Four charges equal to `-Q` are placed at the four corners fo a square and a charge `q

Four charges equal to `-Q` are placed at the four corners fo a square and a charge `q` is at its centre, If the system is in equilibrium the value of `q` si

[@BabitaKannaujiya-g7z]

Pehli bar aisa video mila jo detail me hai ..thanks for this bro..

[@AdarshRajsahu-s9n]

This is the first video of doubtnut in my life which I could understand problem with all the concepts 😅😅

[@SYCORAX_YT]

Exam kaisa gya

[@skdpriyanshu491]

Majduri se h duri...Mr star h jaruri🌟 We know that the net force of a system is zero, so by calculating the option of question.. in whichever option is 0, that will be Answer... . For direction.. System in equlibrium means..? q present inside the Square is in rest.. Thats q oppose the Q . and here -Q present at the corner...means.small.q will be..-q.. thats Solve .....

[@skdpriyanshu491]

sorry, Printing mistake...small q will be...+q

[@shakiibbbb]

@@skdpriyanshu491 yaaa🙃🙃

[@kusumdhull3002]

-Q,-Q repel each other so how u take the direction from one -Q charge towards the another -Q charge

[@kunalnaval7370]

🤣neet nahi nikla na abhi bhi tera?

[@kusumdhull3002]

@@kunalnaval7370 neet to nhi nikla pr jee nikal gya

[@RedLunchBox]

​@@kusumdhull3002bhai charge equil pe hain to har charge pe net force 0 hoga +- ka concept isme na lagega itne na jane kya kiya

[@RedLunchBox]

And nevertheless -Q aur -Q ko sahi liya hai in the sense f vector hai

[@nongoddd]

​@@kusumdhull3002Perfect reply 😭😂🛐

[@naveenyasoju3463]

Thank you sirrrr...,radhe radheshyam seh miladeee,jai shreeekrishnnn❤

[@rtgamer48]

This is my first video on doubtnut which I understand properly 😅😅😅

[@Cricketxlove18]

How did it become Q/4 it should be Q/2??

[@sridevi-l9v]

Thank u sir

[@atmiya7849]

we praise ur efforts sir.

[@gauravmishra9459]

4:06 yaha Q ka -sign kyu kha gaye. ???

[@Praxanta]

Thank you ❤😊

[@asthapatel7308]

Good explanation

[@Samreen464naaz]

Jethalal padha rhe hai

[@Mushasi_the_legend]

Can any one please explain how root2 came on resultant

[@satejgujar3023]

F1=F1 i.e KQ²÷a² therefore resultant=under root KQ²÷a²×2 [because Resultant is addition of vector therefore F1+F1=2F1[F1 is KQ²÷a²]Substitute value of F1 You will get under root 2 F1

[@nongoddd]

Sir earned my respect

[@futurepassion5966]

Thank you

[@NerdSaiyadOfficial]

Thanks sir

[@abhiroopplays1081]

[@kanishk5366]

Thank you sir

[@Sangeeta_m17]

why f3 is positive it should be negative because one is negative and other is positive

[@gargshourya005]

We take magnitude because we are applying coulombs law

[@eshanpcbl]

😢golden days of Doubtnut 😢

[@Priya-singh-01]

🎉🎉🎉🎉🎉

[@anvisharma3203]

Thanku sir...🌟

[@maniratan4984]

Ans. A hoga

[@rajankushwaha3801]

I love yoyyyy