Gauss discovered this at a very young age (Sum 1 To 100 - Based On True Story)

It's the final play of the 1787 World Math Championships. The talented Gauss faces a challenging question from his math teacher. Will the young student show up his teacher, or does he still have lessons to learn?
I wanted to explain how to sum the numbers from 1 to 100 in a fun and creative way. This dramatization is based on a true story.
*Thanks To My $10+/mo Patreon Supporters*
Kyle
Sports sound effects CC BY 3.0 (creativecommon...)
Modified from SoundBible.com
soundbible.com/... (GoGo)
soundbible.com/... (Mike Koenig)
soundbible.com/... (GoGo)
Some Details About The Story
Gauss sum 1 to 100 stories (the legends)
bit-player.org/...
Normal distribution = Gaussian distribution
en.wikipedia.or...
Euler vs Gauss is an argument
forums.xkcd.com...
Gauss is known as the prince of mathematicians
hsm.stackexchan...
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[@MindYourDecisions]

Thanks for the comments! Some of the lines that didn't end up in the video... "Statistics show Gauss is undefeated in prime years when his score is a prime number. I'm going with the odds that he's going to come through" "He's erasing a lot of his work. That's gonna leave a mark in the morning." "The ruling on the field stands. After you write the numbers, you must establish yourself as a non-mathematician or the proof is considered incomplete."

[@RAJSINGH-of9iy]

MindYourDecisions I don't get it, can you please explain about math proof???

[@brahmandsaraswat867]

Sir, your story is something I could relate to, except the tragic ending.😊

[@kimutaiboit8516]

The puns are amazing 😁

[@super1commenter]

I don't believe QED is necessary in the context of the story where Gauss was performing a derivation, not a proof.

[@gobyg-major2057]

Actually the first part would be a derivation, the generalization would be the proof

[@rogue5580]

😂Oh god, the commentary is cringy!!!

[@theimmux3034]

Why doesn't disliking comments on yt work

[@piyushk.3754]

@@theimmux3034 yaa ,same what I think Dislike button is just for show off or ..

[@WahranRai]

It is normal that Gauss (10 year old ) discover that formula : in french "gosse" mean a child !

[@joeljose182]

Gooose

[@IStMl]

But it's pronounced Ga-oss

[@zombiekiller7101]

Goshsisofhhd

[@kamo7293]

Is it true that when he showed this to his teacher, that thr teacher got angry at him, or something?

[@daimao7392]

KamoGaming From a book I read, the teacher was said to be indifferent to his solution when he walked up and presented it to him.

[@hybmnzz2658]

Lol the teacher was impressed and gave him an arithmetic textbook. How have the rumours gotten so different.

[@MartiniComedian]

This is the funniest Presh video yet! :D

[@salmanel-farsi3744]

Absolutely Hilarious! Great commentary.

[@user-xv3rs2dk2l]

@@Yottifferent tyttyt

[@user-xv3rs2dk2l]

Tssusysis🥳👑❤

[@zombiekiller7101]

This is the easies question anyone can derive this formula easily.why this a great achievement?

[@mrbean23589]

One of the best videos made till date....creative and amazing, loved it from start to end....thanks Presh...

[@Lunch80X]

Yesssss Mate! Great effort, I liked the commentating, controversial final and post game debrief, essentially the whole thing. I couldn't help think of what an effect showing a pregame "get to know Gauss" segment as well would do. Fantastic upload Preshy

[@bennyksmusicalworld]

Math is a sport. A mental sport.

[@lalboimanlun1230]

1:57 thats clever.

[@Arthurcoco33]

Perfect, I got an exercise to in my exercise math sheet which is : proove the sum of the naturals numbers from 1 to n is : n(n+1)/2. I will do this method thanks :)

[@alexpawlikowski7340]

I've always found it simpler to add to 100 (disregarding 50 and 100, for now) with 1 + 99, 2 + 98, etc. until 49 + 51. there we have 49 sets of 100, plus 100, plus 50, for a grand total of 5050

[@joesmith5512]

That may work for u now....but it's not the best....hell it's not even a top of the list way of doing it. Creative though.

