L-2.8: Pre-emptive Priority Scheduling Algorithm with Example | Operating System

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[@itsjamal96]

If the same example solved by the same method with mode: non-preemptive then it would be more clear and effective to be learned and understood. My suggestion is that add a link where the same question is being solved through this priority algorithm with mode: non-preemptive to differentiate between them clearly. And it would be easy to identify the effectiveness of preemption during the execution. The rest of the question is explained very well and easy to understand. Thank you

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[@DrAmitabhaYadav]

Consider a pre-emptive priority based scheduling algorithm based on dynamically changing priority. Larger priority number implies higher priority. When the process is waiting for CPU in the ready queue (but not yet started execution), its priority changes at a rate a = 2. When it starts running, its priority changes at a rate b = 1. All the processes are assigned priority value 0 when they enter ready queue. Assume that the following processes want to execute: Process ID Arrival Time Service Time P1 0 4 P2 1 1 P3 2 2 P4 3 1 The time quantum q = 1. When two processes want to join ready queue simultaneously, the process which has not executed recently is given priority. The finish time of processes P1, P2, P3 and P4 will respectively be

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[@shallubajaj951]

Consider a pre-emptive priority based scheduling algorithm based on dynamically changing priority. Larger priority number implies higher priority. When the process is waiting for CPU in the ready queue (but not yet started execution), its priority changes at a rate a = 2. When it starts running, its priority changes at a rate b = 1. All the processes are assigned priority value 0 when they enter ready queue. Assume that the following processes want to execute: Process Arrival Service ID Time Time P1 0 4 P2 1 1 P3 2 2 P4 3 1 The time quantum q = 1. When two processes want to join ready queue simultaneously, the process which has not executed recently is given priority. The finish time of processes P1, P2, P3 are..Plz make a video solving this question..

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//Primitive-priority scheduling algorithm implementation using c program #include #include int jtime = 0; int counter; int n; int at[20], bt[20], ct[20], pt[20], sts[20]; void process_Ps() { int index = -1; // variable for storing the index of the process with the highest priority int highestPriority = INT_MAX; // set the highest priority to the maximum possible value // Check all incomplete processes for (int i = 0; i < n; i++) { if (at[i] 0) { bt[index]--; jtime++; } // If the process is completed if (bt[index] == 0) { ct[index] = jtime; sts[index] = 1; // Set the status to completed counter--; // Decrement the counter since one process is completed } } else //if an index not gets { jtime++; // Increment jtime if no process is available at the current time } } // Main Function int main() { // Reading the number of processes printf("Enter the number of processes: "); scanf("%d", &n); counter = n; // Setting the counter to n // Reading process details from the user for (int i = 0; i < n; i++) { printf("Process %d: ", i + 1); printf("Arrival time: "); scanf("%d", &at[i]); printf("Burst time: "); scanf("%d", &bt[i]); printf("Priority: "); scanf("%d", &pt[i]); sts[i] = 0; // Setting the status of the process to incomplete ct[i] = 0; // Setting the completion time to zero at the beginning } // Printing the given details printf("Given details: "); printf("AT BT PT "); for (int i = 0; i < n; i++) { printf("%d %d %d ", at[i], bt[i], pt[i]); } // Perform process_Ps() function until the counter becomes zero, indicating that all processes are completed while (counter != 0) { process_Ps(); } // Display the results printf(" Results: "); printf("AT BT PT CT "); for (int i = 0; i < n; i++) { printf("%d %d %d %d ", at[i], bt[i], pt[i], ct[i]); } return 0; }

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In priority preemptive scheduling, the process with the lower numerical value for priority is considered to have the higher priority. Thus, a process with priority 4 has a higher priority than a process with priority 5. Example: Process A: Priority 5 Process B: Priority 4 Since Process B has a priority of 4 (which is numerically lower), it has a higher priority than Process A, which has a priority of 5.

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