General Aptitude | Series Formation | Life Science/Chemistry /Physics/Maths / CSIR NET 2012

[@rupambanerjee9014]

Ans B) 1 done via telescopic method/Vn method

[@bikashdutta2585]

Very good explanation of sir

[@RanjangamingYT7477]

B sir

[@tikamrathore5393]

Thanks sir ji

[@ssbcchemist2874]

Thankfully sir

[@vishikachauhan9079]

Option A....Ans is 1

[@ManishYadav-eo1dg]

Thank u sirji

[@Amirkhan-ds8mn]

👍

[@shalu4839]

Thanku sir

[@priyamkborah9669]

Option B - 1

[@Abhay0505]

In the 2nd sum it's wayy too easy, every consecutive pair has difference 6

[@DAIZY-dr3rd]

Ans-B

[@ardraan2526]

Answer is option B

[@maths_mentor24]

Ans:-B

[@lovisharora7604]

Ans)B

[@ap7799]

Option-B

[@mansikesherwani299]

Ans-(b)

[@shalu4839]

Ans-b

[@surbhimidha2035]

Option (b)

[@justnaturethings_7]

Option B

[@aliazhar9905]

Sir jee its answer is 1

[@manishkumar-ys6uf]

Ans(b)

[@manubansal5216]

Ans B

[@pankajdhaka6150]

B

[@shabirparray17]

Option b

[@ManishYadav-eo1dg]

Answer is option b

[@pranavpanjabi]

Kaise aayega option (B) please explain

[@ankitnaharia3933]

@@pranavpanjabi 1/infinite kya hota h 0 hota h

[@pabitrakumarsahoo6099]

B.1

[@JYOTIsharma-lg9gs]

D

[@sandipgarai5790]

1.b

[@krishnamehta8150]

1.) 1

[@biswajitbarik1077]

Is the answer is d??? Infinity

[@rupambanerjee9014]

No the answer is 1

[@niteshkumardugga62]

And is 1

[@pabitrakumarsahoo6099]

1

[@amritadhara748]

q.1) d

[@himanshu1717]

ans B

[@ranajitjyoti5533]

option B

[@ASHOKKUMAR-nj8ry]

1

[@ABHIMANYUSINGH-ll7jb]

B

[@sanjanamodi3992]

D

[@pratiksingh09]

Option B

[@modulusclasses6674]

B

[@amanchourasiya7014]

1

[@cut143]

Option B

[@shreshthavishwakarma1129]

B

[@akashkusumghosal8020]

Option B

[@dippravasvlog4965]

B

[@zebabanu5820]

B

[@dipikaroy3832]

B