France math olympiad question

[@roger7341]

Using Euler's equation, the answer in one line: √2e^(iπ/4), √2e^(i3π/4), √2e^(i5π/4), and √2e^(i7π/4) Converting to complex form: (1+i), (-1+i), (-1-i), and (1,-i)

[@MartinMllerSkarbiniksPedersen]

I dont believe this a olympia question. Too easy

[@rammyrawat8077]

Why can't we say √2iota please someone tell me

[@Qwerty25414]

i^4 will be 1 not -1

[@rammyrawat8077]

@@Qwerty25414 it under root iota