Function Pointers in C / C++

See complete series on pointers here:
• Pointers in C/C++
In this lesson, we have explained the concept of function pointers and shown how you can create and use function pointers in C or C++.
Feel free to drop your comments, feedback and suggestions.
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char* means you have a data type that is pointer to character. Is this what you want to know? At what time in the video are you confused?

[@rakeshramesh9248]

Name is ptr variable its expecting a address.. how are we passing a string then? Can someone explain?

[@njegostrajkovic4451]

​@@rakeshramesh9248 String is implemented as an array of characters in C. When you forward an array to a function, you actually forward the address of the first element of that array. So, &array[0] = array in C. In this case, you just forward the address of the first element of the array of characters, and that is your String.

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@@njegostrajkovic4451 Did you mean &array[0] == array instead of &array[0] = array?

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@@gammyhorse yea he was basically trying to say that &array[0] and array are equivalent and can be used interchangebly

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[@bing4229]

Hello, i have the same problem to understand void (*ptr)(char*). pointer function expects for an address as argument, but when it gets the address of "Tom", should in void function as output like this :printf("Hello %s " , *name); why here no * for name. thank you.

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I don't understand what you did in the last. How can char* which is pointer to char store string tom??

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For example at 11:50, under main you have void (*ptr)(char*); I don't understand why the asterisk is following the char, yet it's before the ptr. Thank you.

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here ptr is pointer variable and char is pointer datatype.

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[@ShopperPlug]

This is interesting, creating "function pointers" which are pointing to a function's address. Never knew such concept existed. I have a question, does it matter if the function pointer points to the function prototype or function definition? Thanks.

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nicely explained.. subtitles makes us understand more clearly.☺

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[@royceguo9675]

In C, it's allowed primarily because there's not much else the name of a function, by itself, could mean. All you can do with an actual function is call it. If you're not calling it, the only thing you can do is take the address. Since there's no ambiguity, any time a function name isn't followed by a ( to signify a call to the function, the name evaluates to the address of the function. --recite from stackoverflow

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*My takeaways:* 1. What is a function pointer 1:30 2. How to create a function pointer 6:25 3. Function pointer vs function that returns a pointer 8:39

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thank u sir u have cleared my doubts bt one thing i haven't understood is that why have u changed c to *ptr in main if we use *c then what will be the difference

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You are taking a pointer to a string "Tom". I did not understood how is it printing without using a loop?

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Roxxane Bcs he used %s, which means print all characters until u see'\0'.

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Conversion of string to char* is not allowed in C++, so this works void printNum(const char* a){ cout

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Doubt at 11:10, How come PrintHello acts as a call to function without having the brackets at the end () needed to define a function. Also at 11:36 how is "Tom" getting printed.

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Great Video and good explanation! But why do we use function pointers?

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then about the void function generally we store the pointers in the integer format then what should we do???