[@youtubeuserdan4017]

That sounds messy tbh.

[@fernandopizarrovillagarcia6992]

The problem was only to sum up the whole numbers from 1 to 100 and he did it. He won.

[@rkarthik4u]

2:43 lol

[@yookoala]

Can't believe I haven't watched this before. Please make more of this. Too good to be left behind.

[@Vishal-wx8ql]

Damn the whole process/method was Amazing

[@MasterStroke.]

If Gauss was the prince of mathematics then Ramanujan was God .

[@ull893]

you said it. very true !!!

[@laslo7360]

This video might be good if I could listen to more than a minute of it without wishing I were hearing anything else. I'd prefer chalkboard ASMR.

[@isalisemilise8344]

chalkboard asmr i cann't hahaha

[@meirjab]

This is fantastic! Thanks @MindYourDecisions for uploading this!

[@harryscully6510]

Isn't it the same formula for the triangle numbers?

[@sleepingsaucer3801]

Harry Scully yep. asking for the sum of whole numbers from 1 to N is the same as asking for the Nth triangle number.

[@viniciusdeloi2672]

Harry Scully Yes. And as a challenge for you, can you figure it out the the sum of the first N triangular number?

[@bastav8162]

@@viniciusdeloi2672 did you find it sir?

[@AA-100]

@@viniciusdeloi2672 n(n+1)(n+2)/6

[@FakeMichau]

1 + 2 = 3 + 3 = 6 + 4 = 10, 3 = 10 :P

[@marlenejoe6605]

this guy in maths exam be like 1+1=100

[@abd.137]

Really. I was 200 yrs late. This is my discovery: s=a(a+b)/2b where 'a' is the limit till the sum will add up to and 'b' is the 'skip': e.g. If b=2 then. s=2+4+6+8+10+... If b=3 then. s=3+6+9+12+...

[@aym9869]

According to your notation: a is the last term , b is the first term ;b also is the skip (the change per term) So the right formula should be S=[a/2b][a+b] Excellent , but the first term is not always equal to the skip. In another notation N is the number of terms, a is the 1st term, d is the skip. The general formula is S= [N/2](2a+(N-1)d) = [N/2]*[first term+Last term] You are not late by 200 years, Because In 499 AD "Aryabhata", an indian mathematician-astronomer gave this method . After that it was introduced by some Islamic mathematicians like "Ibn al‐Bannāʾ al‐Marrākushī al-Azdi", (December 1256 - c. 1321).

[@YuvrajSingh-qy9gi]

A 10 year old discovered this? That 10 year old was Carl fuckin gauss.

[@michaeldakin3696]

I confess I hadn’t heard of Gauss before, but I know that proof very well (I think my dad taught it to me when I was about 10)... So, I think the point is made that Gauss’ contribution to mathematics has been incredibly under appreciated... QED.

[@ericmcdowell5762]

When our math teacher in high school asked us the same question, ... I didn't write anything down initially on paper, ... I did it all in my head, ... and realized there were 50 sets of numbers that added up to 101 (I had never heard of Gauss, or his formula), ... so I wrote down 5050 in a very short time. Our math teacher walked over to my desk, smiled and shook his head "yes", as the other students looked on with dismay. After some time, when the others were given more time to figure their "additions", the math teacher had me go before the class, and explain how I came to my conclusion. Like I said, I was totally unaware of Gauss, and his formula/equation.

[@jacknack6819]

Same I also discovered this on my own, but since I didn't know algebra I used words to write my equation. I thought I did something great but a lower grade showed the equation that Gauss made.

[@windxqrts]

Same, I also figured it out without knowing him

[@santinodemaria2818]

First time ever heard him shouting like this

[@hemaroy6439]

Every mathematicians are respqctful as because mathematics is a world where all mathematicians have some contribution.......

