Frequently Asked Java Program 05: Palindrome String | How to Check Given String is Palindrome or Not

Topics :
---
1) Palindrome String
2) How to Check Given String is Palindrome or Not
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#PalindromeCheck
#StringPalindrome
#PalindromeTesting
#PalindromeOrNot
#CheckPalindrome
#StringReverse
#PalindromeAlgorithm
#PalindromeLogic
#PalindromeValidation
#PalindromeAnalysis
#StringMirror
#PalindromeVerification
#PalindromeString
#StringSymmetry
#PalindromeProcedure
#PalindromeEvaluation
#StringIsPalindrome
#PalindromeSolution
#PalindromeApproach
#StringPalingram
#PalindromeInspection
#StringIsMirror
#PalindromeExploration
#PalindromeResolution
#StringPaliCheck
#PalindromeProcess
#StringPalindromeTest
#PalindromeExamination
#StringReverseCheck
#PalindromeAssessment
#PalindromeMethod
#StringPaliValidation
#PalindromeInquiry
#StringPalindromeCheck
#PalindromeDetermination
#PalindromeAnalyze
#StringIsMirrorCheck
#PalindromeInvestigation
#StringPaliVerify
#PalindromeProcedure
#StringPalindromeAnalysis
#PalindromeInspection
#StringReverseValidation
#PalindromeEfficacy
#StringPaliAssessment
#PalindromeStudy
#StringIsPalindromeTest
#PalindromeReview

[@taqdmageranger]

So quick and easy, thank you so much!!

[@sdetpavan]

Welcome

[@gauri992]

You explain it the best way thanks a lot sir...

[@sdetpavan]

Welcome

[@krikusin2198]

import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String s = in.nextLine(); String s1 = s; String rev = ""; int length = s.length(); for (int i = length - 1; i >= 0; i--) { rev = rev + s.charAt(i); } if (s1.equals(rev)) { System.out.println("YES"); } else System.out.println("NO"); } }

[@arabindamohanty2190]

Thanks a lot for such informative video class thanks a lot.......

[@sdetpavan]

Welcome

[@gudasairamreddy6650]

in Java you can’t use == operator for string comparisons i tried it == it was not working the if loop i was getiting error for 2 hours then i changed it to .equals then it worked i was about to doubt on my self that iam not for coding finally i got it

[@richaprakash3807]

Yes u r correct

[@klevialushi571]

Thanks, i was learnt with C++ where you could do 'if( cond1 == cond2 )' and in Java i was getting No, even though the answer was supposed to be Yes, because i was inserting a Palindrome, but when i used .equals() then the program was working fine. Weird, but thanks!

[@adulapuramakhil871]

Same happened to me in java. What might be the reason? Do you know?

[@vansh9857]

Had same error

[@shraddhaprabhu9033]

Had same error how to fix it if it is palindrome also it is showing not palindrome

[@azartamboli6687]

Bcoz in java string class double equal operator is made for ref comparison....and equals() method used for content conparision

[@praveenkumarkappala6912]

Thank you very much sir, I got job because of UR frequently asked questions Playlist as java developer videos

[@user-oc1bd8lu1d]

really

[@akshatmangal9667]

Thank you sir for wonderful explanation

[@sdetpavan]

You are most welcome

[@kennyi1200]

good.. It is better to use if(org_string.equalsIgnoreCase(reverseString)) .. rather than .equals(str) otherwise for Pop => it will give not a palindrome string because of UpperCase..

[@inchara-y6q]

sir how to reverse a array that are separated by spaces and other special characters

[@sachinkharwar3164]

Sir we can not use == operator to compare string

[@michaelkeanucortez2173]

How can we do it with multiple strings?

[@nonegirl112]

I think These all programs will help me to crack the job in future

[@redhoodiepro8173]

How can you solve a palindrome string for Boolean? For instance: public boolean isPalindrome(string s)

[@rumanir]

Excellent .Please can you add few interview program for collections

[@rajatdwivedi6574]

Java basic concepts kzbin.info/www/bejne/g5malaualMaSZsk

[@dianahalunko5872]

I want do it for 3 strings, how i can do it?

