Fourier's Law of Heat Conduction For Hollow Cylinder | Conduction

Fourier's Law of Heat Conduction For Hollow Cylinder | Conduction | Heat Transfer |

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Impact Academy Official

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@davidpinto5042 4 жыл бұрын

Thanks for the explanation ! Very well taught. Keep on the good work !

@ImpactAcademyOfficial 4 жыл бұрын

Thank you...

@divyadivi_vlogs 3 жыл бұрын

Easy and clear explanation, thank you sir🤗

@ImpactAcademyOfficial 3 жыл бұрын

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@adarshas6449 4 жыл бұрын

Sir i am a bpharm student from kerala.... your explanation made me to understamd fouriers law for hollow cylinder perfect

@ImpactAcademyOfficial 4 жыл бұрын

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@brysondenver6406 3 жыл бұрын

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@yadfaruq5294 5 жыл бұрын

thank you so much for your information, the best explanation ever! ❤️❤️❤️❤️👏👏👏👏👍👍👍👍👍

@ImpactAcademyOfficial 5 жыл бұрын

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@روشنیسبکےلئے-ث9ن 5 жыл бұрын

wah wah... very nice explanation

@ImpactAcademyOfficial 5 жыл бұрын

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@indianpoliticalhub4672 5 жыл бұрын

Sir aap explain bhut acaha karte h

@ImpactAcademyOfficial 4 жыл бұрын

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@kaif749 5 жыл бұрын

Your tecaching method is best sir

@ImpactAcademyOfficial 5 жыл бұрын

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@blackshirtguy. 5 жыл бұрын

Well explain

@ImpactAcademyOfficial 5 жыл бұрын

Thanks Kakathiya University Wrngl...👍👍👍

@soumenkar1008 4 жыл бұрын

Great work sir ... Simply explained..

@ImpactAcademyOfficial 4 жыл бұрын

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@shahdomer8507 2 жыл бұрын

Thank you very much sir i was so confused about it

@ImpactAcademyOfficial Жыл бұрын

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@sigmarulers9861 5 жыл бұрын

Good explain

@ImpactAcademyOfficial 4 жыл бұрын

@sajiddudekula8941 2 жыл бұрын

amazing explanation sir , your videos are really helpful to my academics sir .

@ImpactAcademyOfficial 2 жыл бұрын

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@thuhinulislam6965 5 жыл бұрын

khub upokar hoilo :3

@ImpactAcademyOfficial 5 жыл бұрын

Thanks Thuhinul Islam and do share it amongst your family and friends👍👍👍

@r.barbhuiya1726 5 жыл бұрын

Good lecture

@ImpactAcademyOfficial 5 жыл бұрын

Thank You...

@kaursingh637 5 жыл бұрын

thank u sir for excellent lecture

@ImpactAcademyOfficial 5 жыл бұрын

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@Imaandaaree Ай бұрын

Thank you so much sir 👍👍

@ImpactAcademyOfficial Ай бұрын

Thanks for watching👍👍 Subscribe to our channel to get the latest updates about our videos...!!! If you also want to take offline or online lectures or join classes... Kindly call on this number Zafar sir : 7666456011

@pulkitsahu154 2 жыл бұрын

Sir please make a playlist of applied thermodynamics separetely

@ImpactAcademyOfficial 2 жыл бұрын

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@yashraut9394 4 жыл бұрын

Grate explanation sir👌

@ImpactAcademyOfficial 4 жыл бұрын

@shashanktyagi6485 5 жыл бұрын

Thankyou sir explain very nice

@ImpactAcademyOfficial 5 жыл бұрын

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@thenextoneisreallylong8587 4 жыл бұрын

this helped me a lot, thanks

@ImpactAcademyOfficial 4 жыл бұрын

Welcome👍👍👍

@hussainkareem5376 3 жыл бұрын

thank you so much for your information Please, I want to clarify and solve this question, and there is no question in question m and T A counterflow double-pipe heat exchanger is used to heat liquid ammonia from 10 to 30◦C with hot water that enters the exchanger at 60◦C. The flow rate of the water is 5.0 kg/s and the overall heat-transfer coefficient is 800 W/m2 · ◦C. The area of the heat exchanger is 30 m2. Calculate the flow rate of ammonia

@ImpactAcademyOfficial 3 жыл бұрын

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@rajinderduggal5954 6 жыл бұрын

Great sir

@ImpactAcademyOfficial 6 жыл бұрын

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@harshaarjun9366 4 жыл бұрын

Can u explain the topic for gate as well as ese point of view

@ImpactAcademyOfficial 4 жыл бұрын

@navdeep4301 4 жыл бұрын

Sir,why there is need to wrote thermal resistance in this derivation even we have solved the general equation for hollow cylinder?

@ImpactAcademyOfficial 4 жыл бұрын

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@indianpoliticalhub4672 5 жыл бұрын

Thanks you so much sir

@ImpactAcademyOfficial 4 жыл бұрын

@suryasingh9526 4 жыл бұрын

Sir at 5:00 why the area is not cross sectional as the area must always be the cross sectional ??

@ImpactAcademyOfficial 4 жыл бұрын

@atultiwary2767 5 жыл бұрын

thank u sir

@ImpactAcademyOfficial 4 жыл бұрын

@DarkSlayerphlc 5 жыл бұрын

Thank you very much!!!!!!!!!!!

@ImpactAcademyOfficial 4 жыл бұрын

@tanmoysamanta5654 5 жыл бұрын

Thank you sir.

@ImpactAcademyOfficial 4 жыл бұрын

@johndevilbiss6607 5 жыл бұрын

Sir, WHAT ABOUT the heat (current) leaving or entering FROM THE ENDS of such a cylinder? Perhaps a mention that the cylinder is capped such that there is no heat transfer through the ends, or that it is like a long cylinder and the equation assumes heat flow only happens through the walls, because there's no gradient of temperature at the ends. Please reply, if you are still attentive to comments.

@ImpactAcademyOfficial 4 жыл бұрын

@Deepakkumar-vt4iy 4 жыл бұрын

Negative sign kaisa yaha

@ImpactAcademyOfficial 4 жыл бұрын

@davidmoore6097 3 жыл бұрын

thx

@ImpactAcademyOfficial 3 жыл бұрын

@shivankpayasi840 5 жыл бұрын

Best or worst i cant choose

@shivankpayasi840 5 жыл бұрын

Then keep ur mouth shut

@ImpactAcademyOfficial 4 жыл бұрын

@bharatsinhchavda8268 5 жыл бұрын

Sir book to general equation for cylinder aapelu se bakavas

@ImpactAcademyOfficial 4 жыл бұрын

@sarthakrautela4738 6 жыл бұрын

Sir the video is wrong. The method used is right but you have written - KAdt/dx as Q(heat) instead of H( heat current), and have made the same mistake throughout the video.

@ImpactAcademyOfficial 6 жыл бұрын

No...it is not wrong..the heat transfer due to temperature difference is denoted as "Q"...here there is a comparison between Electrical and Thermal method.

@mayurrane6673 5 жыл бұрын

Go home kid..this is not for u

@advance_parvej 5 жыл бұрын

Q=Rate of heat flow through a conductor. Bro ,sir is right.

@jyotishmank6999 Ай бұрын

Rate of heat is discussed just wrote Q

@Imran-qb6qq 6 ай бұрын

Too many ads

@ImpactAcademyOfficial 6 ай бұрын

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