L-2.8: Pre-emptive Priority Scheduling Algorithm with Example | Operating System

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In pre-emptive priority scheduling algorithm, every time a process with higher priority arrives in the waiting queue, the CPU cycle is shifted to the process with the highest priority. This is pre-emptive because a process that's already being executed can be stopped to execute a process with higher priority.
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If the same example solved by the same method with mode: non-preemptive then it would be more clear and effective to be learned and understood. My suggestion is that add a link where the same question is being solved through this priority algorithm with mode: non-preemptive to differentiate between them clearly. And it would be easy to identify the effectiveness of preemption during the execution. The rest of the question is explained very well and easy to understand. Thank you

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Consider a pre-emptive priority based scheduling algorithm based on dynamically changing priority. Larger priority number implies higher priority. When the process is waiting for CPU in the ready queue (but not yet started execution), its priority changes at a rate a = 2. When it starts running, its priority changes at a rate b = 1. All the processes are assigned priority value 0 when they enter ready queue. Assume that the following processes want to execute: Process Arrival Service ID Time Time P1 0 4 P2 1 1 P3 2 2 P4 3 1 The time quantum q = 1. When two processes want to join ready queue simultaneously, the process which has not executed recently is given priority. The finish time of processes P1, P2, P3 are..Plz make a video solving this question..

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