[@atharvaverma5013]

The teacher had asked to find the sum of first 100 natural number not to generalize it Hence,he should have had won

[@InvitingShores]

Well done. Like it!

[@dahalankur]

Well done bro!

[@user-cj3mq1gg4s]

1^1+2^2+3^3+4^4.........100^100=?

[@johnchessant3012]

The answer is 201 digits long: 1003711157461764453517012107133619415285\ 4686194907351454201517243723658003463474\ 6971244943788132460150776779198800002366\ 0598719000417847322175390593064838349778\ 65973576751345853385981719448969027641920

[@sayonmondal3454]

I think so it would be = (n(n+1)/2)^2.....just check it out

[@kaisarsihaloho975]

@@sayonmondal3454 ummm its 1^1 + 2^2 + 3^3 + 4^4 and its not 1^2 + 2^2 + 3^2 + 4^2..... so, i think that is wrong....

[@sayonmondal3454]

@@kaisarsihaloho975 oh yes sory, I thought it is 1^2 + 2^2 + 3^2....

[@kaisarsihaloho975]

@@sayonmondal3454 well, its ok, at least you tried... :D

[@rjdind]

Great! I'm looking for how this formula came,but applause for this video,cleared my doubt 🔥🔥🔥

[@nicecubin]

I figured this out intuitively at 11 😢

[@mrembeh1848]

the equation at 0:45 is not an equation!!!

[@bee_irl]

+Embeh 1+2=3+3=6+4=10 is suposed to be 1+2=3 3+3=6 6+4=10 ...

[@mrembeh1848]

yes

[@JohnLee-me3vg]

Well, it is an equation...it's just wrong

[@scmtuk3662]

It's not meant to be read as an equation in the sense that "one plus two is equal to three plus three, and also equal to six plus four, which is also equal to ten". It's supposed to be read as a sentence. "One plus two equals three, plus another three equals 6, plus another 4 equals ten"

[@ProfeARios]

I loved this video. Thank you so much for sharing.

[@sphakamisozondi]

What if Euler and Gauss were rappers dropping math disstracks at eachother.

[@amanrubey]

very funny and nice commentary

[@urabus]

I WAS ABLE TO FIGURE OUT THE FORMULA ON MY OWN LETS GOOOOOOOOO

[@konopong]

Awesome!

[@Josh_Fredman]

This one was a lot of fun to watch! =]

[@ConklinOfficial]

forever remembering this formula because of this masterpiece

[@azsumchovek1116]

Searched for this to see his name so here’s how 2 do it: First u need to see how many numbers are there: (Biggest number - smallest number): the spaces + 1 aka 100 Now u do it (biggest number + smallest number). The number of numbers : 2

[@gerrygunn5109]

Before the start, I would have given Gauss a fifty/fifty chance of winning.

[@edpineda7988]

You must say "quod erat demonstrandum" pronounced as "kwod e-RAT de-de-mon-STRAN-dm" (Say "de" twice in fast succession)

[@9SmartSand6]

Funny, but true, story: I figured this one out for myself at the same age - this really annoyed my math teacher, who tried to convince me I 'had to' do it the long way to 'prove' I was right. I declined, saying I would only do that if she was willing to assert it was wrong.

[@presauced]

That is actually fucked up.

[@laurendoe168]

I prefer to remember this as: The sum of all integers between 0 and n is the average of n and its square. n(n+1) / 2 = 1/2 (n + n^2)

[@hmmnotsure]

What's Q.E.D.?

[@9SmartSand6]

QED is an abbreviation of the Latin words "Quod Erat Demonstrandum" which loosely translated means "that which was to be demonstrated". It is usually placed at the end of a mathematical proof to indicate that the proof is complete.

[@hungryfareasternslav1823]

He wasn't racing!!! He was being punished..