[@ShivamSingh-gc6pm]

Thanku sir ji🙏.

[@sdetpavan]

Welcome

[@balapramothc.m.]

vara level🥳

[@sdetpavan]

Thanks

[@vinodthube4853]

In Java you can’t use == operator for string comparisons .. it’s not recommended..rather use .equal method

[@adulapuramakhil871]

Yes, thanks for the information

[@amanmahato3897]

Thank you

[@KaranSharma-lm6eh]

i just learnt it now, that's why my program has been failing, thanks a lot for this input. I appreciate it !

[@neelirahul7892]

Hey because of you I learnt a great thing . Thanks a bunch ❤️

[@JannatulFerdous-mh6zt]

I use .equalignorecase method

[@nishantjalkotkar710]

In 'if' statement "== "operator will Not work as it checks d address, besides equal method checks values.

[@Itachibatman]

thanks sir 🥺

[@sdetpavan]

Most welcome

[@arunkumartirumala2852]

It doesnt work if we use both uppercase and lowercase at a time

[@madhurgoyal2908]

we can use str directly instead taking org = str

[@ShubhamSharma-to5po]

hello sir, i used stringbuilder class but it not giving correct result. public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("enter your string:"); String str = sc.next(); //String org_str = str; StringBuilder org_str = new StringBuilder(str); StringBuilder sb = new StringBuilder(str); StringBuilder rev_str = sb.reverse(); System.out.println(rev_str); System.out.println(org_str); if(org_str.equals(rev_str)) { System.out.println("string is palindrome"); }else { System.out.println("string is not palindorme"); } }

[@charanbudama2601]

looks like line 12 is not required as we are not changing the original string unlike number

[@BhaveshPanchal]

What will we do if we write Madam instead of MADAM ? it showing as not palindrom.. How to ignore camel casing ?

[@subhasishbagchi8902]

TRY equalsIgnoreCase Method

[@gayathridhana1000]

Please do some dsa tutorial

[@poojak352]

It's better to use equalsignorecase 😊

[@EdClarkHYCT]

Palindrome Descendant Java Coding Challenge | How'd You Code That? | Episode 18

[@nivedhavaithi5478]

i have tried as same above, but while i compiled there is no error, while getting output even the palindrome string was saying like not a palindrome. How to resolve this sir? Kindly help me

[@prashanthm134]

In for loop use i>=0. If you don't give equals you will not get.

[@srinidhis2784]

Don't give gap between double col..where rev=""don't give gap between them

[@sanghamitramishra6169]

@@srinidhis2784 thanks..This worked

[@sathishvuggam]

java eclipse important

[@jayaprakash-ql3ip]

1k like by me ☺️

[@luzheso]

In Java you can't use "==" operator for string comparisons, rather use ".equals()" method.

[@Naruto-ts4cr]

5:10 Summary

[@EnzoSwizz98]

try this program.......... it will work fine to check PALINDROME OR NOT both for number and a string ... import java.util.*; class StrPalindrome{ public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("Enter a string: "); String str=sc.next(); String original=str; String reverse=""; StringBuffer sb=new StringBuffer(str); sb.reverse(); reverse=sb.toString(); if(reverse.equalsIgnoreCase(original)) System.out.println("PALINDROME"); else System.out.println("NOT PALINDROME"); } }

[@smitpatel6218]

Can anyone do it for number also?

[@yamunachamilall2709]

check "smart programming" ,it has for number also

[@annalakshmi9802]

public class reversenum{ public static void main(String[] args){ Scanner sc=new Scanner(System.in); S.o.p("Enter a number:"); int num=sc.nextInt(); int org_num=num; int rev=0; while(num!=0){ rev=rev*10+num%10; num=num/10; } if(org_num==rev){ S.o.p(+org_num+"is Palindrome"); } else { S.o.p(+org_num+"is not a Palindrome"); } } }

[@smitpatel6218]

@@annalakshmi9802 thank you

[@monu8524]

Sir ye saare video aap hindi me bhi banaiye.