Forces on Planar Surfaces: Example 2 [Fluid Mechanics #50]

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Simmy Sigma

Simmy Sigma

Күн бұрын

Пікірлер: 61
@ravellcotora565
@ravellcotora565 8 жыл бұрын
I think FP1 is not acting on the centroid of the gate. The location of hydrostatic force is always eccentricity distance below the center of gravity of the submerged area. Correct me if I am wrong.
@ozgurderince8727
@ozgurderince8727 8 жыл бұрын
you are right
@evilsmallyy1779
@evilsmallyy1779 8 жыл бұрын
Ravell Cotora correct🙋🏻‍♂️,but it's OK if u compensate it by Fp1 & Cp
@cadprinter9678
@cadprinter9678 7 жыл бұрын
you're right, but thats not what hes saying. Watch the whole video.
@shaneyaw4542
@shaneyaw4542 3 жыл бұрын
I know this is an old video but it was very helpful. I think you did a great job explaining how to find the centroid in the y-direction.
@SimmySigma
@SimmySigma 3 жыл бұрын
I’m glad you found it helpful! 😊
@iulianmarin529
@iulianmarin529 9 жыл бұрын
Thanks man ! i finally understood... I hope i could take a good great at my tommorow test... Big LIKE !!!
@ywloveskopi-o
@ywloveskopi-o 5 жыл бұрын
very simple and clear worked solution for me. Thank you very much, need more of these
@austinsemeta
@austinsemeta 8 жыл бұрын
Very Nicely Explained and simple about a complicated matter. I have not taken the class yet but you made me understand the physics of it very well, thank you
@jeramsantos3730
@jeramsantos3730 5 жыл бұрын
Shouldn't we consider the location of the 10kN as the centroid of a triangle? Isn't the location of the centroid of a triangle is 1/3 of its base? Why did u use 1/2? Thank you :)
@memelol9816
@memelol9816 3 жыл бұрын
No you should't assume that. Look at that 10 kn, it is weight od the fate. It suppose at the centre of the inclined planed. He give 1/2 at 10 kn due to its moment at point A so it is (10kn)*(1/2 m).
@ryanhumphrey4762
@ryanhumphrey4762 8 жыл бұрын
Thank you very clear explanation. Helped me out a lot!
@zee9000_
@zee9000_ 8 жыл бұрын
can you make a video on taking moment for these type of questions pleaseee?
@deepakshukla6092
@deepakshukla6092 5 жыл бұрын
Fp1 is acting on centre of pressure which is the centroid of pressure diagram(parellelogram). Please correct.
@Johndavid1451
@Johndavid1451 3 жыл бұрын
Thanks for the explanations, really helped!
@edutechguruengineeringlear4280
@edutechguruengineeringlear4280 2 жыл бұрын
kzbin.info/www/bejne/o5C9gYWtl7ynrK8
@Haffuuuu
@Haffuuuu 8 ай бұрын
This is my exam question and i watched ur clip the night before ,🎉🎉🎉🎉😊😊😊😊
@RaymartGDamot
@RaymartGDamot 6 жыл бұрын
Sir, why did you consider the weight of a gate but to your other example you did not put the weight of a gate? Please enlighten me
@hizamshahrusmi
@hizamshahrusmi 9 жыл бұрын
Great vid mate. Just 1 question, are you assumming the position of F1 acting at the centroid of the gate due to simplication? Due to trapezoid pressure prism, I think we should determine the position of F1 which is Ycp.
@Portedrea
@Portedrea 9 жыл бұрын
+Ezam Shah One can either use the centre of pressure (i.e. finding where the resultant acts along the gate), or the force along the centroid added with a couple.
@Optimokutta
@Optimokutta 8 жыл бұрын
Thank you very much for these videos! They are very helpful :)
@MrAngbarako
@MrAngbarako 6 жыл бұрын
Good day! Why there is no pressure at point B in the free body diagram? Thank you very much!
@syedahzam6925
@syedahzam6925 7 жыл бұрын
if we dont take fp1 at centroid of surface but take it at centroid of pressure profile then what would be the Y(r) ..since Y(c)=1 then Y(r)=1.66?????
@amazonmarketplace
@amazonmarketplace 10 жыл бұрын
For Fp1 should you have a sin60 in there?
@cadprinter9678
@cadprinter9678 7 жыл бұрын
He already factored in sin60 lololol sqrt(3)/2.
@edwardgomez9921
@edwardgomez9921 9 жыл бұрын
Would be great if you do it with the pressure prism method!!! You explain it well
@MH-ix2nh
@MH-ix2nh 4 жыл бұрын
that should be (3/2)*sqrt(3) for cos beta right?
@valeriarodriguezpatino1101