[@bee_irl]

This is what I wrote an A+ exam about yesterday... :D

[@peterbentleyhk]

That's wonderful - great fun ! Many thanks :-)

[@theimmux3034]

Presh's old videos were wild

[@LLorfa]

In a very rare flash of smartness for me, I figured out the answer in a couple minutes (I tried it before clicking on the video). What I did was (let's say S is a sum function) S(5) = 15 and S(4) = 10, I figured there must be some simple relationship, I tried a few like (N-2)*(N+1) which worked for 4 but not 5. Eventually I came to (N+1) * (N/2), and saw that it worked for 3-4-5-6, so I assumed the pattern would continue and did 101*50 to get 5050. The answer made sense to me because I figured it had to be less than 10000 which would be 100^2, and because S(10) was 55 I suspected the answer for S(100) might be around 5k. So surprised and proud I am that I made this dumb comment.

[@chanuthgunawardene7579]

The background noise is cool . and annoying!

[@SledgerFromTDS.]

Awesome

[@grainfrizz]

The booing was a root+4th

[@adityamahesh1179]

is this really so difficult in our country this is in our book the same story also

[@basedboy]

Hello I have a Question: I wanted to know what the sum is from the sequence that starts with 300 and ends with 750, BUT i have to count every fifth integer. Example: 300, 305, 310 ….. 740, 745, 750 I know that i multiply n pairs with the sum of a pair. But how many pairs are in that sequence. I need to know how many millimeters of material i need to order for a hydraulik press. Each number represents a block of steel. The number itself is the height of a block. And we put these blocks inbetween the plates to calibrate the press.

[@MitchBurns]

Clever idea. I have to say though, I learned that proof in like 7th grade. It was pretty cool though. I learned the geometric proof of it though. You make them all boxes with width 1 and push them next to each other. You pretty much get a triangle with sides n and n+1, so yeah.

[@Noper812]

if soccer commentators commentated math problems lol

[@StevenTorrey]

So presumably this formula would work with a random set of numbers: 25 to 176? What is the sum of the numbers 25 through 176?

[@swatitripathi9663]

No Steven, this formula will not work for any random set of numbers. It will only work for consecutive numbers starting from 1 (Natural Numbers). However, the question you have asked that, what is the sum of numbers from 25 to 176, can be answered by using this formula. We'll define this unknown quantity (sum of numbers from 25 to 176) by: x First, we'll find the sum of numbers from 1 to 176 by using the formula discussed in this video [n(n+1)/2] which will be denoted by: S₁₇₆ and from then we'll subtract the sum of numbers from 1 to {[25-1]=24} by using the same formula denoted by: S₂₄. We used 24 because if we use 25 instead, then we'll have to add 25 too. ∴ x = S₁₇₆ - S₂₄ = [176(176+1)/2]-[24(24+1)/2] = [176(177)/2]-[24(25)/2] = 15576 - 300 = 15276 We can generalize this. The sum of consecutive natural numbers from n to k is equals to [k(k+1)/2]-[n(n-1)/2] (or) {[k(k+1)/2]-[n(n+1)/2]}+n

[@StevenTorrey]

@@swatitripathi9663 Thanks. Sorry, I was NOT clear. I think I intended to say "a random set of consecutive numbers"... My bad for being inchoherent. Thnaks for answering and solving the problem.

[@abcdefg9213]

Ibra Gauss isn't the King of maths, he's the God of Maths😂

[@libertyhopeful18]

abcdefg i would argue that the god of maths is euler, gauss can be the king

[@Daddy137]

Then what does that make Isaac?

[@libertyhopeful18]

The holy ghost

[@RAJSINGH-of9iy]

N Ramanujan??

[@asston712]

Einstein?

[@gauravbharwan6377]

Bring more like this

[@joshheaton6627]

He was 7

[@swagbhai1511]

I already know this fact about A.P from science and myths.

