluid and no conclusion can be drawn
@CPPMechEngTutorials8 жыл бұрын
We didn't have to. A cube or any other shape would have given us the same results. A prism allows us to examine an arbitrarily shaped fluid element (notice we did not specify theta) that is relatively simple in shape.
@victormd11005 жыл бұрын
@@CPPMechEngTutorials How would prove that the pressure are equal in a fluid element shaped like a circle or an elipse (or any weird curve)? It seems that there would be many more unknowns (pressures) than equations due to all of the different directions normal to the surface
@sahalnijadv92374 жыл бұрын
6:51 pressure is actually a tensor.
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 👍💐💐
@krishnaprasadps7262 Жыл бұрын
Wow awesome session sir, it will be very helpful if you could share the presesentation slides.
@CPPMechEngTutorials Жыл бұрын
Sorry... we only have the video to share.
@gangadharvenkataramanap76517 жыл бұрын
I like you exaplaination, I understand the concept, but what should we do if we want to prove the pressure in x direction is also equal to remaining directions.
@CPPMechEngTutorials7 жыл бұрын
Use the same technique, but in the x-direction. Summation of Fx = dm*ax. The forces in the x-direction are pressure forces -- call the pressures P4 and P5 on the two faces and initially do not assume they are the same. You will find that P4 = P5 if the acceleration is 0. You would then have to use the idea discussed in Topic 2.2 that pressure only varies in the direction of gravity in a static fluid, so the pressure in the x-direction and y-direction should be the same since gravity is in the z-direction.
@bluefinsxmovies Жыл бұрын
Please I cannot stop wondering these two things Where did the sin & cos disappear to? Why did; P2dxdscosΩ become P2dxdy all of a sudden? Please I await your response
@pranavkankal56044 жыл бұрын
Great work !!! Thank you very much 😊
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 💐💐💐
@spikeoac42484 жыл бұрын
If pressure doesn't vary with direction, then how is it that in the next video you prove that pressure varies linearly in the z direction? Doesn't that disprove what you just proved in this video?
@weeskaterdude4 жыл бұрын
In considering an infinitesimal fluid element, we are approximating the pressure at a point. By Pascals law we can show that the pressure is independent of direction. This does not imply that pressure cannot vary in space and therefore it is entirely possible that we can obtain a pressure differential. Consider an open tank of water. We know that a fluid element at the bottom of the tank experiences greater pressure than an element approaching the free surface. I.e there exists a pressure gradient. We can describe this gradient via a chosen coordinate system and the result obtained would be that the pressure varies linearly in the chosen coordinate. I hope this is clear.
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 💐💐💐
@wyattblah8 жыл бұрын
This is a great explanation!
@CPPMechEngTutorials8 жыл бұрын
Great!
@siten13 жыл бұрын
Why is everything infinitesimally small(dx, dm, dv, etc) except density?
@TheFuckel Жыл бұрын
It is constant
@pankajkumar-jo5sp4 жыл бұрын
Extremely interested concept
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 💐💐💐
@dbestacademybymentorgodslo2529 Жыл бұрын
Please wat is the name of the app you are using?
@siten13 жыл бұрын
Why is Pressure not dP?
@LailaWiduri4 жыл бұрын
All I can say is THANK YOUUUUU. This video is really helpful
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 👍💐💐
@YesHerself8 жыл бұрын
nice! very well explained.thank you!
@CPPMechEngTutorials8 жыл бұрын
+teynerdy You're welcome!
@amh83036 жыл бұрын
What is the name of the reference that ur make video with? Abather the way ur good👌
@CPPMechEngTutorials6 жыл бұрын
We made these videos to be independent of any textbook. However, many textbooks have a similar derivation for Pascal's Law
@amh83036 жыл бұрын
@@CPPMechEngTutorials I meant the text book that ur follow . Because i think it is the same my lecturer going with! I had an exam this sunday .
@mujeebkhan097 жыл бұрын
amazing great job... thumbs up
@CPPMechEngTutorials7 жыл бұрын
Hooray!
@alnajdia63 жыл бұрын
You angel, you.
@thangcogang27394 жыл бұрын
thankss :>
@beoptimistic58534 жыл бұрын
kzbin.info/www/bejne/joGmmHqKbqefqLM 💐💐💐
@rahulravi6613 жыл бұрын
You just went through all that to put everything to zero? (P.S it's a troll comment , I'm an idiot 😏)