Frequency of each element in an integer array | Brute force | JAVA interview question

[@AkashYadav-tc2lo]

very well explained. Thanks, but still i have a confusion on why we have stored visited in arr[j] ??

[@TechnosageLearning]

We have set freq[j] = visited....because we have already updated the count of that element(freq[j]) and we dont want to visit that element again Otherwise same element's frequency will be updated again and again and it wont provide the required result.

[@kalpshah2070]

i have doubt related that you have print elements and their frequency for unique elements that not visited but what about that elements that stored in freq[j] how they print?

[@rajrawat6376]

How to do it if time complexity O(N) using brute force

[@TechnosageLearning]

kzbin.info/www/bejne/pqu0p359mN-YaaM Checkout this video

[@rajrawat6376]

@@TechnosageLearning yeah i hve checked out this but the concept of has map isn't thought to us yet so i was asking if there was any other way

[@mdaquibahmed3567]

Well explained maam

[@politics2198]

very Awesome explaination.

[@TechnosageLearning]

Thank you!

[@myviewyt3332]

Well explained

[@NirajKumar-n9f2d]

public class count { public static void main(String[]args){ int []arr={1,2,3,4,2,2,3,1}; int []freq=new int[arr.length]; int visited = -1; for(int i=0;i

[@basithnizam]

what will happen if the give array has value of visited that is "-1"

[@yashas1322]

it will not print(exclude)

[@mdhasanuzzaman6963]

according to above logic it will getting the draw back

[@samdarsh3795]

Well explained mam 👍

[@TechnosageLearning]

Thank you😊

[@Riteshpc-c3x]

thanks

[@Caped_Crusader7]

why visited = -1?

[@ImrojShaik-l4c]

same as the code in the internet

[@supriya_codes]

which screen recorder u r using??

[@TechnosageLearning]

Default Mac screen capture tool

[@naushadalam5129]

8 2 0 1 1 1 0 3 1 ans=2 4 1 1 code output=2 4 1 0 how can i handle this case

[@naushadalam5129]

after sorting array