Frequently Asked Java Program 26: How To Count Occurrences of a Character in a String

[@shakulhameed1767]

we simply sovle the problem like int count =s.replaceAll("[^a]","").length();

[@ayushpandeyg]

That's professional 👍👍

[@j_j8758]

Wowww that was good!

[@Himu421]

Amazing video sir ! You code in such simple way and explain it so well that any basic /intermediate base person can fully grasp the concept and learn coding.

[@sdetpavan]

Thanks

[@nayabshaik2282]

I was very scary to make understand coding earlier. But once I started watching your videos, my thought process changed. I am very comfortable to understand your logics, I feel like "OH CODING IS SUCH SIMPLE" 😄🤣 Great Thank you Pavan sir..🤝🤝🙏🙏

[@CareerHirings]

why writing this much complex...i dont know............ we can write in this way too String s="yash is a good boy "; char comp='a'; int flag=0; for(int i=0;i

[@akadeadahot7067]

this method is also easy check it guys' String str="java programming is very easy"; int count=0; for(int i=0;i

[@janetbawuah8981]

thanks it worked.

[@udaybenake206]

This is working but does not count uppercase characters if we are pass lowercase or vice versa

[@TheCrazyRitik]

@@udaybenake206 because java is case sensitive A and a both are different

[@f.a5148]

@@udaybenake206 use this for Upper case or lower case: if(str.charAt(i)=='a' || str.charAt(i) == 'A')

[@f.a5148]

thanks man this is much easier.

[@AaminaSadiya-v5e]

Superb easy to understand sir...thanks a lot for helping us.

[@sdetpavan]

Welcome

[@Canada1989]

This was asked in my interview

[@Nmx7428]

This is asked in my interview too with 5year experience

[@Shreenidhi110]

Thank you so much,very easy way to understand

[@sdetpavan]

Welcome

[@pakkaandhrapori3768]

Thanks for easy explanation and can we do the same program without "replace" method? please explain the approach as well

[@bharathkoneru4008]

We can do it by converting the given String to character array and then search for element. Increment the count when the element is found.

[@suprem3g4mer6]

@@bharathkoneru4008 how

[@emmadivamshi1798]

Sir Your explanation is very nice and am very thankful to you sir

[@sdetpavan]

It's my pleasure

[@rameshtirneddi5624]

if we get string from the user then how to get max occuring character

[@abinayabala6868]

can u tell me how to check for all the character occurence

[@swayamprakashbhuyan2580]

Love your videos and commenting for better reach. You have a great voice btw.

[@sdetpavan]

Thanks

[@vikramsinghyadav7793]

Sir we can use Hashmap that would be more efficient

[@tejajami6729]

import java.util.Arrays; class OccrenceOfInputArray { public static void main(String[] args) { int arr[] = {1, 1, 2, 2, 3, 4, 5, 6, 8, 9}; int len = arr.length; System.out.println("Total length: " + len); String arrString = Arrays.toString(arr); // Replace '2' with an empty string and get the length int totalCount = len - arrString.replace("2", "").length(); System.out.println("Total count of 2: " + totalCount); } } sir, while im running this program after removing the 2 we got the output is 8, but here output is getting is: -18..........please clarify this doubt sir

[@hemrajpatil782]

very easy sir.thank u. sir can u please make programm for prime no. from array ..please sir .

[@SaisowmyaPriya]

hi sir can we use this method is scanner sirif yes can u tell me how to use it

[@v2factsand327]

Excellent explanation

[@sdetpavan]

Glad it was helpful!

[@rizwanreshi8673]

Sir what about when there are same letter with upper and lower case.

[@vladshome]

you can use the ".toLowerCase()" method on the string, before removing the character you're counting. it will make the whole String lowercase

Tell for all character occurences. For all occurences it will become a very exhausting code

[@vithvishnu1497]

Can i get this in loop.. if yes can u comment the statement..

[@udaybenake206]

This is working but does not count uppercase characters if we are pass lowercase or vice versa

[@rohanmane7423]

Do s=s.toLowerCase(); /toUpperCase();

[@MB-zt7cd]

Nice explanation however I am bit confused, as we count the spaces as well in index., So when we are replacing a with space, the space would still be counted. so not sure how did it work. Could you please explain the logic for that. Thank you

[@avinashhr]

He is not replacing with space its null.

[@bharathkoneru4008]

Its not replacing with space, a is replaced with empty(""). space means " " empty means ""

[@pawan_288]

good

[@osaimurari3485]

burra padu sir!

[@gayathridhana1000]

sir please make more interview programs

[@NiteshKumar-vz8uy]

This question asked me today

[@ravindrakawale5161]

Great explain....🙌🙌

[@sdetpavan]

Glad it was helpful!

[@vs4084]

Thankyou sir for this video...

[@sdetpavan]

Most welcome

[@shraddhaprabhu9033]

Sir make program video of duplicate characters in a string

[@zishanalam8277]

What about no case sensitive

[@krishdeepika6967]

Not working giving output as zero

[@kvnagendra5354]

Nice explanation

[@sdetpavan]

Thanks

[@magicalmagie2889]

Sir y u removing a es

[@groundlevel1817]

impressive.

[@sdetpavan]

thanks

[@ananya8672]

not a good approach

[@iliveinacrowdedhouse368]

Bonne vidéo

[@bidya74]

corrupted

[@kvelez]

import java.util.HashMap; import java.util.Scanner; public class Main { public static void main(String[] args) { System.out.print(" Enter a statement: "); Scanner scan = new Scanner(System.in); String statement = scan.nextLine(); scan.close(); String[] words = statement.split("\\s+"); HashMap wordHashMap = new HashMap(); HashMap letterHashMap = new HashMap(); for (int i = 0; i < statement.length(); i++){ char currentChar = statement.charAt(i); if (letterHashMap.containsKey(currentChar)){ letterHashMap.put(currentChar, letterHashMap.get(currentChar) + 1); } else { letterHashMap.put(currentChar, 1); } } for (Character letter : letterHashMap.keySet()){ int count = letterHashMap.get(letter); System.out.println("Letter: " + letter + " appears " + count + " times."); } for (String word : words){ if (wordHashMap.containsKey(word)){ wordHashMap.put(word, wordHashMap.get(word) + 1); } else { wordHashMap.put(word, 1); } } for (String item : wordHashMap.keySet()){ int count = wordHashMap.get(item); System.out.println("Word: " + item + " appears: " + count + " times."); } } }

[@MAGAVISHNUT]

This for known statement.. Then what is code for when we use scanner Class