Third Law of Thermodynamics|| Hindi || Physics class 11 || 3rd law of thermodynamics in hindi

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The third law of thermodynamics states as follows, regarding the properties of closed systems in thermodynamic equilibrium:
The entropy of a system approaches a constant value as its temperature approaches absolute zero.
This constant value cannot depend on any other parameters characterizing the closed system, such as pressure or applied magnetic field. At absolute zero (zero kelvin) the system must be in a state with the minimum possible energy. Entropy is related to the number of accessible microstates, and there is typically one unique state (called the ground state) with minimum energy.[1] In such a case, the entropy at absolute zero will be exactly zero. If the system does not have a well-defined order (if its order is glassy, for example), then there may remain some finite entropy as the system is brought to very low temperatures, either because the system becomes locked into a configuration with non-minimal energy or because the minimum energy state is non-unique. The constant value is called the residual entropy of the system.[2] The entropy is essentially a state-function meaning the inherent value of different atoms, molecules, and other configurations of particles including subatomic or atomic material is defined by entropy, which can be discovered near 0 K. The Nernst-Simon statement of the third law of thermodynamics concerns thermodynamic processes at a fixed, low temperature:
The entropy change associated with any condensed system undergoing a reversible isothermal process approaches zero as the temperature at which it is performed approaches 0 K.
Here a condensed system refers to liquids and solids. A classical formulation by Nernst (actually a consequence of the Third Law) is:
It is impossible for any process, no matter how idealized, to reduce the entropy of a system to its absolute-zero value in a finite number of operations.[3]
There also exists a formulation of the Third Law which approaches the subject by postulating a specific energy behavior:
If the composite of two thermodynamic systems constitutes an isolated system, then any energy exchange in any form between those two systems is bounded.[4]
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@gear.institute
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@kakhetosumi2372
@kakhetosumi2372 Жыл бұрын
kya explaination de diya ree sirji.......10 saal ka doubt 1min mein clear....hats off!!!
@shershaah6917
@shershaah6917 10 ай бұрын
10 sal sa thermodynamic ma ataka tha kya
@ayeshapervaiz2313
@ayeshapervaiz2313 3 жыл бұрын
Thnku sir G.May God bless you...
@vrajdabgar2668
@vrajdabgar2668 3 жыл бұрын
My all doubts are clear thank you sir 👍🏻
@mohsinrehman666
@mohsinrehman666 7 ай бұрын
Very nice.
@akkiraj7093
@akkiraj7093 Жыл бұрын
No one can explain best than u sir
@niranjan9358
@niranjan9358 3 жыл бұрын
Thanks sir ji. thanks a lot
@bikashsahoo2063
@bikashsahoo2063 3 жыл бұрын
sir if supposed we got a perfect crystal.. can we reduce its temperature by keeping it on a vacuum 🤔
@prabhusharma9260
@prabhusharma9260 3 жыл бұрын
Bht vdia explanation aa sir...ajj tkk science boring lgdi c..wtt ajj lgda ki bht intresting aa.. 🙏
@Gaurav-pc7jz
@Gaurav-pc7jz 2 жыл бұрын
I think no
@deepakrajak4569
@deepakrajak4569 Жыл бұрын
Thank u❤❤😊😊
@bishalkumar7100
@bishalkumar7100 3 жыл бұрын
thanks a lot sir...you are great
@sangeetabisht7635
@sangeetabisht7635 3 жыл бұрын
Good evening sir best explained ,:)
@gear.institute
@gear.institute 3 жыл бұрын
Glad to help you For all my videos links click here gearinstitute.in/youtube-videos/ For MCQ or mock test click here gearinstitute.in/
@Saif-zj6yc
@Saif-zj6yc Жыл бұрын
Very nice sir ,you are a genius sir and you make us understand very clearly and very easily sir Thank you very much sir
@kundannarayansahu7171
@kundannarayansahu7171 3 жыл бұрын
Bhut Achchah sir aapka class
@AnjaliKumari-qr9rh
@AnjaliKumari-qr9rh 3 жыл бұрын
Thank you sir 🙏
@mannuarya7699
@mannuarya7699 4 жыл бұрын
Nice explanation.. helpful video 👌🙏🙏🙏
@itsmyjourney4315
@itsmyjourney4315 3 жыл бұрын
Sir 1 doubt sir.. Jb 0K tk temperature gya hi ni to third law ka Statment kaise prove hua sir?