@valeriarodriguezpatino1101 6 жыл бұрын
I didn't understand what was Cp and why did you take it in count on the moments of A?
@ibrahimakpnar1845
@ibrahimakpnar1845 4 жыл бұрын
did you find the why he got cp my friend
@athena04nymph77
@athena04nymph77 9 жыл бұрын
How can you solve the weight of the gate if it is not given? Thanks.
@101591i
@101591i 11 жыл бұрын
I'm having trouble understanding how you got Ix how did you get it to equal (1/12*2*2^3)
@methuselahinmelchizedek9583
@methuselahinmelchizedek9583 7 жыл бұрын
thats the formula for moment of inertia of a rectangular shape
@toxicevilking2945
@toxicevilking2945 Жыл бұрын
U alive? I love ur videos it's helped me a lot❤
@yallaskate
@yallaskate 9 жыл бұрын
very good, thanks m8
@JEN-jo4qu
@JEN-jo4qu 9 жыл бұрын
very helpful video
@sallyalmufti9492
@sallyalmufti9492 7 жыл бұрын
p= density *g multiply h ,why you did not plug in the density over there ?
@reembassim4359
@reembassim4359 7 жыл бұрын
sally almufti he's using specific gravity instead of density*g, (1000)(9.81)=9.81kN•m/s^2
@reembassim4359
@reembassim4359 7 жыл бұрын
Sorry kn/m^3
@domeaquin6003
@domeaquin6003 6 жыл бұрын
Isn't the area of Fp2 1*2? you are using 2*2
@SaiTama-kf7lw
@SaiTama-kf7lw 3 жыл бұрын
why is it theres a couple?
@short_physics
@short_physics 9 жыл бұрын
nice lec ...thanks...
@petter9078
@petter9078 7 жыл бұрын
Hmm nice video. However I solve this in a much smoother way!
@kelvin4845
@kelvin4845 8 жыл бұрын
what if there is water on both side with the gate is in between, how to solve?
@augusttoday
@augusttoday 5 жыл бұрын
I did a problem like this before. The free body diagram would have more forces acting on the left side and the right side, I had to make 2 free body diagrams to do it one for the left side and one for the right side because the center of pressures were different because of the angle that the gate is tilted at. It was a confusing problem. It also depends on the heights of the water on both sides, because the pressure would be different if the heights of the water were different via density times height times gravity.
@RohitKumar-hf1vv
@RohitKumar-hf1vv 5 жыл бұрын
Nice
@fonjockazenju5754
@fonjockazenju5754 2 жыл бұрын
Pressure = density×g×depth but he didn't include the density when finding Fp
@lisro21
@lisro21 10 жыл бұрын
you are good
@ILikeWeatherGuy
@ILikeWeatherGuy 7 жыл бұрын
nice video! :D
@ratnafatinahbintimohammadb4277
@ratnafatinahbintimohammadb4277 5 жыл бұрын
sorry bro i aint get it... somehow yours i feel complicated
@حسينعائدخشانالخزاعي
@حسينعائدخشانالخزاعي 3 жыл бұрын
Source
@edutechguruengineeringlear4280
@edutechguruengineeringlear4280 2 жыл бұрын
kzbin.info/www/bejne/o5C9gYWtl7ynrK8
@tristanjeff1520
@tristanjeff1520 6 жыл бұрын
your hbar from fp1 is wrong
@jcp6092
@jcp6092 3 жыл бұрын
This solution is wrong!!! The resultant of the diagonal pressure distribution is to be applied below the centroid of that portion of the gate...
@edutechguruengineeringlear4280
@edutechguruengineeringlear4280 2 жыл бұрын
kzbin.info/www/bejne/o5C9gYWtl7ynrK8
@طالالانتظار-ي1م
@طالالانتظار-ي1م 6 жыл бұрын
السلام عليكم اريد نفس هذا الشرح بالعربي الي يعرف لا يقصر الله يوفقكم 🌸🌸
@pinkhead6857890
@pinkhead6857890 3 жыл бұрын
Why do all that free body diagram Phd shit when you can just draw a vertical line at point B and then takeoff the volume?
@edutechguruengineeringlear4280
@edutechguruengineeringlear4280 2 жыл бұрын
kzbin.info/www/bejne/o5C9gYWtl7ynrK8
@ziadd6874
@ziadd6874 10 жыл бұрын
the moment of Inertia is always (1/12)x(base)x(height)^3
@sassyach
@sassyach 9 жыл бұрын
Depends upon the geometrical shape nigga
@rogerarbizo1242
@rogerarbizo1242 7 жыл бұрын
yeah what my nigga sass said, depends on what geometrical figure ya dealing with ya dig.
@leonardouchiha1137
@leonardouchiha1137 6 жыл бұрын
Ziad D Sad that you acted like you are the only smartass student who's still alive but can't analyze properly and carefully, then bitching someone who is smarter than you.
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