[@lets_see_777]

This is what I learned in 8th grade. Its not even a hard question until and unless you have passed 8th

[@aashsyed1277]

8 year old gauss*

[@chinmayeebiswal2195]

The voice is so funny 😂😂

[@gauravbharwan6377]

I liked QED thing

[@oOBeagleOo]

0:49 this is seriously seriously wrong. 1+2=3, 3+3 =/= 1+2 or 6+4 for that matter. All of it is wrong~!!!!

[@scmtuk3662]

Are you seriously that stupid? 1+2=3+3=6+4=10 It's not literally saying that the value of 1+2 = 3+3 and 3+3 = 6+4, you idiot. It's saying that 1+2=3, then +3 = 6, then +4 = 10.

[@lalboimanlun1230]

21Beagle I don't understand how you misunderstood that and post this comment.

[@ricklarsen7477]

I think he was just kidding.

[@peterboth7104]

Rick Larsen, who? Gauss or 21Beagle? 😁

[@jaybycakes4193]

im 9 andd i figuredd this out without the video xD

[@fahrifahri2204]

So the sum of adding the numbers 1 to 1,000,000 is 500,000,500,000

[@david-yt4oo]

Q.E.D. !!!!

[@niveshduppalapudi6616]

it would be fun if i could contact u thought any kinda social media

[@soli3605]

Thanks YT for the algorithm haha

[@jeeaspirant7702]

5050

[@sagarvishwakarma5377]

Iska big formula konsa hai

[@xiaoshen194]

Wo Indian nhi h usko hindi nhi aati

[@sanatkumarpanda9339]

thank you ☺️☺️☺️☺️

[@crisostomodamien]

Pretty sure i figured it out

[@michaelempeigne3519]

I still think the QED is a requirement so the refs were fair. However, for modern times, they are not being as strict.

[@CreativeJE]

this video only helped to understand this thanks

[@zheli2417]

how to make animate like this ? Is it complicated? Thanks in advance

[@tostupidforname]

this is wierd but fun

[@niveshduppalapudi6616]

plz produce some basic calculus videos or books

[@mr.peoples901]

This is a fun one I did it in my head and got the answer faster than you got there I saw that one and 99 = 100 and then just ran up the whole thing until I got the 50 realized it was 50 pairs so 50 pairs of 100 plus 50or 5050.

[@archangecamilien1879]

Haha!!...That's a good one...

[@satyamsarkar5176]

I have a formula too

[@deepaknicedramapleasesenda775]

Who is he?

[@9SmartSand6]

Carl Friedrich Gauss was a German mathematician and physicist who made significant contributions to many fields in mathematics and sciences.

[@sumyiuli7803]

"And OH MY GODDDD!!!!!!!" Umm...Wut?

[@niveshduppalapudi6616]

which will help beginners to start

[@kartikaalst7354]

this is easy as fuck

[@jlee-mp4]

zooombiiee zooombieeeee hehyaayaa in your headddd in your headddddddddddd zombieee zombieeeeee zombieeeeeee eheheheh

[@hacktivist]

The commentary is kinda annoying.

[@dr.abdullah.noman.]

7280D 12:02

[@pabloastoreca8726]

Is there any formula yo sum numbers from a number to other?

[@scmtuk3662]

Yes. The formula for the numbers k to n (k being the first number of course), will be literally the sum of the numbers 1 to n, as usual, but then you'll subtract the sum of the numbers 1 to k. For example the sum of the numbers 20 to 30, will be the sum of the numbers 1 to 30, and then the sum of the numbers 1 to 19 will be subtracted from that answer. The general formula would therefore be (n(n+1)/2)-(k(k-1)/2) You can also write this as (n(n+1)-k(k-1))/2 For example ((30x31)-(20x19))/2=(920-380)/2 = 540/2 = 270

[@stevealexander6425]

I like most of your videos. This one is boring. I'd rather listen to your voice without the "sports" thing. BTW, I learned to solve this when I was in grammar school.

[@MrDamojak]

Steve Alexander cool story bro

[@yohansaldana8218]

What the...

[@wouter11234]

Help

[@niveshduppalapudi6616]

u r god