@MINAKSHI-d9b
@MINAKSHI-d9b 2 ай бұрын
Same question
@SaritaSingh-qz7it
@SaritaSingh-qz7it 7 ай бұрын
Thankyou so much for your precious explanation
@gear.institute
@gear.institute 7 ай бұрын
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@Anshumanyadv0007
@Anshumanyadv0007 5 ай бұрын
Thanks ❤❤❤
@gear.institute
@gear.institute 5 ай бұрын
For more videos Download our app now edumartin.page.link/jLFr
@pksharma5442
@pksharma5442 4 жыл бұрын
Awesome sir
@vinodmore9514
@vinodmore9514 3 жыл бұрын
Nice explaination sir
@amanyadavkanpur
@amanyadavkanpur 3 жыл бұрын
perfectly explain sir its helpful
@subhasmrutipanda7916
@subhasmrutipanda7916 2 жыл бұрын
Thank you so much Sir🙏
@mohdqalednaibtahsildar1213
@mohdqalednaibtahsildar1213 2 жыл бұрын
Supper explaination
@girirajkashyap2912
@girirajkashyap2912 3 жыл бұрын
Gjab sir 😊 gud for neet👌
@dhyeygadhiya1649
@dhyeygadhiya1649 Жыл бұрын
Wow super nice 👍
@onlyracing263
@onlyracing263 2 жыл бұрын
Well explained sir ji 🙏
@biswajitsahu2473
@biswajitsahu2473 4 ай бұрын
Superb 🎉
@gear.institute
@gear.institute 4 ай бұрын
Thank You For more videos Download app edumartin.page.link/jLFr
@allrounderstudy1683
@allrounderstudy1683 2 жыл бұрын
Yes sir aa gya
@shrutidawalkar1435
@shrutidawalkar1435 Жыл бұрын
Your a tooooo goooooooood Teacher 😎😎
@therefinerylife2958
@therefinerylife2958 4 жыл бұрын
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@gear.institute
@gear.institute 4 жыл бұрын
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@AyazKhan-iy3cy
@AyazKhan-iy3cy 4 жыл бұрын
Sir very fantastic ❤❤
@chemicalengineeringadda1755
@chemicalengineeringadda1755 2 жыл бұрын
Sir aapka samjhane ka method osm hai....
@gear.institute
@gear.institute 2 жыл бұрын
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@shwelpajadhav5905
@shwelpajadhav5905 Жыл бұрын
You are just superb
@gear.institute
@gear.institute Жыл бұрын
For more videos Download my app📥 edumartin.page.link/jLFr
@rkstudies2158
@rkstudies2158 3 жыл бұрын
Apne achchhe se explain kiya
@viral889
@viral889 2 ай бұрын
everything is possible infact 0 kelvin srif hum ne apni smjh ki aik limit lagai hai abhi hum ne bhot kuch discover hi nahi kiya 0 kelvin bhi achive hoga in future aur jisy aj tum 0 kelvin samjh rahe ho wo baad m pata chalega k us zero k billions parts bhi kiye ja sakte hain
@RANJEETBOSS150
@RANJEETBOSS150 3 жыл бұрын
Very nice sir ji
@sherazikhan3628
@sherazikhan3628 Жыл бұрын
Lub u sir 👍✅💯💯
@somnathbhand7258
@somnathbhand7258 Жыл бұрын
Sir nano kalvin kya hota hai ???
@anuragmishra.22
@anuragmishra.22 3 жыл бұрын
Very nice class 👌👌
@snehpalsingh1281
@snehpalsingh1281 3 жыл бұрын
Thanks
@PratimaDevi-qw2nt
@PratimaDevi-qw2nt 4 ай бұрын
Ok sir thanks sir
@gear.institute
@gear.institute 4 ай бұрын
Welcome For more videos download app edumartin.page.link/jLFr
@rekhasingh9920
@rekhasingh9920 4 жыл бұрын
Nice sir
@mainhunadon
@mainhunadon Жыл бұрын
Nano Kelvin kya or kitna h?
@gear.institute
@gear.institute Жыл бұрын
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@SagarKumar-xu2fo
@SagarKumar-xu2fo 3 жыл бұрын
🙏🏻🙏🏻🥳
@rushikeshbharde9751
@rushikeshbharde9751 4 жыл бұрын
👍👌
@BTS_ARMY1234
@BTS_ARMY1234 8 ай бұрын
Im in class 8
@jokerboss605
@jokerboss605 3 жыл бұрын
🤔🤗😱😱😱
@JoKeRGaMiNg-il1tl
@JoKeRGaMiNg-il1tl Жыл бұрын
Bawal padhate ho sir
@gear.institute
@gear.institute Жыл бұрын
Thermodynamics Full Syllabus bit.ly/3k7lXws
@Jagu-dada-555
@Jagu-dada-555 Жыл бұрын
@lokeshKumar-lu4de
@lokeshKumar-lu4de 3 жыл бұрын
Thank you sir 🙏
@pushkarkumar2185
@pushkarkumar2185 3 жыл бұрын
Good explaination
@gear.institute
@gear.institute 3 жыл бұрын
Glad to help you For all my videos links click here gearinstitute.in/youtube-videos/ For MCQ or mock test click here gearinstitute.in/
@somnathmaity9471
@somnathmaity9471 3 жыл бұрын
Thank you sir 🙏🙏😇
@davemaharshi5226
@davemaharshi5226 2 жыл бұрын
Thankyou so much sir
@nainasingh330
@nainasingh330 2 жыл бұрын
Thank you sir ☺️
@humanity_50
@humanity_50 3 жыл бұрын
Thanks sir 👍👍
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